The P Block Elements

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New answer posted•a year ago
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a year ago

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The following reaction takes place in the test tube

 

  1. i) When Aluminium is treated with dilute hydrochloric acid.

Al + HCl  -à AlCl3

ii) When Aluminium is treated with dilute sodium hydroxide solution.

Al  +  NaOH -

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New answer posted•a year ago
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a year ago

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BCl3+3H2O→B (OH)3+3HCl

B (OH)3+2H2O→ [B (OH)4]−+H3O+

 B (OH)3  due to its incomplete octet accepts an electron pair (OH)-  to give has configucation [B (OH)4]−.

Boron in this ion involves one 2s orbital and three 2p or

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New answer posted•a year ago
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When a trivalent atom is added to the crystal of SiO2, it substitutes silicon atoms which result in generation of holes. These holes make the crystal conductor of electricity. The overall Crystal is electrically neutral and is cal

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New answer posted•a year ago
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As compared to carbon, silicon is bigger in size and is less electronegative. It shows resistance in forming p−p multiple bonding which is easily done by carbon. Thus, SiO2 is a 3−D network where each silicon is linked covalently

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New answer posted•a year ago
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As we move down the group in group 13 and 14 the participation of s-electrons in bond formation decreases the primary reason behind this is the inert pair effect.

In this the p-electrons take part in bond formation and more energy

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New answer posted•a year ago
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(A) Carbon has small size and large electronegativity, it forms strong n−pπ bonding with two oxygen atoms forming a separate CO2 molecule.

 

While in SiO2 silicon is larger in size with comparatively less electronegativity tha

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New answer posted•a year ago
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(A) sarbon in CCl4 does not have a vacant d-orbital to accommodate the electrons from OH of water molecules. Also CCl4 is nonpolar covalent compounds whereas H2O is polar. So, no strong interaction occurs between them. Hence CCl4

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New answer posted•a year ago
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a year ago

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Both BCl3 and AlCl3 are electron deficient compounds that are central atom boron and aluminium have incomplete Octet. In each compound, a metal atom is surrounded by six electrons of three covalent bonds with 3 chlorine atoms.

Each

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a year ago

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H3BO3

Boric acid forms a hexagon and rings through hydrogen bonding and has a layer-like structure.

Boric acid is present in water as [B (OH)4]−.H3BO3 electron from the OH of water and forms the complex BOH for negative for sp3 and

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New answer posted•a year ago
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a year ago

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H3BO3 or B (OH)3 is an electron deficient compound or Lewis acid which easily accepts electron from OH of water and releases its proton hence it is a Monobasic acid.

Reaction:

B (OH)3 + 2H2O → [B (OH)4]− + H3O+

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