Understand JEE Normalization Process
Compiled by Madiha Jawed | shiksha.com
The normalized Board marks weightage is only for deciding JEE (Main) ranking which will be used for admission to all Centrally Funded Technical Institutions (CFTIs), NITs, and IIITs; but excluding IITs.
According to the recent information released by the CBSE, the JEE Interface Group (JIG) has decided that 50% of Boards marks be normalized by equating percentile amongst different boards/examining bodies and anchoring them to All India JEE-Main percentiles, and 50% be normalized by equating each Board’s/examining Body’s percentile with JEE(Main) percentile marks of respective Boards /examining bodies.
Accordingly, the detailed procedure for normalization of Board marks will be as follows:-
- Note down the aggregate marks (A0) obtained by each student in JEE- Main.
- Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main.
- Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1.
- Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this as B2.
In order to calculate normalized board marks, one needs to know marks of all the students in that Board, marks of all the students of that Board in JEE (Main), as well as marks of all the students of all the Boards in JEE (Main).
The normalized board score of the candidate will be computed as:
- Bfinal = 0.5 * (B1 + B2)
For the purpose of admission to CFTIs (Centrally Funded Technical Institutes) where it has been decided to use the JEE Mains performance and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit list will be computed as:
- C = 0.6 * AO + 0.4 * Bfinal,
Five subjects to be used for normalization are:
1. Language
2. Mathematics
3. Physics
4. Any one of the subjects: Chemistry, Biology, Biotechnology, Computer Science
5. Any Elective or Language (No subject should be repeated in the subject combination).
For any query, students can write to: jeemainnormalisation2013@gmail.com
| What is Normalization |
Normalisation as used in the Indian context is a process for ensuring that students are neither advantaged nor disadvantaged by the difficulty of exams that they do for the Boards. This process is used in other countries with similar issues as in India. |
| Normalisation Process requires us to know the following |
Percentile score of a Candidate in a Board or JEE (Main) will reflect what Percentage of Candidates have scored below that candidate in that Board or JEE (Main) Examination. A Percentile score is the value of below which a certain Percent of observations fall. For example, the 20th Percentile is the value (or score) below which 20 Percent of the observations may be found. |
| Formula for calculating the percentile of a candidate |
100 x Number of students in the group with aggregate marks less than the candidate (divided by) Total number of candidates in the group
|
| Example |
Suppose we have , 13711 Candidates in a Board ABCD and a Candidate who has scored 60% of Board marks has 6865 Candidates below him; his Percentile score will be calculated as follows:
Percentile score for 60% of board marks = 6865 x 100 13711 Percentile = 50.07 |
For details, visit:
http://jeemain.nic.in/jeemain2013/pdf/Normalisation_Formula_v8_2013.pdf
Also check out JEE Advanced 2013 Exam analysis & solutions
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2013-06-30 22:06:35
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2013-06-18 12:50:22