

M.Tech. in Computer Science and Engineering
- Public/Government Institute
- Estd. 1946
M.Tech. in Computer Science and Engineering at JNTUACEA Overview
JNTUA College of Engineering, Ananthapuramu offers a 2 years M.Tech. in Computer Science and Engineering at the PG level. Candidates need to fulfil the both eligibility and selection criteria to get admission in the course. The institution accepts the scores of GATE exam for admission to the course. The total tuition fee for M.Tech. in Computer Science and Engineering is INR 60,000. Check below more details on JNTUA College of Engineering, Ananthapuramu M.Tech. in Computer Science and Engineering:
Total Tuition Fees | ₹60,000 Get Fees details |
Duration | 2 years |
Course Level | PG Degree |
Mode of Course | Full Time |
Official Website | Go to Website |
Seat breakup | 32 |
Type of University | Public/Government,Autonomous |
M.Tech. in Computer Science and Engineering at JNTUACEA Fees
Students taking admissions in the JNTUA College of Engineering, Ananthapuramu M.Tech. in Computer Science and Engineering course must pay the fee consisting of components, namely One-Time Fees, Registration Fees, Exam Fees, and others. There are some additional charges to be paid by students (if applicable). These charges are specific to the institution. The total tuition fees to be paid by students for M.Tech. in Computer Science and Engineering at JNTUA College of Engineering, Ananthapuramu is INR 60,000. More details around JNTUA College of Engineering, Ananthapuramu M.Tech. in Computer Science and Engineering fees breakup is as follows:
| Fee components | Amount (2 years) |
|---|---|
The above fees is calculated basis first year. Actual fee may vary.
The mentioned fees is as per Andhra Pradesh State Council for Higher Education. | ₹ 60,000 |
₹ 60,000 |
M.Tech. in Computer Science and Engineering at JNTUACEA Students Ratings & Reviews
- 3-41
M.Tech. in Computer Science and Engineering at JNTUACEA Frequently Asked Questions
JNTUA cutoff 2024 has been released for the Last Round. As per the JNTUA cutoff 2024 released for the BTech courses, the required rank should ranged between . Considering the Last Round cutoff, the required rank needed would be varied from 6855 to 136972 for getting admission at JNTUA.
Further, check out the courses available under this range for the General AI candidates as per the JNTUA Last Round cutoff 2024:
| Course | 2024 |
|---|---|
| B.Tech. in Civil Engineering | 43852 |
| B.Tech. in Electrical and Electronics Engineering | 16442.1 |
| B.Tech. in Mechanical Engineering | 33700 |
| B.Tech. in Electronics and Communication Engineering | 6855 |
| B.Tech. in Chemical Engineering | 66065 |
| B.Tech. in Computer Science and Engineering | 136972 |
| Courses | Eligibility |
|---|---|
| B.E. / B.Tech | Candidate must have passed diploma in engineering/technology or 3 years B.Sc degree with Mathematics as one of the subjects And secured at least 45% marks (40% marks reserved category) from a recognized university. |
| MCA | Candidate must have passed bachelor degree of 3/4 years duration with Mathematics as one of the subject at Intermediate or Degree level with above mentioned marks from any recognised University/Institute. 45% marks for BC categories. Candidate who are appearing for the final year degree examination are also be eligible. Degree obtained by Distance Mode Program should have recognition by Joint Committee of UGC, AICTE and DEC/DEB. Candidate who passed all the subjects of the three years of any Degree course in one sitting is not eligible for admission. |
| MBA/PGDM | Candidate must have completed bachelor degree of 3/4 years duration with above mentioned marks from any recognised University/Institute. 45% marks for BC categories. Candidate who are appearing for the final year degree examination are also be eligible. Degree obtained by Distance Mode Program should have recognition by Joint Committee of UGC, AICTE and DEC/DEB. Candidate who passed all the subjects of the three years of any Degree course in one sitting is not eligible for admission. |
| M.E./M.Tech | Candidate must have passsed B.E./B.Tech. in relevant stream and obtained at least 50% marks (45% in case of reserved category candidates) from an AICTE/UGC approved institution recognised by the Government of Andhra Pradesh as equivalent thereto. Final year appearing students may also apply on provisional basis. |
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M.Tech. in Computer Science and Engineering at JNTUACEA Placements
| Particulars | Statistics (2024) |
|---|---|
| Highest Salary | INR 7.20 Lakh |
| Median Salary | INR 4.20 Lakh |
M.Tech. in Computer Science and Engineering at JNTUACEA Entry Requirements
M.Tech. in Computer Science and Engineering at JNTUACEA Admission Process
- CounsellingAdmission is through counseling based on the rank obtained in Andhra Pradesh Post Graduate Engineering Common Entrance Test (APPGECET). Remaining seats will be filled on the basis of score obtained in GATE.
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