

M.Tech. in Computer Science
- Public/Government Institute
- Estd. 1946
M.Tech. in Computer Science at JNTUACEA Overview
A 2 years M.Tech. in Computer Science course is offered at PG level by JNTUA College of Engineering, Ananthapuramu. The tuition fee of M.Tech. in Computer Science is INR 60,000 for the entire course duration. The JNTUA College of Engineering, Ananthapuramu M.E./M.Tech have a seat intake of 25 students. Students can get admission related information regarding JNTUA College of Engineering, Ananthapuramu M.Tech. in Computer Science on this page. In addition, JNTUA College of Engineering, Ananthapuramu courses have industry-oriented syllabus for better placement opportunities. Check out the various JNTUA College of Engineering, Ananthapuramu M.E./M.Tech courses.
Total Tuition Fees | ₹60,000 Get Fees details |
Duration | 2 years |
Course Level | PG Degree |
Mode of Course | Full Time |
Official Website | Go to Website |
Seat breakup | 25 |
Type of University | Public/Government,Autonomous |
M.Tech. in Computer Science at JNTUACEA Fees
The tuition fee for M.Tech. in Computer Science is INR 60,000, which candidates can pay as per the frequency set by the institution. Check out the different JNTUA College of Engineering, Ananthapuramu M.Tech. in Computer Science fee elements below:
Fee components | Amount (2 years) |
---|---|
Tuition fee is calculated on the basis of 1st year. Actual amount may vary.
The fees might include components other than tuition fees.
Mentioned fees is as per Andhra Pradesh State Council for Higher Tuition fee is calculated on the basis of 1st year. Actual amount may vary.
The fees might include components other than tuition fees.
Mentioned fees is as per Andhra Pradesh State Council for Higher Education, AP PGECET. | ₹ 60,000 |
₹ 60,000 |
M.Tech. in Computer Science at JNTUACEA Students Ratings & Reviews
- 4-51
M.Tech. in Computer Science at JNTUACEA Frequently Asked Questions

JNTUA cutoff 2024 has been released for the Last Round. As per the JNTUA cutoff 2024 released for the BTech courses, the required rank should ranged between . Considering the Last Round cutoff, the required rank needed would be varied from 6855 to 136972 for getting admission at JNTUA.
Further, check out the courses available under this range for the General AI candidates as per the JNTUA Last Round cutoff 2024:
Course | 2024 |
---|---|
B.Tech. in Civil Engineering | 43852 |
B.Tech. in Electrical and Electronics Engineering | 16442.1 |
B.Tech. in Mechanical Engineering | 33700 |
B.Tech. in Electronics and Communication Engineering | 6855 |
B.Tech. in Chemical Engineering | 66065 |
B.Tech. in Computer Science and Engineering | 136972 |



Courses | Eligibility |
---|---|
B.E. / B.Tech | Candidate must have passed diploma in engineering/technology or 3 years B.Sc degree with Mathematics as one of the subjects And secured at least 45% marks (40% marks reserved category) from a recognized university. |
MCA | Candidate must have passed bachelor degree of 3/4 years duration with Mathematics as one of the subject at Intermediate or Degree level with above mentioned marks from any recognised University/Institute. 45% marks for BC categories. Candidate who are appearing for the final year degree examination are also be eligible. Degree obtained by Distance Mode Program should have recognition by Joint Committee of UGC, AICTE and DEC/DEB. Candidate who passed all the subjects of the three years of any Degree course in one sitting is not eligible for admission. |
MBA/PGDM | Candidate must have completed bachelor degree of 3/4 years duration with above mentioned marks from any recognised University/Institute. 45% marks for BC categories. Candidate who are appearing for the final year degree examination are also be eligible. Degree obtained by Distance Mode Program should have recognition by Joint Committee of UGC, AICTE and DEC/DEB. Candidate who passed all the subjects of the three years of any Degree course in one sitting is not eligible for admission. |
M.E./M.Tech | Candidate must have passsed B.E./B.Tech. in relevant stream and obtained at least 50% marks (45% in case of reserved category candidates) from an AICTE/UGC approved institution recognised by the Government of Andhra Pradesh as equivalent thereto. Final year appearing students may also apply on provisional basis. |
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M.Tech. in Computer Science at JNTUACEA Placements
Particulars | Statistics (2024) |
---|---|
Median Salary | INR 4.20 Lakh |
M.Tech. in Computer Science at JNTUACEA Entry Requirements
M.Tech. in Computer Science at JNTUACEA Admission Process
- CounsellingAdmission is through counseling based on the rank obtained in Andhra Pradesh Post Graduate Engineering Common Entrance Test (APPGECET). Remaining seats will be filled on the basis of score obtained in GATE.
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To check the merit list for JNTUA, candidates can follow the steps given below:
- Head on to Andhra Pradesh EAMCET official website "sche.ap.gov.in/EAPCET" for the Andhra Pradesh EAMCET Merit List 2024.
- Click on “AP EAMCET Rank Card.”
- The pop up screen will appear where candidates need to disclose their details like date of birth, hall ticket number, and Andhra Pradesh EAMCET registration number 2024.
- And then they need to select "View merit list 2024" to view the Andhra Pradesh EAMCET merit list.
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