Alternating Current Class 12 Formulas

Alternating Current Class 12 Formulas

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nitesh
nitesh singh
Senior Executive
Updated on Oct 27, 2025 14:49 IST

AC is one of the most important chapters for the Board and competitive exams. Find the Alternating Current Formulas for quick revision and numerical practice of the chapter.

Class 12 Physics Alternating Current includes very important concepts such as AC voltage, Power in AC Circuit, Impedance, and many other concepts. Learn all the important formulas of the Class 12 AC chapter 7.

Practice numerical problems and revise effectively using our Class 12 Chapter 7 formulas provided by Shiksha. We also provide NCERT Notes and the solution of the NCERT exercise.

Table of content
  • Alternating Current Basic Formulas
  • AC Voltage Applied to a Resistor
  • AC Voltage Applied to a Capacitor
  • AC Voltage Applied to an Inductor
  • LCR Circuit

Alternating Current Basic Formulas

  • AC Voltage:

( t ) = V max sin ( ω t ) v(t) = V_{\text{max}} \sin(\omega t)

  • Peak Value of AC: 

i ( t ) = v ( t ) R = V max R sin ( ω t ) i(t) = \frac{v(t)}{R} = \frac{V_{\text{max}}}{R} \sin(\omega t)

  • Average Value of AC: 

I avg = 2 I max π V_{\text{avg}} = \frac{2 V_{\text{max}}}{\pi}, \quad I_{\text{avg}} = \frac{2 I_{\text{max}}}{\pi}

  • RMS Value of AC:


I rms = I max 2
V_{\text{rms}} = \frac{V_{\text{max}}}{\sqrt{2}}, \quad I_{\text{rms}} = \frac{I_{\text{max}}}{\sqrt{2}}

AC Voltage Applied to a Resistor

  • Kirchhoff’s Loop Rule for an AC circuit with a Resistor


V max sin ( ω t ) -i(t)R = 0

  • Current in the AC Circuit with a Resistor

i ( t ) = V max R sin ( ω t ) i(t) = \frac{V_{\text{max}}}{R} \sin(\omega t)

  • Amplitude (Peak Value) of Current

I max = V max R I_{\text{max}} = \frac{V_{\text{max}}}{R}

  • Instantaneous Power in a Resistive Circuit

p ( t ) =
V max I max sin 2 ( ω t )
p(t) = v(t) \cdot i(t) = V_{\text{max}} I_{\text{max}} \sin^2(\omega t)

  • Phase Difference Between V and Ir

It means both will reach the respective peak values at the same time.

Φ = 0 \phi = 0^\circ

AC Voltage Applied to a Capacitor

  • Kirchhoff’s Loop Rule for an AC circuit with a Capacitor

v m sin ( ω t ) = q C

  • Current in the AC Circuit with a Capacitor

i ( t ) = C V max ω cos ( ω t ) i(t) = C \cdot V_{\text{max}} \omega \cos(\omega t)

  • Amplitude (Peak Value) of Current

I max = V max ω C I_{\text{max}} = V_{\text{max}} \cdot \omega C

  • Capacitive Reactance

X C = 1 ω C X_C = \frac{1}{\omega C}

  • Instantaneous Power in a Capacitive Circuit

p ( t ) = V max I max sin 2 ( ω t )

  • Average Power in a Capacitive Circuit

In a full cycle, energy is stored in the first cycle and the same energy is returned in the next half cycle. So

P avg = 0

  • Phase Difference Between V and Ic

Current lags behind the voltage by 90° in a capacitive circuit:

ϕ = 90

AC Voltage Applied to an Inductor

  • Kirchhoff’s Loop Rule for an AC circuit with an Inductor

v L = L d i d t

  • Current in the AC Circuit with An Inductor

i ( t ) = V m ω L cos ( ω t )

  • Amplitude (Peak Value) of Current

I m = V m ω L

 

X L = ω L

  • Instantaneous Power in Circuit

p ( t ) = V m I m 2 cos ( 2 ω t 90 )

  • Average Power in Circuit

For a full cycle, the average power is zero.

P avg = 0

  • Phase Difference Between V and IL

The current phase is ahead of the voltage phase.

ϕ = + 90

Relatable Study Material for Chapter 7
Class 12 Alternating Current NCERT Solutions
Class 12 Physics Chapter 7 NCERT Notes
Alternating Current Quick Revision Notes
Class 12 Physics Chapter 7 NCERT Exemplar Solutions

LCR Circuit

  • Current in LCR Circuit

I m = V m Z

  • Impedance

Z = R 2 + ( X L X C ) 2 Z = \sqrt{R^2 + (X_L - X_C)^2}

  • If there is no resistance

Z = ( X L X C ) 2

  • If there is no Inductive Reactance

Z = R 2 +
( X C ) 2

  • If there is no capacitive reactance

Z = R 2 + ( X L
) 2

  • If inductive and capacitive reactance are equal, It behaves like a circuit with a resistor only. It is called resonance.

( X L X C ) = 0 (X_L - X_C) = 0

  • Resonant Frequency

Since X L = X C ω 0 = 1 L C X_L = X_C \quad \Rightarrow \quad \omega_0 = \frac{1}{\sqrt{LC}}

  • Phase Angle

tan ϕ = X L X C R

  • Quality Factor 

Q = ω 0 L R = 1 ω 0 C R

About the Author
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nitesh singh
Senior Executive
Nitesh Singh, a science graduate and content creator, specializes in developing engaging Physics, Chemistry, and Mathematics resources for the K-12 segment. He crafts precise and pedagogically sound Q&As, comprehens Read Full Bio