# JEE Main Marks vs Percentile vs Rank 2024: Calculate Percentile and Rank Using Marks

Joint Entrance Exam (JEE) Main 2024 ( JEE Main )

Updated on Jun 27, 2024 18:02 IST

Check your JEE Main 2024 marks vs percentile and marks vs rank in the JEE Mains exam. In this article, you'll learn to check the JEE Main marks vs rank 2024 formulas to analyze the rank based on scores obtained in the JEE Main 2024 exam. Candidates can calculate their JEE Main 2024 percentile score using the formula used by NTA. JEE Mains percentile can also be used to know the expected rank before the JEE Main result 2024 is announced.

JEE Mains Marks vs Percentile vs Ranks 2024: Students often have doubts related to marks vs percentile in JEE Mains. The National Testing Agency (NTA) has released the JEE Main 2024 results as percentile scores. The JEE Main percentile scores are not the actual marks but the normalized marks of candidates. Normalization is done to remove any possible parity in the difficulty level of the JEE Main 2024 question paper as the exam is held in several shifts and days. Candidates can check the formula for JEE Main Marks vs Percentile below. Also, the comparative analysis of marks vs rank JEE Mains can be seen on this page.
NTA has clearly explained the normalization process for calculating the JEE Main percentile score. The raw marks obtained in JEE Main 2024 by any candidate are converted to a percentile score for preparing the result. Candidates are provided here with a detailed analysis of marks vs percentile in JEE Main to help estimate their most probable marks easily. Candidates are also provided here JEE Main marks vs percentile vs rank to help them get an idea about their rank in the exam. It is to note here that the jee mains marks vs percentile vs rank is just to calculate the probable rank in the exam. The actual percentile and rank are mentioned in JEE Main 2024 result.

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## What is NTA Score in JEE Mains?

NTA score in JEE Mains is the aggregate percentile score of all three subjects. Candidates having query what is NTA score are informed that NTA score is same as aggregate percentile score. Candidates can check below NTA score meaning and qualifying marks for JEE Mains 2024. Read more below to know how to calculate percentile in JEE and NTA score vs Percentile.

Q:   What is JEE Main cutoff for IIITs?

A:
The cutoff for IIITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC/ST candidates. Candidates can check the JEE Main 2022 cutoff below for some top IIITs and branches. For detailed cutoff report, candidates can check Shiksha page. IIIT Allahabad IT Closing Rank Open Category: 5704 IIIT Allahabad ECE Closing Rank Open Category: 9700.

Q:   Is 75 percent marks in class 12 required for JEE Mains?

A:

Candidates need not have 75 percent marks in class 12 for appearing in JEE Main. As per the official brochure released by the NTA there is no minimum percentage required for appearing in the JEE Main. The requirement of 75 percent marks need not be associated with JEE Main. It is to be understood that 75 percent marks is required for admission to institutes which include NITs, IIITs, GFTIs and IITs. There are many institutes which offer admission on 60% and even less along with JEE Main. Candidates must clearly understand that the requirement of 75 percent marks in class 12 is only for taking admission in the institutes.

Q:   Can I take admission in any institute if I do not get JEE Main cutoff marks?

A:
Candidates who do score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
 JEE Main 2024 Result JEE Main 2024 Cutoff JEE Main 2024 Answer Key JEE Main Previous Year Question Paper PDF

Use your JEE Main 2024 Percentile and predict your Rank and the Colleges you are eligible for using Shiksha's JEE Main Rank and College Predictor. Get cut-off information for 600 colleges and 2500 colleges

Predict JEE Main Colleges

## NTA JEE Mains 2024 Cutoff

Category

Cutoff

Unreserved (UR)

100.0000000 to 93.2362181

OBC-NCL

93.2312696 to 79.6757881

SC

93.2312696 to 60.0923182

ST

93.2312696 to 46.6975840

UR-PwD

93.2041331 to 0.0018700

## Why JEE Main Result is announced in Percentile?

The JEE Main 2024 exam was conducted in two sessions in January and April over 5 days with 2 shifts each day. There's a possibility that the question paper for a particular day can be more difficult or easier than any other day. To overcome this possible parity in difficulty level, normalization is done. The normalized marks are not the actual marks obtained by the candidate but a comparative score obtained using a specially developed formula by NTA. The range of JEE Mains marks vs percentile is given below based on the previous years' trends and the normalization formula used by NTA. The article below will provide important details to candidates about JEE Main marks vs percentile.

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## What is JEE Main 2024 Percentile Score?

The JEE percentile score compares an applicant's performance to all other test takers and is not the same as a percentage score or raw marks. The JEE Main percentile score indicates the percentage of candidates who scored lower or equal to a particular score in the examination. Knowing how to access an estimated rank before the official announcement can be beneficial, but only if the applicant understands the normalization process and tiebreakers used to determine JEE Main marks and percentiles.

## JEE Main 2024 Marks vs Percentile: A Comparative Study

In addition to understanding their percentile score, students should also be aware of their assigned rank about that score. To fully comprehend the relationship between JEE Main marks and percentiles, it is also important for students to understand how rank is assigned based on percentile.

Q:   How to calculate percentile in JEE?

A:

NTA uses a formula to calculate NTA score in JEE Main. The formula used is

Q:   Which category has the lowest cutoff in JEE Mains 2023 exam?

A:
As per the JEE Main 2023 cutoff data released by the NTA PwD category has the lowest cutoff of 0.0013527. The highest cutoff is for general category which is 90.7788642. The PwD candidates scoring above 0.0013527 NTA score are eligible to appear in JEE Advanced for admission to IITs. The PwD cutoff has been lowered in 2023 to 0.0013527 which was 0.0031029 in the year 2022.

Q:   What is CRL in JEE Main Cutoff?

A:
CRL stands for the Common Rank List. NTA releases the cutoff in several categories one of which is CRL. Basically, CRL means unreserved category. Candidates belonging to unreserved category need to have JEE Main cutoff equal to or more than the CRL cutoff. The other categories for which cutoff is released are Gen-EWS, Open-PwD, OBC-NCL, SC and ST.

Q:   What are the types of JEE Main cutoff?

A:
JEE Main cutoff is of two types, one is qualifying cutoff for JEE Advanced and the other is admission cutoff for the institutes. JEE Main qualifying cutoff is released by the NTA along with the result and is in the form of percentile scores. NTA releases JEE Main cutoff for a total of six categories which include unreserved (CRL), Gen-EWS, Open-PwD, OBC-NCL, SC and ST. JEE Main admission cutoff is released by the Joint Seat Allocation Authority JoSAA and is in the form of All India Rank.

Q:   What is JEE Main cutoff for NITs?

A:
The cutoff for NITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC, ST candidates. Candidates can check the JEE Main 2022 cutoff below for some top NITs and branches. For detailed cutoff report, candidates can check Shiksha page. MNNIT Allahabad CSE Closing Rank Open Category: 5627 (Home State) MNNIT Allahabad CSE Closing Rank Open Category: 4254 (Open) MNIT Jaipur CSE Closing Rank Open Category: 5610 (Home State) MNIT Jaipur CSE Closing Rank Open Category: 4631 (Open). .

The marks vs percentile for JEE Mains 2024 is available. Candidates can refer to the table below for marks vs percentile in JEE Mains 2024 to get an idea of their approximate percentile range in JEE Main result.

JEE Main 2024 Score JEE Main 2024 Percentile
300-281 100 - 99.99989145
271 - 280 99.994681 - 99.997394
263 - 270 99.990990 - 99.994029
250 - 262 99.977205 - 99.988819
241 - 250 99.960163 - 99.975034
231 - 240 99.934980 - 99.956364
221 - 230 99.901113 - 99.928901
211 - 220 99.851616 - 99.893732
201 - 210 99.795063 - 99.845212
191 - 200 99.710831 - 99.782472
181 - 190 99.597399 - 99.688579
171 - 180 99.456939 - 99.573193
161 - 170 99.272084 - 99.431214
151 - 160 99.028614 - 99.239737
141 - 150 98.732389 - 98.990296
131 - 140 98.317414 - 98.666935
121 - 130 97.811260 - 98.254132
111 - 120 97.142937 - 97.685672
101 - 110 96.204550 - 96.978272
91 - 100 94.998594 - 96.064850
81 - 90 93.471231 - 94.749479
71 - 80 91.072128 - 93.152971
61 - 70 87.512225 - 90.702200
51 - 60 82.016062 - 86.907944
41 - 50 73.287808 - 80.982153
31 - 40 58.151490 - 71.302052
21 - 30 37.694529 - 56.569310
20 - 11 13.495849 - 33.229128
0 - 10 0.8435177 - 9.6954066

## JEE Main 2024 Percentile vs Ranks

The release of percentile and rank statistics is dependent on various factors such as the number of registered candidates, the number of questions on the exam, the difficulty level of the exam, and trends from previous years' marks and ranks in JEE Main.

The percentile vs rank statistics for JEE Main 2024 is provided here. Candidates can check here percentile vs rank data. Candidates can refer to the table below for the same:

JEE Main 2024 Percentile JEE Main 2024 Rank
100 - 99.99989145 1 - 20
99.994681 - 99.997394 80 - 24
99.990990 - 99.994029 83 - 55
99.977205 - 99.988819 210 - 85
99.960163 - 99.975034 367 - 215
99.934980 - 99.956364 599 - 375
99.901113 - 99.928901 911 - 610
99.851616 - 99.893732 1367 - 920
99.795063 - 99.845212 1888 - 1375
99.710831 - 99.782472 2664 - 1900
99.597399 - 99.688579 3710 - 2700
99.456939 - 99.573193 5003- 3800
99.272084 - 99.431214 6706 - 5100
99.028614 - 99.239737 8949 - 6800
98.732389 - 98.990296 11678 - 9000
98.317414 - 98.666935 15501 - 11800
97.811260 - 98.254132 20164 - 15700
97.142937 - 97.685672 26321 - 20500
96.204550 - 96.978272 34966 - 26500
94.998594 - 96.064850 46076 - 35000
93.471231 - 94.749479 60147 - 46500
91.072128 - 93.152971 82249 - 61000
87.512225 - 90.702200 115045 - 83000
82.016062 - 86.907944 165679 - 117000
73.287808 - 80.982153 246089 - 166000
58.151490 - 71.302052 385534 - 264383
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## JEE Main Normalisation Formula

After compiling the raw marks, the NTA applies the normalization formula to get the percentile scores of a candidate for each subject – Maths, Physics, and Chemistry as well as the total. The highest score of each session will get the same percentile of 100 which is ideal. The percentile score has been used to prepare the JEE Main merit list. The percentile scores will be calculated up to 7 decimal places to avoid ties among candidates with the same scores.

The JEE Main percentile score obtained by a candidate is determined only after applying normalization to the marks obtained by a candidate. JEE Main Percentile scores indicate the percentage of candidates who have scored equal to or below that particular percentile in the examination. A percentile score is measured on a scale of 100 to 0 for each session of examinees. The formula to calculate JEE Mains marks vs percentile is

## JEE Main 2024 Normalisation Process: Tie Breaker Guidelines

The following rule comes into effect when two or more candidates obtain equal percentile scores. The inter-se merit will be determined according to the following rules in case of a tie.

Candidates obtaining a higher Percentile Score in Mathematics will be ranked higher

• If a tie still exists, the candidate with a higher Percentile Score in Physics will be given a higher rank
• If a tie still exists, the candidate obtaining a higher Percentile Score in Chemistry will get a higher rank
• If a tie still exists, candidates older in age will be given a preference

The JEE Main result is released separately for each session. The best scores of the two sessions are considered for candidates who appeared in both sessions. The merit list is prepared on the final scores and ranks are announced based on the same.

How to calculate JEE Main 2024 Percentile Score - Know Normalization Process

How to Calculate JEE Main 2024 Rank From Percentile

## JEE Main Marks vs Percentile vs Rank 2024 FAQs

Q. When will JEE Main 2024 Result be declared?

A. The JEE Main 2024 session 2 results has been announced. Candidates can check the result from the official website jeemain.nta.ac.in by login to the website using their application number and date of birth. JEE Main 2024 result session 1 was announced on February 12.

Q. I got 281 marks in JEE Main. What will be my Percentile?

A. . It is 99.96 percentile, it's a really good performance and you should be able to get under AIR 100. Any score above 250 in JEE Main is considered a good score. To score well in JEE Main, candidates must have a good understanding of Class 11 and Class 12 Physics, Chemistry and Mathematics.

Q. If someone gets 23.072 percentile, what will be the score in JEE Main?

A. Around 15-20 marks out of 300.

Q. How much percentile is required for NIT?

A. General Category candidates need to score a minimum of 95 percentile score to get NITs. For reserved category candidates, an 80 percentile score is enough to get NITs.

Q. What is a good score in JEE Main?

A. 250 marks in JEE Main can be considered as a good score. The candidates scoring  above 250 will get a percentile between 85 -95. A high score in JEE Main is required to get admission in NITs and to appear for JEE Advanced. The top scores in JEE Advanced are given admission in IITs.

Q. What is needed to score good marks in JEE Main?

A. To score good marks in JEE Main exam it is very important for candidates to have a good under-standing of Physics, Chemistry, and Mathematics. The basics should be strong. The questions are mostly asked from Class 11 and Class 12 curriculum. The candidates must understand the concept behind every topic to use the right formula to solve the questions in JEE Main 2024.

Q. How JEE Main rank is prepared?

A. JEE Main rank is prepared by compositing the scores of JEE Main and marks of class XII in the ratio of 60:40. According to it, the scores are arranged in merit.

Q. My CBSE percentage is 75.5. Am I eligible for JEE Main 2024?

A. Yes, you are eligible to appear for JEE Main.

Q. Is 45 percentile enough for JEE Mains?

A. Candidates can appear in JEE Main irrespective of their percentage in class 12. The requirement of percentage is for admission in the institute not for appearing in JEE Mains.

Q. If I appear in all the sessions. Which scores will be counted while declaring the result?

A. The best of the scores from all the sessions will be considered for merit/ranking in JEE Main 2024.

Satyendra is an expert news writer and content editor at shiksha.com with over ten years of experience in the education field. His work involves writing news and articles, editing, and proofreading content related t... Read Full Bio

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### Student Forum

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Write here...

Based on the search results, here is the answer:

With an 85 percentile in JEE Mains 2024 and being in the OBC category, you have a good chance of getting admission to some NITs and GFTIs (Government Funded Technical Institutes), but it may be challenging to secure a seat in the top NITs for popular b

...more

D

Deepa

Contributor-Level 6

With a 69 percentile in JEE Main and a rank of 456991, you may have limited options for counseling. At this percentile range, securing a seat at the NITs could be challenging, even for SC candidates. However, some less popular branches at lower-ranked NITs may still be available, depending on your a

...more

D

Deepa

Contributor-Level 6

The previous year category cutoff rank in NIT Surat was 19361 in Civil engineering. While the AIR rank was 353269.  So chances of getting NIT Surat are very less.

Similarly chances of getting IIIT Vadodara are also very less.

Scholar-Level 18

JEE Main is an important exam that the students must prepare before hand if they are aspiring to choose Engineering. Similarly for admission to I2IT Pune, JEE Mains scores are important. Another accepted entrance exam is MHT CET. If students could not qualify JEE Main then worry not, admissions are

...more

L

Liyansha Jain

Contributor-Level 10

No, candidates need not pay any fees for making corrections in JEE Main application form. However, if any candidate changes his/her category from SC/ST/OBC-NCL/PWD to underserved category, they need to pay the difference in application fees. For making any other changes, candidates don't have to pay

...more

S

Satyendra Singh

Contributor-Level 10

Candidates can face difficulty in payment of application fees due to various reasons like

• Slow internet connectivity while paying the fees
• Slow bank server
• Insufficient balance in bank

In case any candiate faces issues while trying to pay JEE Main application fees, they should try paying the fees after

...more

S

Satyendra Singh

Contributor-Level 10

Candidates can pay JEE Main application fees using any one of the following method

• Credit/debit card of any nationalised bank
• Internet banking
• UPI
• Paytm

Before paying the application fee, candidates should check whether there is requisite balance in the Bank Account / Wallet/Debit/credit card. In case an

...more

S

Satyendra Singh

Contributor-Level 10

No, JEE Main application form can only be filled online. The application form of JEE Main is released only in online mode on the website jeemain.nta.ac.in. There is no option of filling the application form in offline mode. Candidates who do not have a laptop/personal computer can visit the computer

...more

S

Satyendra Singh

Contributor-Level 10