Biomolecules

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New answer posted

8 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Sucrose is the disaccharides which is a non-reducing sugar, but if forms glycosidic linkage between C1 of a - glucose and C2 of b-fructose. Hence Assertion is correct, but Reason is incorrect.

New answer posted

8 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Biuret test is given by proteins and dipeptide & compounds having following groups

Hence positive test given by tripeptide & biuret.

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

? 0.30 gm glycine is present in 100 gm protein

? 75 gm glycine is present in 1 0 0 0 . 3 0 * 7 5 = 1 0 0 0 0 3 0 * 7 5 = 2 5 * 1 0 3 g / m o l

New answer posted

8 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Zymase naturally occurs in yeast.

Diastase is found in malt.

Urease is found in soyabean.

Pepsin is found in stomach.

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

During denature of protein, 1° structure remains the same, whereas 2° and 3° structure get destroyed.

New answer posted

8 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Amylose is the water soluble compound.

New answer posted

8 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

->Correct pyranose structure.

-> -OH group in left is up and –OH group in right is below.

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Ala – Gly – Leu-Ala- Val

Two amino acid units are connected by peptide linkage. So number of peptide linkage = 4.

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

C e l l u l o s e H + / H 2 O β D G l u c o s e W a t e r B r 2 G l u c o n i c a c i d

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