Computer Science and Engineering
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New answer posted
2 years ago
Contributor-Level 10
The cutoff ranks 2023 for BTech (Hons) in Computer Science and Engineering at NIT Jamshedpur - National Institute of Technology other than the General category are - 11202 for OBC, 48731 for SC, 675 for ST, and 10593 for EWS. While the admissions are based on the scores/rank obtained in JEE exam, the last cut-offs also change a lot depending on the All India quota or Home State. It also varies if the applicant is a female.
New answer posted
2 years ago
Contributor-Level 10
For 2023, the cut-off was 9809for General category candidates in the All India quota for BTech (Hons) in Computer Science and Engineering at NIT Jamshedpur. For female candidates in the general category under All India quota, 16038 was the closing rank. BTech cut-off varies depending on the category and domicile/quota of the applicant.
New answer posted
2 years agoContributor-Level 9
The cutoff trend for B.Tech at IIT Mandi - Indian Institute of Technology has been decreasing in the recent years. In 2021, the closing rank for B.Tech. under general category for all India quota was 3041. In 2022, it decreased to 3017. Likewise, the cut off ranks have changed from 1228 to 1212 for OBC, 732 to 636 for SC, 361 to 310 for ST, 436 to 462 for EWS. This trend is likely to continue in the coming years, as the demand for engineering education in India continues to grow. Similar cut off trend can be seen for female candidates under all categories however the ranks are slightly different.
New answer posted
2 years agoContributor-Level 9
Opening and Closing rank depends on the category and quota of candidates. For general category under All India, opening rank was 2773 and closing rank was 3017. Cut off are different when it comes to other categories or female candidates and even domicile of home state. In All India, opening and closing rank for female candidates was 5608 and 5988. Admission to BTech in Computer Science and Engineering at IIT Mandi - Indian Institute of Technology is based on the scores obtained in the entrance exam JEE. Applicants are advised to confirm what category are they applying while checking for cut offs.
New question posted
2 years agoNew answer posted
2 years agoBeginner-Level 5
The minimum marks requiered for B.Sc. in Computer Science at Thakur College Of Science is 45% in 12th exams, with Science or commerce background, commerce student needed subject is IT & MATHS either Maths for commerce students, to get B.Sc. in Computer Science at Thakur College Of Science.
New answer posted
2 years agoBeginner-Level 5
A Bachelor of Science in computing and technology degree is a four year 8 semester engineering programme at the Symbiosis International University, Pune. The department is aiming to provide students with quality education by means of specialist programmes, traineeships, seminars, apprenticeships, value add courses as well as projects in areas such as computer Science and information technology where they are exposed to industry problems and application development.
New answer posted
2 years ago
Scholar-Level 18
Hello Riya Singh, your JEE Mains ranking at about 1.1 Lacs is quite good. I am sure that you are bound to get one of the branches of engineering that you are desiring. Unfortunately you have not mentioned your percentile. However, I am sure you must be aware of your percentile. NTA has announced cutoffs in percentile for different categories of students. As EWS category student, cutoff is at 63.1114141. You can appear for JoSSA counselling only if you have scored more than this percentile. It's all right. To help you, I am attaching a link that will take you to the college predictor developed by Shiksha for JEE Mains examination. You j
New answer posted
2 years ago
Contributor-Level 10
Your chances of getting a free seat for computer Science engineering through the TS counseling are slim. The cutoff rank for CSE in the open category for the 2022-23 academic year was 23,000. For the BC-E category, the cutoff rank was 35,000.
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