Engineering Entrance Exam

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New answer posted•8 years ago
Ritik Agiwal
8 years ago
Hello,
I hope you are doing well. You can check the list of colleges including NITs and IIITs you can get according to your marks and rank here. Use Shiksha JEE College Predictorhttps://www.shiksha.com/b-tech/resources/jee-mains-college-predictor?utm_source=cconnect&utm_medium=CR_JEECP&utm_campaign=

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New answer posted•8 years ago
SAMARTH AGARWAL
8 years ago
For getting Government college such as IIT, IIIT, NIT or any other government funded college, then you must qualify for JEE main in order to get the admission in B.Tech programme. You can also appear for state level exam by which you can get admission into state level government college not national

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New answer posted•8 years ago
SAMARTH AGARWAL
8 years ago
You have qualified but the margin between the cutoff and gain marks is just 5 (if you are of general category).
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor
You can use the above link for predicting the college. But I suggest you to qualify one entrance exam either national lev

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New answer posted•8 years ago
D
8 years ago
Yes, we have 240 intake in mechanical engineering looking into number of seat and overall merit of JEE. It may be possible to get admission at Dr. D. Y. Patil Institute of Technology, Pimpri, Pune.

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New answer posted•8 years ago
sawan kumar
8 years ago
Some of the colleges have their personal admission test exam like BITSAT. Also, in some of the colleges, you can get admission on the basis of your JEE Mains marks or your class 12th mark.

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New answer posted•8 years ago
A
8 years ago
One should fall within 120 to attain admission in SMS, CUSAT.

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4 Comments
New answer posted•8 years ago
Ashutosh Tamrakar
8 years ago
You have to score above 160 marks to get admission in DAVV, Indore. Try JEE college predictor to get more information and insight about college & branch which you can get on the basis of your rank:-
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor?utm_source=connect&utm_medium=CR_

...Read more

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New answer posted•8 years ago
New answer posted•8 years ago
New answer posted•8 years ago