Engineering Entrance Exam
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My rank in JEE Main Paper 2 B.Arch is 28,016 but my 12th class percentage is 60%. How do I apply?
l got 70.2% in CBSE board exams in 2025. Can l appear for JEE Mains 2026?
I want to know about the JEE. I am a 10th pass out. Can you help me with the same?
I got 6056 rank in AEEE and home state quota. What is the possibility of getting ECE?
Yea. You can easily get the ECE with your rank in the upcoming round. As a rank with 6056 is already very close and the Amrita CBE have always a slight range distance for ECE every year.
How many rounds of JEE Main Counselling 2025 are expected to be conducted?
The admission to BTech and BTech courses has been started through JEE Main. Additionally, the institute has released the Round 1 seat allotment result wherein B.Tech. in Computer Science and Engineering (Internet of Things, Cyber Security including Block Chain Technology) closing rank stood at 47166
Recently, NIELIT Patna cutoff 2025 for the Round 1 seat allotment has been released by the institute for the admission to BTech and BTech Integrated courses. As per the JEE Main 2025 cut off data, the B.Tech. in Computer Science and Engineering rank stood at 50162 for the General AI category candida
Can I have a different name in my Aadhar card and 12th marksheet and might it create any issue while appearing in JEE Mains exam?
A particle is dropped from a height H. The de-Broglie wavelength of the particle as a function of height is proportional to (a) H (b) H1/2 (c) H0 (d) H-1/2
A particle is dropped from a height H. The de-Broglie wavelength of the particle as a function of height is proportional to (a) H (b) H1/2 (c) H0 (d) H-1/2
Explanation- velocity of a freely falling body is v=
And
-1
Consider a 20 W bulb emitting light of wavelength 5000 Å and shining on a metal surface kept at a distance 2 m. Assume that the metal surface has work function of 2 eV and that each atom on the metal surface can be treated as a circular disk of radius 1.5 Å.
(i) Estimate number of photons emitted by the bulb per second. [Assume no other losses]
(ii) Will there be photoelectric emission?
(iii) How much time would be required by the atomic disk to receive energy equal to work function (2 eV)?
(iv) How many photons would atomic disk receive within time duration calculated in (iii) above?
(v) Can you explain how photoelectric effect was observed instantaneously?
Consider a 20 W bulb emitting light of wavelength 5000 Å and shining on a metal surface kept at a distance 2 m. Assume that the metal surface has work function of 2 eV and that each atom on the metal surface can be treated as a circular disk of radius 1.5 Å.
(i) Estimate number of photons emitted by the bulb per second. [Assume no other losses]
(ii) Will there be photoelectric emission?
(iii) How much time would be required by the atomic disk to receive energy equal to work function (2 eV)?
(iv) How many photons would atomic disk receive within time duration calculated in (iii) above?
(v) Can you explain how photoelectric effect was observed instantaneously?
Explanation-number of photon emitted per second n=
(ii) E=hc = this enegy is greater than 2 so emission is possible
(iii) work function = =
= =
(iv) N=
= =2
(v) as the time of emission is 11.04s so
A particle A with a mass mA is moving with a velocity v and hits a particle B (mass mB) at rest (one dimensional motion). Find the change in the de-Broglie wavelength of the particle A. Treat the collision as elastic.
A particle A with a mass mA is moving with a velocity v and hits a particle B (mass mB) at rest (one dimensional motion). Find the change in the de-Broglie wavelength of the particle A. Treat the collision as elastic.
Explanation- according to law of conservation of momentum
S0 mAv+mb0=mAv1+mBv2
So mA(v-v1)= mBv2
according to law of conservation of kinetic energy
1/2mAv2=1/2mAv12+1/2mBv22
So mA(v2-v12)= mBv22
From above eqn we can say that v+v1=v2 or v=v2-v1
So v1= v and v2= v