Engineering Entrance Exam
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New answer posted
2 years agoContributor-Level 9
It is never a given that an IIT's JEE Advanced question paper will follow the same format or have the same degree of difficulty. One of the most often-asked questions about the JEE Advanced exam is also a myth. The pattern and design of the question paper are independent of the IIT being conducted.
New answer posted
2 years agoContributor-Level 9
No, admission to the BE programmes is based on merit in the Birla Institute of Technology and Science Admission Test (BITSAT) only. BITS Pilani Hyderabad does not accept any other entrance test scores.you cannot take admission to BITS Hyderabad with a JEE Main score. BITS Hyderabad only accepts their own entrance test marks for admissions, and merit-based selection is done through the BITSAT examination. BITS Pilani does not take into account the JEE Mains score for its admission process. Instead, admission to BITS Pilani is solely determined by the BITSAT score. The syllabus for JEE Main and BITSAT are quite similar, so focusing
New answer posted
2 years agoContributor-Level 9
The second session for JEE Main 2024 took place for the BE/BTech paper on April 4, 5, 6, 8 and 9 in two shifts of 9:00 am to 12:00 pm and 3:00 pm to 6:00 pm. On April 12, the BArch/Bplan paper was held in a single shift from 9 am to 12 am.
New answer posted
2 years agoContributor-Level 6
SASTRA University takes the cutoff for admission in B.TECH as follows-
If a student secures a JEE Main Score of 185 and normalized +2 total marks of 95%, the combined score of the student will be (0.25*185)+(0.75*95) = 117.50. They ask applicants to submit the JEE scores in the application form even if they are not qualified for the Advanced or they don't have the cut-off prescribed by MHRD. SASTRA does not use the CBSE cut-off for its admission but its own ranks calculated based on +2 marks and JEE (Main) scores.
As you have 90% in board exam you can easily get ECE branch at SASTRA University, Kumbakonam campus. But you should try
New answer posted
2 years agoContributor-Level 10
To get into VIT, Vellore campus for B.Tech CSE, your rank should be under 6000. It means you need to score more than 81 to fall under 6000 rank. The counselling for VITEEE is going on.
The fee for CSE is INR 7.8 Lakh. A total of 1080 seats are available for this course.
I hope it will help.
New answer posted
2 years agoContributor-Level 10
No, you cannot get admission to CSE branch with this rank. You can get admission to ECE, ME, and Civil Engineering easily.
According to previous years:
- VIT Vellore: CSE closing rank was around 1,000 in 2023
- VIT Chennai: CSE closing rank was around 2,500 in 2023
- VIT Bhopal: CSE closing rank was around 5,000 in 2023
- VIT Amaravati: CSE closing rank was around 7,000 in 2023
I hope it will help.
New answer posted
2 years agoContributor-Level 10
With a rank of 28623 in VITEEE you get following branch:
- B.Tech. in Mechanical Engineering at VIT Chennai
- B.Tech. in Civil Engineering at VIT Chennai
- B.Tech. in Electronics and Computer Engineering at VIT Chennai
- B.Tech. in Fashion Technology at VIT Chennai
- B.Tech. in Civil Engineering at VIT Vellore
I hope it will help.
New answer posted
2 years agoContributor-Level 10
With this rank you only few options. Below is the list:
- B.Tech. in Civil Engineering at VIT Vellore
- B.Tech. in Fashion Technology at VIT Chennai
I hope it will help.
New answer posted
2 years agoContributor-Level 10
You are only eligible for TNEA if you have completed your Class VIII to Class XII in Tamil Nadu or If you are Native Tamil Nadu and have passed any of the VIII, IX, X, XI and XII outside Tamil Nadu.
In all these cases you need to show your domicile or related documents.
To apply, you can simply fill out the application form.
I hope it will help.
New answer posted
2 years agoContributor-Level 10
With 16658 rank in VITEEE, it is highly unlikely to get admission to B.Tech CSE Branch for VIT Vellore.
As per the available data, the rank cutoff for Computer Science Engineering (CSE) at VIT Vellore is around 7500.
I hope it will help.
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