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New answer posted
2 months agoContributor-Level 8
To get admitted to a B.Tech program based on CUET (Common University Entrance Test), candidates generally need to have passed their 10+2 (or equivalent) with Physics, Chemistry, and Mathematics as core subjects, with a minimum aggregate score (often around 50% or 60%, but this can vary by institution). Additionally, they must appear for the relevant CUET exam and secure a score that meets the cutoff of the specific university or college.
New answer posted
2 months agoContributor-Level 8
With a 90 percentile in JEE Mains, you have a good chance of getting into GGSIPU (Guru Gobind Singh Indraprastha University), especially if you are a Delhi resident and looking for courses other than Computer Science or Information Technology. GGSIPU accepts JEE Main scores for its engineering programs. However, the specific cutoff for your desired branch and college within GGSIPU will depend on the competition and the number of seats available in that particular session.
New answer posted
2 months agoContributor-Level 8
The fees structure of B.Tech 2025 CSE course is lies between 12 lack to 20 lack which is depend on your college if you are not eligible for any type of counselling then you can take admission in private colleges through management couta in this situation the fee structure of your B.Tech course is increased
New answer posted
2 months agoContributor-Level 8
The cutoff of B.Tech food technology at agricultural College and research association is not directly provided in 2024
Here are some criteria for taking admission in B.Tech food technology
To get admission in B.Tech food technology, you need to have a minimum of 50% marks in class 12th
New answer posted
2 months agoContributor-Level 9
With a 72.3175743 percentile in the SC category, you may be eligible for colleges like:
- Delhi University colleges (Sri Aurobindo, Zakir Husain, Lakshmibai, Shyama Prasad Mukherji)
- SAGE University Indore
- Arya Group of Colleges Jaipur
- JK Lakshmipat University Jaipur
- The ICFAI University Jaipur
Check official websites for cut-offs and fees.
New answer posted
2 months agoContributor-Level 8
A score of 166 in JEE Mains Session 2 would likely translate to a percentile between 98.04+ and 98.14+, based on various analyses and predictions. The exact percentile may vary slightly depending on the difficulty level of the specific paper you took compared to the overall JEE Mains exam.
General estimate:
A score of 166 generally falls within the range of 98.04 to 98.14 percentile.
Difficulty level:
If your specific paper was considered on the easier side, your percentile might be closer to the lower end of that range. If your paper was considered more challenging, your percentile could be closer to the higher end
New question posted
2 months agoNew answer posted
2 months agoContributor-Level 9
With 47 marks in SC category, check NTA's official cutoff marks to confirm qualification (cutoff range: 45-65 marks). Compare your score and proceed accordingly – either to counseling or prep for the next attempt.
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