Engineering

The cut off for B.Tech courses in TNAU is calculated by adding the marks of Maths Physics and Chemistry (100 for Maths 50 each for Physics and Chemistry and dividing the sum by 2. For example, if you scored 91 in Maths 84 in Physics 89 in Chemistry and 95 in Biology your cut off would be (91/2) + (84/2) + (89/2) + (95/2) = 179.5. I hope that helps! Let me know if you have any other questions.

The validity of the Assam CEE 2023 result is one year. If the candidates apply for admission after a year of qualifying the entrance examination, then they will be considered ineligible and disqualified from the process. Therefore, the candidates are required to apply for the counselling and admission process on the same year that they qualified the entrance examination. If the candidates are not able to attend the counselling process, then they will have to apply and re-attempt Assam CEE next year for a new score and rank.

With 75 percentile in JEE Mains, you might not be able to get an NIT or IIIT, but you might get following colleges with CSE: Annasaheb Dange College of Engineering and Technology, Ashta, Sangli Birbhum Institute Of Engineering & Technology Hooghly Engineering & Technology College. I hope this helps! Let me know if you have any other questions.

The tie-breaking guidelines have been created for cases when there are two or more candidates who have secured the same score in Assam CEE 2023. Then, the PCM aggregate of 12th standard will be considered for shortlisting the candidates. If a tie still persists, then, the overall aggregate in Physics Chemistry Mathematics and English will be used. If the tie still exists, then the committee will select the candidates on different terms. Candidates are advised to be informed about the tie-breaking guidelines to understand how ranks are allotted if more than one person secure the same rank.

With 93 percentile in JEE Mains, it is not possible to get NITs or IITs for CSE branch because the cutoff for CSE branch goes very high, something 95 percentile above. I hope this helps! Let me know if you have any other questions.

TS EAMCET qualifying marks for OC 2023 is 25%, I. e. the candidates must score a minimum of 40 out of 160 in the TS EAMCET examination to qualify. The TS EAMCET 2023 entrance examination offers admission to professional courses such as B.E. / B.Tech B.Pharma Pharma. D B.F.Sc. BVSC B.Sc. Nursing and others.

Yes, you can get admission in B.Tech CSE and other branches as well without any entrance examination as there are colleges which offer admission based on class 12th marks. Sri Sivasubramaniya Nadar College of Engineering, Kalavakkam is one such college that offers admission in B.Tech on the basis of 12th marks. I hope this helps! Let me know if you have any other questions.