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New answer posted•a year ago
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Answered by
a year ago
IIT Roorkee JEE Advanced cutoff 2026 ranged from 582 to 8735 for the General AI category. Hence, General AI category students need a rank of at least 8735 to be considered eligible for admission. Check the list below to know the highest rank needed by other categories.
| Category | IIT Roorkee JEE Advanced cutoff 2026 |
|---|---|
| General | 8735 |
| OBC | 3789 |
| SC | 2409 |
| ST | 1279 |
| EWS | 1450 |
| PWD | 126 |
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