JEE Advanced Cut-off

IIT Kharagpur cutoff 2026 is out for admission for round 1 for admission to the BTech, BArch, BS and BSc courses. The round 1 cutoff ranged from 509 to 13366, wherein BTech CSE and B.Sc. in Applied Geology were the most and least competitve UG courses for admission. 

Students can see the table below to know the first round cutoff ranks for all the available courses for the General AI category, sorted from most to least competitive. 

Students need to obtain a competitive rank in JEE Main and JEE Advanced so that they can become eligible for admission procedures at IIT Bhubaneswar. Candidates are required to achieve a cut-off rank, as decided by the course. For instance, the cut-off rank needed for BTech Civil Engineering was 14,782, whereas for Computer Science and Engineering (CSE) it was approximately 3,685. Interested candidates can refer to the table below for information on cutoffs from previous years.

JEE Advanced Cutoff 2025 for BTech course ranged from 126 to 5733 for students in the General AI category, so therefore a student should attain a rank of 5733 or preferably lower to increase their chances of admission to IIT Delhi. Please note that BTech cutoff 2025 will vary according to different rounds, courses, specialisations and categories. Students can refer to the table provided below to view the IIIT Delhi JEE Advanced cutoff 2025 for the last round in the General category.

If you want to know about the latest cutoff information for JEE Advanced Cut-off then go through the JEE website. But for general it is typically 85 out of 300.

If you just want to grab a seat in IIT Patna then your OBC rank has to be in 2800-3200 OBC NCL rank while General rank would be around 12000. If you want to get top branches like CSE, ECE, then you will have to be in Top 500 of your category rank.

Yes, it is possible to get a seat at IIT Ropar with a rank of 10,000 in JEE Advanced. For candidates belonging to the General All India category, the last round cutoff ranks were between 2379 and 13009. Although at 10,000 rank, the choice of specialisation would be limited, candidate can get admission to the college. A few specialisations available at this rank would be B.Tech. in Civil Engineering,  B.Tech. in Chemical Engineering and B.Tech. in Metallurgical and Materials Engineering. 

IIT Roorkee offers BTech specialisations on the basis of JEE Advanced scores. The cutoff depends on a few factors such as category and gender. However, to get an overall idea of the cutoff trend at the institute, candidates can check the table below. The table consists of the branch-wise last round closing ranks for General AI category candidates:

IIT Hyderabad released its first round of cutoff list for admission to the B.Tech. in Artificial Intelligence for various All India Quota categories. For the General AI category, the IIT Hyderabad Artificial Intelligence cutoff 2026 was 906. 

Among all categories, PWD AI had the toughest competition for this branch. Students can refer to the table below to know the IIT Hyderabad JEE Advanced cutoff 2026 for other categories. 

You should target a rank between 282 and 874 if you want admission to the CSE and Electrical branch in the first round. The IIT Hyderabad JEE Advanced cutoff 2026 was released for the first round, wherein CSE had the closing rank of 282. B.Tech. in Electrical Engineering had the closing rank of 874.

Please note that other categories, round, etc, will have different cutoffs.

The maximum rank needed by the General AI category students was 3994 in the first round as per the IIT Dhanbad CSE cutoff 2026. Hence, students with this rank could get admission. 

The IIT Dhanbad JEE Advanced cutoff 2026 was released for the first round for admission to the BTech course and its various specialisations. The cutoff was out for different AI quota categories. Check the list below to know the maximum rank for other categories. 

• OBC: 1292
• SC: 780
• ST: 306
• EWS: 536
• PWD: 148