JEE Main
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a year agoContributor-Level 10
To check the JEE Mains session 2 answer key for the year 2025, visit the official website of National Testing Agency NTA that is jeemain.nta.nic.in, browse the homepage and click JEE Mains section, login with your credentials like Application no and Password, you can download the answer key by clicking download anyway option. Answer key provides an idea about your marks before the normalisation process. Additionally, the results for JEE MAINS Session 2 2025 were released on April 17th 2025.
New answer posted
a year agoContributor-Level 10
As you possess a 92.26 percentile in JEE Main and your category is EWS, your EWS category rank will probably be within a scale of 8,000-9,000. The table below shows last year Round closing ranks of SVNIT Surat especially by Computer Science and Engineering (CSE) EWS quota, where the Other State (OS) quota closing ranks were 1000-1500 and Home State (HS) quota killing ranks were 1000-2500.Although 92.26 percentile is good there is a possibility of facing difficulties in gaining a CSE seat at SVNIT Surat because EWS ranks as a percentage opens are very high as far as CSE is concerned. Your chances could be in other NITs or branches, or i
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a year agoContributor-Level 9
Branch and category matter here. You might score a seat in Civil or Mechanical Engineering at some NITs or find a fit in less competitive branches like Biotechnology. Don't forget to leverage home state quota or explore less popular NITs - they might just be your ticket in!
New answer posted
a year agoContributor-Level 9
With a 72.3175743 percentile in the SC category, you may be eligible for colleges like:
- Delhi University colleges (Sri Aurobindo, Zakir Husain, Lakshmibai, Shyama Prasad Mukherji)
- SAGE University Indore
- Arya Group of Colleges Jaipur
- JK Lakshmipat University Jaipur
- The ICFAI University Jaipur
Check official websites for cut-offs and fees.
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a year agoContributor-Level 8
A score of 166 in JEE Mains Session 2 would likely translate to a percentile between 98.04+ and 98.14+, based on various analyses and predictions. The exact percentile may vary slightly depending on the difficulty level of the specific paper you took compared to the overall JEE Mains exam.
General estimate:
A score of 166 generally falls within the range of 98.04 to 98.14 percentile.
Difficulty level:
If your specific paper was considered on the easier side, your percentile might be closer to the lower end of that range. If your paper was considered more challenging, your percentile could be closer to the higher end
New answer posted
a year agoContributor-Level 9
To predict your JEE Mains rank, use a rank predictor tool or calculate your percentile score manually. Consider factors like category, state, and exam difficulty. Estimated ranks:
- 280-300 marks: Rank 1-20
- 240-250 marks: Rank 428-755
- 200-210 marks: Rank 2720-3803
- 150-160 marks: Rank 11678-17290
Use tools like Shiksha's JEE Main Rank Predictor for more accurate estimates.
New answer posted
a year agoContributor-Level 8
A JEE Main is not always required to take admission in B.Tech at Amity University. On the one hand, it is accepted and can result in your getting scholarships or direct admissions, but 12 th grade marks are important. The aggregate eligibility students need is aggregate of above 60 percent in 10+2 with Physics, Chemistry andMath/Biology (55 percent in the case of sponsored category). Amity too holds the Amity JEE entrances tests. But when you are having good 12 th Board result (e.g. 80% or more) or you have got good score in JEE main (e.g.30+ score with 60% in PCM/PCB), then you may be having direct admission without touching Amity JEE
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