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2 years agoContributor-Level 10
The JEE Main cutoff for CSE at NIT Karnataka ranges from 578-1002 for the general category. However, it is important to note that the cutoff varies every year depending on various factors such as the number of students appearing for the exam, the difficulty level of the exam, and the number of seats available.
New answer posted
2 years agoContributor-Level 10
I hope this helps! Let me know if you have any other questions.
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2 years agoContributor-Level 10
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2 years agoContributor-Level 10
New answer posted
2 years ago
Contributor-Level 10
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2 years agoContributor-Level 10
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2 years agoContributor-Level 10
JEE Main 2026 exam pattern has been released by the NTA. As per exam pattern, the JEE Main Paper 1 (BE/B.Tech) exam will consist of 75 questions, 25 each from Physics Chemistry and Mathematics. Out of 25 questions, 20 will be MCQs and 5 will be NAV. Students need to answer all 75 questions. JEE Main paper 2A for B.Arch consists of 77 questions of which 25 are from Mathematics, 50 from General Aptitude and 2 from Drawing. In Paper 2B for BPlan total questions are 100 of which 25 are from Mathematics, 50 from General Aptitude and 25 from Planning.
The question paper will have no internal choices within questions and total duration of exam
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2 years agoNew answer posted
2 years agoContributor-Level 10
JEE Main is conducted for multiple courses and the syllabus is different for each course. The syllabus of JEE Main Paper 1 (BE/B.Tech) includes class 11 and 12 Physics, Chemistry and Mathematics topics. For JEE Main paper 2A B.Arch the syllabus consists of Mathematics, General Aptitude and Drawing. Similarly, for JEE Main Paper 2B B. Plan the syllabus is Mathematics, General Aptitude and Planning. Candidates can check and download the detailed topics-wise JEE Main syllabus on the Shiksha page as well as on the official website jeemain.nta.nic.in.
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