Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
S
a year ago

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: option (i)

 As the chemical properties depend upon the number of electrons present in the atom thus the isotopes resemble the same chemical properties as they have the same number of electrons i.e. atomic number.

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New answer posted•a year ago
S
a year ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (C)

(A) The molecule of a compound is obtained when two or more atoms of different elements are combined together.

(B) A compound can be separated into its constituent elements by physical methods of separation.

(C) A compound

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New answer posted•a year ago
S
a year ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (A)

The density (d ) is given by the formula:

d = m V

Here, m is the mass and v is the volume

On substituting the values in the above equation:

3.12 g mL-1 = m 1.5 m L M = 4.68 g

The mass will be 4.7 upto 2 significant figure.

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New answer posted•a year ago
S
a year ago

This is a Matching Type Questions as classified in NCERT Exemplar

Ans:

(i) Cr                  (d)  [Ar] 3d54s2

(ii) Fe2+             (c) [Ar]3d64s0

(

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New answer posted•a year ago
S
a year ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (C)

The empirical formula mass of CH2O is 30 g

The relation between empirical and molecular formula is given as,

n = M o l e c u l a r f o r m u l a m a s s E m p i r i c a l f o r m u l a m a s s  …. (1)

On substituting the values in equation (1)

n = 180 g 30 g  = 6

Thus, the molecular formula of the compo

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New answer posted•a year ago
S
a year ago

This is a Matching Type Questions as classified in NCERT Exemplar

Ans:

(i) Photon  (d) Exhibits both momentum and wavelength

(ii) Electron  (d) Exhibits both momentum and wavelength

(iii) ψ 2 (b) Probability density

                     

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New answer posted•a year ago
S
a year ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (B)

The molar mass of carbon is 44 g mol-1

44 g of carbon dioxide contains 12 g of carbon

The percentage composition is given as, % composition

= m a s s o f t h a t c l e m e n t m o l a r m a s s o f c o m p o u n d * 100

On substituting the values in the above equation,

% of carbon = 12 g 44 g m o l - 1 * 100

= 27.27%

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New answer posted•a year ago
S
a year ago

This is a Matching Type Questions as classified in NCERT Exemplar

Ans:

(i) X-rays  (d) ν = 1018Hz

(ii) UV  (c) ν = 1016Hz

(iii) Long radio waves (a) ν = 10 -104 Hz

(iv)Microwave  (b) ν = 1010 Hz

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New answer posted•a year ago
S
a year ago

This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (A)

The molarity (M) is given by the formula:

M = n V ( L )

On substituting the values in the above equation:

0.02M = n × 1000 L 100

n = 0.002 mol

The number of molecules can be calculated as, number of moles

= n u m b e r o f m o l e c u l e s A v o g a d r o s n u m b e r

On substituting the values in the above

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New answer posted•a year ago
S
a year ago

This is a Matching Type Questions as classified in NCERT Exemplar

Ans:

(i) Hund's Rule             (c) Pairing of electrons in the orbitals belonging to the same subshell does not take place until each

      &nbs

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