Ncert Solutions Chemistry Class 11th

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: Hybridisation in the case of PCl₅ :

The hybridisation of phosphorus PCl₅ is sp₃d and it has a trigonal bipyramidal geometry. The axial bonds in PCl₅ are slightly longer as compared to the equatorial bonds because axial bonds exp

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: Formation of N₂ molecule: Electronic Configuration

σ1s^{2 $<$} σ* < 1s² < σ2s² < σ*2s² < [ π2p²_x = π2p²_y] < σ2p²_z

The bond order will be:

$\frac{1}{2}$ ( 10-4)= 3.0

Bond order indicates the number of bonds in a diatomic molecule. Triple bond N=N.

Formation of F₂ molecule: Ele

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Option (C) The combustion reaction of methane is given below

CH₄ + O₂ ->  CO₂ + H₂O

In this reaction, water and carbon dioxide are formed.

According to the reaction, 1 mole of methane gives 2 moles of water. So, 16 g of

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Option (C)

In the decimal portion, only trailing or final zeros are significant. This is in accordance with the rules of significant figures.

The given number, 0.200 has 3 significant figures whereas the number, 200 has onl

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Option (B)

Atomic mass unit is defined as a mass that is equal to accurately  the mass of carbon-12 atom.

When scientists compare the relative atomic masses of the elements to the mass of carbon, they find that they are

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

(i) Both A and R are true and R is the correct explanation of A.

Explanation: The molecular formula gives the actual number of different atoms present in a molecule and the empirical formula gives a simple whole number rati

This is a Matching Type Questions as classified in NCERT Exemplar

(i) → (e) (ii) → (d) (iii) → (b) (iv) → (g) (v) → (c), (h) (vi) → (f) (vii) → (a) (viii) → (i)

Explanation:

(i) It is defined as the number of moles of solute dissolved in 1 litre of solution. So, the unit of molarity is mol L-1
(ii) M

This is a Matching Type Questions as classified in NCERT Exemplar

(i)- (b); (ii) - (c); (iii) - (a); (iv) - (e); (v) - (d)

(i) 88 g of CO₂

The number of moles is given by the following formula,

Moles = $\frac{\mathrm{M}\mathrm{a}\mathrm{s}\mathrm{s}}{\mathrm{M}\mathrm{o}\mathrm{l}\mathrm{a}\mathrm{r}\mathrm{}\mathrm{m}\mathrm{a}\mathrm{s}\mathrm{s}\mathrm{}\mathrm{}\mathrm{}\mathrm{}\mathrm{}}$  - (1)

So, the number of moles of CO₂ is calculated by using equation (1) as follows

Moles of

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (A), (D)

Law of conservation of mass: According to this law, the mass is neither created nor destroyed during a chemical reaction in an isolated system. It can only be transformed from one form to another. Burning of wood is an

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (C), (D)

Molality: It is defined as the number of moles of solute divided by the mass of solvent in kg . It is denoted by m . The formula is expressed as

m = $\frac{\mathrm{n}}{\mathrm{W}\mathrm{}\mathrm{}}$

The SI unit of molality is 1 mol/kg

Molarity: It is defined as the num