Moving Charges And Magnetism Formulas

Moving Charges And Magnetism Formulas

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nitesh singh
Senior Executive
Updated on Oct 23, 2025 10:42 IST
Find all the important formulas of Class 12 Physics Chapter 4 Moving Charges and Magnetism here. This Formula sheet covers Biot-Savart Law, Ampere’s Circuital Law, magnetic fields, force on moving charges, and more. These are ideal for NEET and JEE preparation.

Find all the important formulas of Class 12 Physics Chapter 4 Moving Charges and Magnetism here. This Formula sheet covers Biot-Savart Law, Ampere’s Circuital Law, magnetic fields, force on moving charges, and more.

Magnetism Formulas

A compiled formula list is always a helpful resource for CBSE Board and competitive exam aspirants. We at Shiksha have created a simple and highly useful Moving Charge and Magnetism Formula sheet, which is equally good for quick revision and numerical practice. Solve the NCERT Exercise using the Class 12 Physics chapter 4 formulas provided by Shiksha.

We offer complete study material for all Class 12th Physics chapters. Learn the important concepts of Class 12 Physics Chapter 4 through our NCERT Notes and combine them with quick formula revision for the best results. Memorize Magnetism Formulas and Practice NCERT Exemplar to boost your competitive exam preparation.

Table of contents
  • Magnetic Force
  • Magnetic force on a current-carrying conductor
  • Motion in a Magnetic Field
  • Biot-Savart Law
  • Ampere’s Circuital Law
  • The Solenoid
  • Torque on Current Loop
  • Magnetic Dipole
  • Moving Coil Galvanometer
View More

Magnetic Force

  • Lorentz force on a charge q, that is moving with velocity v in a magnetic field B [As vector cross product]:

F B = q ( v × B ) \mathbf{F}_B = q (\mathbf{v} \times \mathbf{B})

  • Only the magnitude of Lorentz force

F B = q v B sin θ F_B = q v B \sin\theta

  • Lorentz Force on a charge when both the Electric and Magnetic fields are present.

F = q ( E + v × B )

 

Magnetic force on a current-carrying conductor

  • Force on a Straight conductor of length L with electric current I in a magnetic field B.

F = I ( L × B ) \mathbf{F} = I (\mathbf{L} \times \mathbf{B})

  • Magnitude of force of the above-given force.

F = I L B sin θ

  • Force when conductor is parallel to magnetic field direction

F = 0

  • Force when conductor is perpendicular to B:

F = I L B

Motion in a Magnetic Field

  • Path of charge which is moving in different conditions: three conditions are given.
    • When velocity is perpendicular to magnetic field direction, it will be circular path.
    • When velocity vector is parallel to magnetic field, it will be a straight path.
    • If velocity vector has both components, then it will be a helical path.
  • Radius of Circular Path

    r = m v q B r = \frac{m v_\perp}{q B}

     

  • Angular Frequency often used in Cyclotron:

    ω = q B m \omega = \frac{q B}{m}

     

  • Time Period of the completing the circle.

    T = 2 π m q B T = \frac{2\pi m}{q B}

     

  • Pitch of Helical path.

    p = v
    × T = 2 π m v q B

Biot-Savart Law

Magnetic field due to a conductor is proportional to the current element which is at a distance and angle θ.

  • Small magnetic field element dB due to a Current-carrying conductor due to current element dI, at a distance r:

d B = μ 0 4 π I d l × r ^ r 2 d\mathbf{B} = \frac{\mu_0}{4\pi} \frac{I \, d\mathbf{l} \times \hat{\mathbf{r}}}{r^2}

  • Magnitude of Magnetic field:

d B = μ 0 4 π I d l sin θ r 2 dB = \frac{\mu_0}{4\pi} \frac{I \, dl \sin\theta}{r^2}

  • Magnetic Field on axis of a Circular Current Loop at a distance x from the centre of loop.

B = μ 0 I R 2 2 ( R 2 + x 2 ) 3 / 2

  • At the center of the loop:

B center = μ 0 I 2 R

Ampere’s Circuital Law

Line integral of the magnetic field B around any closed amperian loop is equal to μ₀ times the net current enclosed by the loop.

  • Circuital Law Formula

B d l = μ 0 I enclosed \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I_{\text{enclosed}}

Applications of Ampere's Circuital Law

  • Magnetic Field Due to a Long Straight Current-Carrying Wire of Infinite Length
B = μ 0 I 2 π r
  • Magnetic Field Inside a Long Solenoid with n turns per unit length

B = μ 0 n I B = \mu_0 n I

  • Inside a Toroid of radius r with N turns 

B = μ 0 N I 2 π r

Related Physics Class 12 Chapter 4 Study Material 
Class 12 Moving Charges and Magnetism NCERT Solutions
Physics Moving Charges and Magnetism NCERT Notes
Class 12 Physics Chapter 4 NCERT Exemplar Solutions
Class 12 Moving Charge and Magnetism Quick Revision Notes

The Solenoid

It is an electromagnet made by wrapping a metallic wire around a hollow metallic cylinder.

  • Magnetic Field Inside a Long Solenoid

B = μ 0 n I B = \mu_0 n I

  • Magnetic Field Inside a Solenoid with Core

B = μ n I

  • Magnetic Field Outside a Long Solenoid

B 0

  • Magnetic Flux Through Solenoid

Φ = B A = ( μ 0 n I ) A

  • Force between Two Parallel Current-Carrying Conductors

F L = μ 0 I 1 I 2 2 π d

Torque on Current Loop

  • Torque on a Current Loop in a Magnetic Field
τ = m × B
  • Magnitude:

τ = m B sin ⁡θ

Magnetic Dipole

  • Magnetic Dipole Moment

m = n I A n ^

  • Magnitude:

m = n I A

Moving Coil Galvanometer

It measure current deflection in circuit using concept of torque on a coil when placed in a magnetic field.

  • Deflecting Torque: τ d = N I A B \tau_d = N \cdot I \cdot A \cdot B
  • Restoring Torque: r = k θ \tau_r = k \cdot \theta
  • Reading at Equilibrium: = k θ N A B I = \frac{k \cdot \theta}{N \cdot A \cdot B}
  • Current Sensitivity: = θ I = N A B k S = \frac{\theta}{I} = \frac{N \cdot A \cdot B}{k}
  • Voltage Sensitivity: v = θ V = N A B k R S_v = \frac{\theta}{V} = \frac{N \cdot A \cdot B}{k \cdot R}

 

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nitesh singh
Senior Executive
Nitesh Singh, a science graduate and content creator, specializes in developing engaging Physics, Chemistry, and Mathematics resources for the K-12 segment. He crafts precise and pedagogically sound Q&As, comprehens Read Full Bio
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