Engineering Entrance Exam

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New answer posted•2 years ago
S
2 years ago

As per JEE Mains rank -31387. And EWS catagory rank of 4992 you've good chance of getting admission to some of the top engineering college in India . ( Computer Science engineering). Or releted specialization. 

  1. 1). National institute of technology (NITs ) 
  2. Indian institute information techno

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New answer posted•2 years ago
S
2 years ago

With a JEE Main general rank of 372,000 and an EWS rank of 57,000, getting into top-tier government colleges for CSE (Computer Science Engineering) or ECE (Electronics and Communication Engineering) might be challenging. Here are some colleges that you can still get:

  • CGC Landran, Mohali, Punjab.
  • Jain

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New question posted•2 years ago
New question posted•2 years ago
New answer posted•2 years ago
S
2 years ago

Here are the basic requirements 

  • There is no age limit for JEE Main 2024 eligibility criteria for repeaters.
  • He/She must have passed their class 12 exam in 2022, 2023 or 2024.
  • Three consecutive attempts are allowed for the JEE Main 2024 examination.
  • Students should have secured the minimum required

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New answer posted•2 years ago
S
2 years ago

You stand a good chance of being accepted into prestigious NITs. Candidates should aim for a JEE score of 250 in order to be admitted to NIT. A 90 percentile or higher can lead to admissions to prestigious NITs like NIT Delhi and NIT Calicut. Even lower ranks—70,000 and above—can get you

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New question posted•2 years ago
New answer posted•2 years ago
S

Biju Patnaik University of Technology (BPUT), Rourkela, Odisha offers various UG and PG courses in various disciplines such as architecture, engineering, management, pharmacy etc. B.Tech is one of the popular course here. They take admission through JEE Main or OJEE Main rank. Candidates should have

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New answer posted•2 years ago
S
2 years ago

Hi Aryan,

The last rank to be allocated in JEE 2023 by JoSAA counselling was 42,135. The cut-off was for the Indian Institute of Information Technology Manipur to enrol in the Electronics and Communication Engineering course.

I hope it will help.

Thank You.

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New answer posted•2 years ago
S
2 years ago

Hello Nandhu!

I have calculated the JEE Mains score basis on the percentile. The formula used is (100 - P)/100) * N + 1, where P is the percentile and N is the total number of students. 

After the calculation based on your percentile, 50 - 60 out of 300 can be the possible score.

I hope it will h

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