NIT Surathkal - National Institute of Technology

Candidates with a valid GATE score are called for the GATE CCMT Counselling for the final admission round at NIT Surathkal. NIT Surathkal cutoff 2023 for MTecj VLSI has ranged between 614 and 665. Going as per the last year trend, candidates with 588 GATE score are not eligible for the NIT Surathkal admission to M.Tech VLSI. Tabulated below is the round-wise closing rank for NIT Surathkal M.Tech VLSI branch for 2023 for General category students:

Candidates seeking admission shall apply for GATE through the COAPS portal and take the entrance exam. Candidates with a Bachelor’s or an equivalent degree in an appropriate branch of Engineering of a minimum four-year duration with 60% aggregate (55% for SC/ST/PwD) can apply. The students shortlisted based on GATE score are further required to appear for CCMT counselling following which the seat allotment is carried out.

The technology institute offers a three-year full-time MCA course. The three-year duration of the course is divided into six semesters of six months each. Admission to the PG course is entrance-based. 

The aspirants with a BCA/BSc Hons/BSc with Mathematics and Statistics subjects with 60% aggregate (55% aggregate for reserved category) can take admission to the MCA course in NITK. Moreover, the candidates must also hold the relevant documents at the time of form filling and admission as proof of eligibility.

Going as per the past three year trends candidates can expect the closing ranks for NIT Surathkal JEE Main cutoff 2024 Round 1 Seat Allotment for top specialisations between the following range: 

• B.Tech. in Electronics and Communication Engineering must range between 3404 and 4554
• B.Tech. in Computer Science and Engineering must range between 618 and 1594
• B.Tech. in Information Technology must range between 1650 and 2652
• B.Tech. in Computational and Data Science must range between 2966 and 3329

NIT Surathkal cutoff is based on JEE Main scores followed by the JoSAA Counselling and later by CSAB Counselling. NIT Surathkal JEE Main cutoff for admission to BTech courses has been released upto Round 8. Candidates seeking admission to NIT Surathkal must have a valid score in order to be eligible for the Counselling. It is also mandatory to register for JoSAA Counselling as well as CSAB Counselling. Tabulated below is the closing NIT Surathkal cutoff for BTech courses offered at the UG level: 

National Institute of Technology Surathkal (NIT Surathkal) has been ranked by NIRF 2025 under various categories such as Engineering, Overall, Research, etc. Candidates can go through the below table for details regarding NIT Surathkal ranking 2025:

The eligibility criteria for MTech course at the NIT Surathkal is that candidate should have passed BTech with a minimum of 60% aggregate from a recognised university. Aspirant should have the degree and mark sheets (original/copies) at the time of form filling and admission confirmation. The selection process include GATE + CCMT Counselling. 

The National Institute of Technology Surathkal provides undergrdaduate, postgraduate, and doctoral-level programmes in the streams such as Engineering, Technology, Science, and Management. The courses provided by the institute include BTech, MTech, MCA, MBA, MSc, PhD, etc.  The admissions to these courses are entrance-based. Also, candidates need to fulfil the eligibility criteria to proceed for NIT Surathkal admission process.

The cutoff trend for B.Tech at NIT Surathkal has been decreasing in the recent years. In 2022, the closing rank for B.Tech. under general category for all India quota was 25078. In 2023, it decreased to 23632. Likewise, the cut off ranks have changed from 34699 to 8409 for OBC, 76541 to 4193 for SC, 789 to 1001 for ST, 32563 to 3735 for EWS, and 460 to 634 for PWD.

This trend is likely to continue in the coming years, as the demand for engineering education in India continues to grow. Similar cut off trend can be seen for female candidates under all categories however the ranks are slightly different.