SASTRA (Deemed to be University) Thanjavur Answered Questions

Yes, you can get admission to B.Tech. in Robotics and Artificial Intelligence with 60% in Class 12 at SASTRA University. The eligibility criteria for B.Tech./5 Year Int. M.Tech. Programme is a pass in the +2 examination with Mathematics & Physics as compulsory subjects of study with either Chemistry / Bio-Technology / Computer Science / Biology and recognised by any State Board / Central Board or any other accepted by SASTRA as equivalent to 10+2 examination, with a minimum +2 aggregate of 60% marks in a single sitting.

Step 1: Determine the admission stream
Admissions to B.Tech. in Computer Science and Engineering at SASTRA University are conducted under two streams: Stream 1 (based on JEE (Mains) score and +2 Marks) for 70% of seats and Stream 2 (based on +2 marks) for 30% of seats.
Step 2: Check eligibility for Stream 1
For Stream 1, applicants must have a valid JEE (Mains) score and normalized +2 marks. The weightage for JEE Main scores and +2 marks will be 25% & 75% respectively.
Step 3: Calculate the combined score for Stream 1
The aggregate JEE Main score and normalized +2 aggregate will be taken together as per the weightage and applicants will be ranked based on the resultant combined score.
Step 4: Check eligibility for Stream 2
For Stream 2, applicants must have +2 marks. Admission is based on +2 marks for 30% of the seats.
Step 5: Apply to SASTRA University
Applicants must apply to SASTRA University through the official website or other designated channels, ensuring they meet the eligibility criteria for their chosen stream.
The final answer is:
1. Determine the admission stream
2. Check eligibility for Stream 1
3. Calculate the combined score for Stream 1
4. Check eligibility for Stream 2
5. Apply to SASTRA University

To get admission in B.Tech. in Computer Science and Engineering at SASTRA University, you need to have the following documents:
1. 10+2 examination certificate with Mathematics & Physics as compulsory subjects of study with either Chemistry / Bio-Technology / Computer Science / Biology.
2. A minimum aggregate of 60% marks in Maths, Physics and Chemistry/ Bio-Technology/Computer Science / Biology, obtained in a single sitting.
3. Age should not be more than 19 years as on 01.08.2025.

The placement statistics for B.Tech. in Electronics and Communication Engineering at SASTRA University are as follows:
the highest package: 29 lakhs
Average package: 4-8 lakhs
Companies that offered placements:
Amazon: 27 lakhs
PayPal: 21 lakhs
Cypress Semiconductor Corporation: 13 lakhs
Microsoft: 9 lakhs
Tata Communication: 7-8 lakhs
Honeywell Collins: 4.5 lakhs
TCS: 3.3 Lacs (the lowest package)
Number of companies that offered core jobs: 15
Average package for core jobs: 4 lakhs

The placements for B.Tech. in Electronics and Communication Engineering at SASTRA University are as follows:
- the highest package: 29 lakhs
- Average package: around 4-8 lakhs
- Companies that visit the campus: Amazon, PayPal, TCS, City Union Bank, etc.
- Average salary for TCS: 4 lakhs
- the lowest package: around 3 Lacs (offered by TCS)

For B.Tech. in Civil Engineering at SASTRA University, admission is based on two streams: Stream 1, which considers JEE (Mains) scores and +2 marks for 70% of the seats, and Stream 2, which is based on +2 marks for 30% of the seats. There isn't a specific entrance exam for SASTRA University itself for this program; instead, it utilizes JEE (Mains) scores as part of its admission criteria for Stream 1.

B.Tech. in Chemical Engineering at SASTRA University can be chosen for its:
* Programme Educational Objectives (PEOs) that focus on creating responsible chemical engineers
* Flexibility
* Intellectual Rigor
* Job Security
* Programme Specific Outcomes that enable graduates to examine processes, select appropriate processes, prepare material and energy balance, perform experiments, design process equipment, and develop mathematical models.

To be eligible for admission to the B.Tech. in Chemical Engineering at SASTRA University, a candidate should pursue a stream with Mathematics and Physics as compulsory subjects of study, along with either Chemistry, Bio-Technology, Computer Science, or Biology, with a minimum aggregate of 60% marks in all subjects in the +2 examination from a recognised State Board/Central Board or any other accepted by SASTRA as equivalent to 10+2 examination.

A pass in the +2 examination with Mathematics & Physics as compulsory subjects of study with either Chemistry / Bio-Technology / Computer Science / Biology and recognised by any State Board / Central Board or any other accepted by SASTRA as equivalent to 10+2 examination, with a minimum +2 aggregate of 60% marks in a single sitting.