Engineering Entrance Exam
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New answer posted
2 years agoBeginner-Level 4
Vivekananda Global University, is located in Jaipur. The Minimum marks required in class 12th for administrative course in Vivekananda Global University is more than 50 percentage for general category and more than 45 percentage for SC/ST category. Vivekananda Global University gives admission in B.Tech on basis of scores of JEE Mains, CUET, VGUCET . So, without JEE Mains it's not possible to get admission in this college.
New answer posted
2 years agoContributor-Level 9
- B.Tech Artificial Intelligence and Data Science: 13079
- B.Tech Computer Science and Business Systems: 16942
- BE Computer Science and Engineering: 13079
- BE Electronics & Communication Engineering: 14123
- BE Electronics and Instrumentation Engineering: 7190
- BE Biomedical Engineering: 12008
New answer posted
2 years agoContributor-Level 9
New answer posted
2 years agoContributor-Level 9
DegreeProgramme/ Course offeredDomain/ General/ Optional Languages mapped to the ProgrammesEligibility for the programmeRemarks
B.Com ( Hons.)General Test or Accountancy
Applicants appearing for their class 12 examinations from any of the Boards affiliated to the Council of Boards of School Education (COBSE) or National or International Boards recognised by the Association of Indian Universities (AIU) with a minimum of 60% or equivalent in their class 12 examination are eligible to apply. For Cambridge/lGCSE examinations and examinations of the approved British Examination bodies a minimum five subjects including Engl
New answer posted
2 years agoContributor-Level 7
No, Joint Entrance Examination (JEE) is not required for admission to University Visvesvaraya College of Engineering. Candidates need to take the state common entrance examination KCET to take admission in this college. The admission process for University Visvesvaraya College of Engineering is done through Common Entrance Test. Candidates must have scored 45% in class 12 from a recognized board, and Physics, Chemistry, and Mathematics should be main subjects.
New answer posted
2 years ago
Contributor-Level 10
For 2023, cut off was 3258 for General category candidates in All India quota for BTech in Computer Science and Engineering in IIT Dhanbad (ISM). For female candidates in general category under All India quota, 5862 was the closing rank. BTech cut off varies depending on the category and domicile/quota of the applicant.
New answer posted
2 years agoNew answer posted
2 years agoContributor-Level 6
There were different TNEA cutoffs for B.Tech according to specific fields at Kumaraguru College of Technology for 2023.
B.Tech Artificial Intelligence and Data Science | 23403 |
BE Computer Science and Engineering | 27139 |
B.Tech Information Technology | 38568 |
BE Electrical and Electronics Engineering | 51742 |
BE Aeronautical Engineering | 64102 |
B.Tech Biotechnology | 65866 |
BE Automobile Engineering | 81375 |
BE Electronics and Instrumentation Engineering | 82269 |
BE Mechatronics Engineering | 82856 |
BE Mechanical Engineering | 83775 |
B.Tech Fashion Technology | 84656 |
B.Tech Textile Technology | 85885 |
New answer posted
2 years agoContributor-Level 10
Applicants are required to have completed one of the following entrance examinations/tests:
JEE ( Main)with a minimum of 60 percentile. Students with aggregate score of 75% in class 12 but JEE (Main) percentile above 50% may be considered.
SAT / BMU-SAT / CUET
New answer posted
2 years agoContributor-Level 6
Yes, you might get direct admission at Kumaraguru college of technology if the rank is around 2000. You have to keep Kumaraguru college of technology as your first choice in TNEA councelling process. TNEA cutoffs are around 3092 to 27310th rank for general category students. 22146 to 67758th rank is for SC/ST category students approximately in 2023 majorly for Bachelor courses (B.Tech and B.E.). So, 2000 i guess is a good rank to get into Kumaraguru college of technology for Bachelor course.
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