Exam

Candidates get admitted to GITAM School of Pharmacy, Visakhapatnam  programs based on their GITAM GAT results. To take part in the BPharm and MPharm admissions procedure, candidates might take the entrance exam. 
Those whose entrane scores put them on the short list can pay the course fee to guarantee their spot in the program. Candidates must check the selection criteria of the course they are applying to, in order to follow it precisely. 

There are multiple factors that help universities abroad make decisions about admissions for international students using SAT. Some of the key factors include:

• SAT score of the applicant versus the applicant pool score.
• Syncing SAT score with previous adacemic background.
• Based on SAT score assess applicant's analytical and problem solving skills (mentioned on SAT score report).
• Finally, if there is scope for offering financial aid, SAT scores may be one of the deciding factors.

Thus, these are the uses of SAT at an international level for offering admissions to applicants.

There are 63 countries which accept SAT scores for admission and use them to assess applicants. These countries are as follows:

Shanti Business School accepts candidates who have scored 50% at graduation level (45% in case of specified categories) and have a valid score of CAT/ MAT/ XAT/ ATMA/ CMAT that is not earlier than 12 months from the date of applying. The final selection of the candidate is based on 35% Entrance Examination score, 40% Presentation, PI & GD, 20% Academic performance, and 5% sports and extra-curricular activities.

Explanation- velocity of a freely falling body is v= $\sqrt[]{2gh}$

And $?=\frac{h}{mv}=\frac{h}{m\sqrt[]{2gh}}$

$?=h$ ^-1

Explanation-number of photon emitted per second n= $\frac{p}{\frac{hc}{?}}=\frac{p?}{hc}=\frac{20*5000*{10}^{-10}}{6.62*{10}^{-34}*3*{10}^8}$

$=5*{10}^{19}{s}^{-1}$

(ii) E=hc $/?$ = $\frac{6.62*{10}^{-34}*3*{10}^8}{5000*{10}^{-10}*1.6*{10}^{-19}}=2.48eV$  this enegy is greater than 2 so emission is possible

(iii) work function $?$ = $\frac{p}{4?d^2}*?r^2?t$ = ${?}_o$

$?t$ = $\frac{4?d^2}{p{r}^2}$ = $\frac{4*2*16*1.6*{10}^{-19}*2^2}{20*{(1.5*{10}^{-10})}^{-2}}=28.4s$

(iv) N= $\frac{n?r^2}{4?d^2}*?t$

 = $\frac{5*{10}^{19}*{(1.5*{10}^{-10})}^2*28.4}{4*({2)}^2}$ =2

(v) as the time of emission is 11.04s so photoelectric is not spontaneous.

Explanation- according to law of conservation of momentum

S0 m_Av+m_b0=m_Av₁+m_Bv₂

So m_A(v-v₁)= m_Bv₂

according to law of conservation of kinetic energy

1/2m_Av²=1/2m_Av₁²+1/2m_Bv₂²

So m_A(v²-v₁²)= m_Bv₂²

From above eqn we can say that v+v₁=v₂ or v=v₂-v₁

So v₁= $\frac{m_A{-m}_B}{m_A{+m}_B}$ v  and v₂= $\frac{2m_A}{m_A{+m}_B}$ v

_$?$ initial=h/m_Av

_$?$ final=h/m_Av₁= $\frac{h\left(m_A{+m}_B\right)}{m_{a\left(m_A{-m}_B\right)v}}$

$d?$ = $?$ _final- $?$ _initial= $\frac{h}{m_{A}v}\{\frac{m_A{+m}_B}{m_A{-m}_B}-1\}$

Yes, admission to Backstage Pass Institute of Gaming and Technology UG courses is entrance-based. The college conducts an in-house entrance exam for admission to the courses. Students who successfully fill the application form are informed about the commencement of the exam and other details.