International Institute of Information Technology, Pune
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New answer posted
8 hours agoBeginner-Level 1
If you get above 93 percentile in the 1st or 2nd session of JEE main, take preparation of JEE advanced. You can get IIT's seat through JEE advanced. Or you can also try for NITs. If you are unable to clear the cutoff, you can also give exams for state government colleges and exams for specific colleges ( like VITJEE, BITS Pilani etc.)
New answer posted
YesterdayContributor-Level 10
The I2IT Pune JEE Main cutoff 2025 was released in the form of ranks for the All India categories. For the General AI category, the BE in the Computer Engineering branch had the overall cutoff ranging from 42136 in the first round to 52834 in the last round. Hence, General AI students needed to attain a rank of at least 52834 to secure admission to the International Institute of Information Technology, Pune.
Note: Other categories will have different cutoffs.
New answer posted
YesterdayContributor-Level 10
To check the merit list for admission to I2IT Pune for the BE courses via the MHT CET entrance examination, students have to go to the official website of the Maharashtra State Common Entrance Test (CET) Cell. During admissions, the final merit list is published on the official site.
Only those students with names are in the merit list are considered eligible for the CAP counselling process. This process is important for admission to any of the offered BE courses.
New answer posted
YesterdayContributor-Level 10
The selection process for the All India quota students is based on their JEE Main ranks. Students who want admission to I2IT Pune need to appear in the CAP counselling process to avail a seat for any BE course.
The minimum rank required for admission was 68635 for the General AI category. Hence, students need to secure at least 68635 to be eligible for admission. Refer to the table below to know the exact minimum ranks for each offered BE branch.
| Course | I2IT Pune JEE Main cutoff 2025 (Last Round) |
|---|---|
| B.E. in Computer Engineering | 52834 |
| B.E. in Electronics and Telecommunication Engineering | 68635 |
| B.E. in Information Technology | 61370 |
Note: This is the cutoff for the General AI category; other categories will have different cutoffs accordingly.
New answer posted
YesterdayContributor-Level 10
The minimum rank required to get admission at I2IT Pune would depend on the category you belong to. The I2IT Pune JEE Main cutoff 2025 for the General AI category says that a rank of at least 61370 is required to be eligible for admission to the BTech in Information Technology department. This category had an overall cutoff ranging from 47728 to 61370 for this course.
Note: This is the cutoff for the General AI category; other categories, quotas, courses, etc., will have different cutoffs.
New answer posted
YesterdayContributor-Level 10
Students who attempted the JEE Main should start preparing for the JEE Advanced entrance examination if they want admission at IITs. Those who score above the 98th percentile in JEE Main session 2 should start to study for the JEE Advanced exam.
Students who get around the 95th and 98th percentile should attempt to solve more mock tests and previous year question papers to increase their chances of attaining a good enough rank in the JEE Advanced.
New answer posted
2 days agoContributor-Level 10
Yes, the International Institute of Information Technology, Pune, does accept the MHTCET M.Tech entrance examination results for admission to the ME/MTech programme. Students who belong to the Home State quota can avail admission to this institute by first appearing for the exam and then participating in the counselling process.
Students should note that the cutoff gets released in the form of percentiles for various HS quota categories. Each category will have different cutoffs accordingly. For more information about I2IT Pune cutoff 2025, students can visit this page.
New answer posted
2 days agoContributor-Level 10
Yes, you could get a seat at I2IT Pune if you belong to the General HS category. This category had the overall cutoff ranging between 23.67 and 4.54. Students can expect admissions to be available after the initial round.
If you belong to the OBC, SC, ST, or EWS AI category, then too admissions are possible. Students can see the table below to know the lowest percentile for each HS category.
| Category | I2IT Pune MHTCET M.Tech cutoff 2025 |
|---|---|
| General | 4.54 |
| OBC | 17.22 |
| SC | 13.64 |
| ST | 7.33 |
| EWS | 10.39 |
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New answer posted
2 days agoContributor-Level 10
I2IT Pune MHTCET M.Tech cutoff 2025 for the OBC category students belonging to the Home State quota ranged from 10.39 to 17.22 for the M.Tech in Computer Engineering course. Students who want admission to this course have to first appear for the accepted entrance examination and then sit for the counselling process to be considered for admission. For the round-wise closing cutoff details for this category, see the list below.
- Round 1: 17.22
- Round 2: 10.39
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