JEE Main Cut-off
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New answer posted
10 months agoContributor-Level 10
The NIT Hamirpur cutoff 2025 has been released for admission to the BTech programme. The Round 1 of the closing ranks varied between 10852 and 41548 for the students belonging to the General AI quota. The cutoff ranks vary for different courses, specialisations, rounds, categories, and quotas. Detailed Round 1 JEE Main closing ranks for all the courses available at NIT Hamirpur for the General AI quota are tabulated below:
| Course | JEE Main Round 1 Closing Ranks 2025 |
|---|---|
| B.Tech. in Civil Engineering | 41202 |
| B.Tech. in Electrical Engineering | 23305 |
| B.Tech. in Mechanical Engineering | 30851 |
| B.Tech. in Electronics and Communication Engineering | 17112 |
| B.Tech. in Computer Science and Engineering | 10852 |
| Bachelor of Architecture (B.Arch.) | 780 |
| B.Tech. in Chemical Engineering | 35719 |
| B.Tech. in Materials Science and Engineering | 41548 |
| Integrated B.Tech. + M.Tech. in Computer Science and Engineering | 12558 |
| Integrated B.Tech. + M.Tech. in Electronics and Communication Engineering | 18796 |
| B.Tech. in Engineering Physics | 30990 |
| B.Tech. in Mathematics and Computing | 14230 |
New answer posted
10 months agoContributor-Level 10
NIT Calicut admits students to its BTech courses based on JEE Main ranks, followed by JoSAA counselling. If you belong to the general category under the AI quota, the minimum rank required to be eligible for Round 1 admission was 4678 or less. The maximum cutoff rank went up to 28830. Candidates can refer to the table below to view the JEE Main first round closing ranks for the B.Tech. programme across multiple specialisations for the General AI quota:
| Course | JEE Main Round 1 Cutoff 2025 |
|---|---|
| B.Tech. in Chemical Engineering | 21138 |
| B.Tech. in Computer Science and Engineering | 4678 |
| B.Tech. in Civil Engineering | 28830 |
| B.Tech. in Electrical and Electronics Engineering | 9624 |
| B.Tech. in Electronics and Communication Engineering | 7380 |
| B.Tech. in Mechanical Engineering | 15624 |
| B.Tech. in Production Engineering | 28078 |
| B.Tech. in Biotechnology | 26457 |
| B.Tech. in Engineering Physics | 13924 |
| B.Tech. in Materials Science and Engineering | 26840 |
| B.Tech. in Energy Engineering | 18696 |
New answer posted
10 months agoContributor-Level 7
The rank you would need to get admission to the courses offered would depend entirely on which category you belong to and which program you are interested in. As per IIIT Guwahati's last round data, the closing cutoff for various courses ranged between 28255 and 44592 for the General AI category candidates. The toughest specialisation out of all was B.Tech. in Computer Science and Engineering, with the last-round closing rank of 28255 for the General AI category candidates. The least competitive course is B.Tech. in Electronics and Communication Engineering for the General AI category. Therefore, for admission
New question posted
10 months agoNew answer posted
11 months agoContributor-Level 9
Yes, candidates can get DTU with 40000 rank for BTech. Candidates have the opportunity to enroll in Delhi Technological University for certain BTech specialisations. Delhi Technological University JAC Delhi cutoff 2024 is released for admisison to the BTech courses. The closing cutoff ranged between 8336 and, 54432. Candidates can refer to the table below to check out the specialisations available for admission up to 40000 rank in JAC Delhi at DTU:
New question posted
11 months agoNew answer posted
a year agoBeginner-Level 4
Cutofff 2024 are
general :93.5
ews: 81.33
Obc-ncl: 79.67
St: 46.89
sc: 60.022
pwd: 0.81
These institutions have accepted SC category ranks beyond 50,000 in previous years, especially in disciplines like Civil, Mechanical, or Electrical Engineering. Admission chances improve under the Home State quota or in less competitive branches.
New answer posted
a year ago
Contributor-Level 6
According to our knowledge JEE main cut off 2025 percentile for differnet groups are
General: 92+
OBC-NCL: 83–92
EWS: 85+
SC: 61+
ST: 47+
New answer posted
a year agoContributor-Level 9
The JEE Mains (Common Rank List - CRL) cutoff of last year (2024) for B.Tech in Computer Science and Engineering (CSE) at I.K. Gujral Punjab Technical University (IKG PTU) for General category Home State candidates varied between around rank 63 and rank 1710 in the last round of seat allotment. This cutoff applies to Home State quota and General category candidates. Cutoffs differ based on category and quota.
New answer posted
a year agoBeginner-Level 5
I think the latest cutoff for JEE is for General it would be 93%, for OBC, it is 70% and for SC, it is 40%.
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