For DTU (Delhi Technological University) and NSIT/NSUT admissions through JEE Main:
All India General (CRL) Rank is considered for General category seats.
All India OBC-NCL Rank is considered for OBC category seats.
JEE Main Cut-off
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New answer posted
6 months ago
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Neerja Rohatgi
Contributor-Level 10
NIT Jamshedpur JEE Main cutoff 2026 was published for the first round for various Home State quota categories. The cutoff was released in the form of opening and closing ranks.
For the General HS quota, the round 1 cutoff ranged from 10935 to 47292, with BTech CSE being the toughest branch for admission. Students can refer to the table below to know the round 1 cutoff range for other HS quota categories.
| Category (HS) | NIT Jamshedpur JEE Main cutoff 2026 |
|---|---|
| General | 10935 - 47292 |
| OBC | 4803 - 16055 |
| SC | 2473 - 10234 |
| ST | 1126 - 4065 |
| PWD | 285 - 2072 |
| EWS | 2202 - 7439 |
New answer posted
6 months ago
0 Follower
14 Views
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Neerja Rohatgi
Contributor-Level 10
For the OBC AI category, the NIT Goa cutoff 2026 ranged from 4861 to 12766, with BTech CSE being the most difficult course for admission.
On the other hand, for the OBC HS quota, the round 1 cutoff ranged from 11369 to 38332. Students can see the table below to know the round 1 NIT Goa branch-wise cutoff 2026.
| Course | OBC HS (Round 1 ) | OBC AI (Round 1 ) |
|---|---|---|
| B.Tech. in Computer Science and Engineering | 11369 | 4861 |
| B.Tech. in Electronics and Communication Engineering | 17620 | 6367 |
| B.Tech. in Electrical and Electronics Engineering | 31617 | 8082 |
| B.Tech. in Mechanical Engineering | 38332 | 10413 |
| B.Tech. in Civil Engineering | - / - | 12766 |
New answer posted
6 months ago
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25 Views
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Neerja Rohatgi
Contributor-Level 10
NIT Arunachal Pradesh JEE Main cutoff 2026 for the OBC AI and HS quota was published for the first round. For the OBC AI quota, the round 1 cutoff ranged from 10017 to 17488.
For the OBC HS quota, the round 1 cutoff for the BTech course branches ranged from 49859 to 208588. Students can see the table below to know the cutoff for the first round for both AI and HS quota.
| Course | OBC AI | OBC HS |
|---|---|---|
| B.Tech. in Computer Science and Engineering | 10017 | 49859 |
| B.Tech. in Electronics and Communication Engineering | 12899 | 54421 |
| B.Tech. in Electrical Engineering | 13793 | 166397 |
| B.Tech. in Mechanical Engineering | 15111 | 94114 |
| B.Tech. in Civil Engineering | 16573 | 110446 |
| B.Tech. Biosciences and Bioengineering | 17488 | 208588 |
New answer posted
6 months ago
0 Follower
22 Views
S
Saumya Gairola
Contributor-Level 10
The JEE (Main) cut off for BTech CSE in NIT Durgapur is different for Home state candidates and Other state candidates. Also, the cut off varies according to the category of students (Gen/OBC/SC/ST/EWS). Usually the cut off for the General category students for BTech CSE in NIT Durgapur is 10000 to 12000.
New answer posted
10 months ago
1 Follower
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Chenna kesavulu Putchakayala
Contributor-Level 8
New answer posted
10 months ago
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Piyush Jain
Contributor-Level 10
The round 1 closing rank for the BTech course at MNNIT Allahabad starts from 4265, and it ends on 33173. In the band of these ranks, Computer Science and Engineering was the most competitive specialisation. A student should always keep in mind that, ranks vary for different courses, specialisations, rounds, categories, quotas, etc.
New answer posted
a year ago
0 Follower
18 Views
N
Neerja Rohatgi
Contributor-Level 10
The OBC category All India quota cutoff 2025 for admissions is 87157. IIIT Agartala cutoff 2025 result is based on the JEE Mains rank. This cutoff is essential for OBC AI quota candidates as it determines their eligibility for admission to this University for the programme it offers. The cutoff ranks are based on several factors, such as the difficulty level of the exam, the number of candidates who appeared for the exam, the number of seats available, and previous year trends.
New answer posted
a year ago
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Neerja Rohatgi
Contributor-Level 10
For the OBC category 40,000 rank, you could easily get admission to IITDM Kurnool for all the available M.Tech course specialisations. The last round cutoff rank ranged from 50248 to 103216. The most competitive course specialisation stands at a cutoff rank of 50248 for B.Tech in Computer Science and Engineering, for which you are eligible, as your rank is 40,000. Below is a table provided of the last round cutoff rank for JEE MAINS 2025.
| Course Name | Last round closing rank 2025 |
|---|---|
| B.Tech. in Computer Science and Engineering | 50248 |
| B.Tech. in Electronics and Communication Engineering (Design and Manufacturing) | 74325 |
| B.Tech. in Mechanical Engineering (Design and Manufacturing) | 101470 |
| B.Tech. in Artificial Intelligence and Data Science | 53831 |
| B.Tech. + M.Tech. in Computer Science and Engineering | 61114 |
| B.Tech. + M.Tech. in Mechanical Engineering | 103216 |
| B.Tech. + M.Tech. in Electronics and Communication Engineering | 83499 |
New answer posted
a year ago
0 Follower
12 Views
N
Neerja Rohatgi
Contributor-Level 10
With JEE Mains 2025 cutoff rank of 7000, your chances of getting admitted to IIITDM Kurnool are high if you belong to the General AI category. B.Tech in Computer Science and Engineering qualifying rank according to the last round stands at 39803 for the students belonging to the General AI category. If you belong to the OBC category, All India quota, you can still avail this course with its last round closing rank being 50248. Please note that other categories and rounds will have different cutoffs entirely.
New answer posted
a year ago
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Himanshi Gupta
Contributor-Level 10
UGI Greater Noida BTech cutoff is determined based on applicants JEE Main scores. In 2024, the closing rank ranged from 541927 to 849805. The most competitive closing rank was for the ECE course - 541927 followed by CSE at 554651. The mentioned cutoff was for the general-all India category candidates. During counselling, the seat allotment is done based on the cutoff mark.
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