M.Tech. in Food Processing Technology 

at JNTUK, Kakinada

Yes, JNTUK does offer M.Tech courses for a duration of over two-years. The university offers Master in Technology courses through the university and its affiliated colleges. To get admission into JNTUK M.Tech specialisations, candidates are required to qualify for their BTech/ BE and equivalent degrees with a minimum aggregate of 50%. Additionally, the admission process is based on GATE, followed by CCMT counselling, and through PGECET counselling for GATE and PGECET-qualified students.

Candidates can refer to the table below for MTech placements over the past three years. Check below to know the placement trend for the MTech course:

Note: The above-mentioned data is sourced from NIRF Report 2024 released by the University.

The eligibility criteria to pursue the MTech course at JNTUK are to complete Class 12 with a 50% aggregate with Physics and Maths as a subject. Candidates willing to be admitted to BTech at JNTUK must have valid eligibility criteria and entrance exam scores. JNTUK BTech admission is based on entrance examination i.e., EAMCET. Further, candidates must participate in the EAMCET counselling rounds for final seat allotment.

As per the Jawaharlal Nehru Technological University (JNTU) admission is based  EAMCET (Engg, Agriculture & Medical Common Entrance Test). However, the university other entrance exams for admission to its UG and PG courses. Tabulated below are cousre-wise entracnec exams accepted by JNTUK: 

The CGPA provided for a student by JNTUK is the Cumulative grade point for a student’s overall performance throughout all the semesters in a program. The CGPA is calculated by taking into account all the courses undergone by a student in all the semesters of a programme, i.e. CGPA = Σ (Ci X Si) / ΣCi Where Si is the SGPA of the i^th semester and Ci is the total number of credits in that semester.

As per the B.Tech (R16) academic regulations of JNTUK, Kakinada, the following is 
the procedure for the computation of Cumulative Grade Point Average (CGPA). 

SGPA (Si) = Σ (Ci X Gi) / Σ Ci

Where Ci is the number of credits of the ith course and Gi is the grade point 
scored by the student in the ith course.

The CGPA is calculated by taking into account all the courses undergone by
a student in all the semesters of a programme, i.e.

CGPA = Σ (Ci X Si) / Σ Ci

Where Si is the SGPA of the ith semester and Ci is the total number of 
credits in that semester.

The equivalent percentage can be calculated as per the below formula for the 
B.Tech students who obtains their degrees under R16 regulations ie. 2016-17 
admitted batch onwards (2017-18 batch onwards for lateral entry scheme). 

Equivalent Percentage = (CGPA – 0.75) X 10

Jawaharlal Nehru Technological University Kakinada offers admission through EAMCET, ECET, GATE, APICET, and GPAT exams. 70% of the seats are reserved for candidates who qualify for the entrance examination whereas the rest 30% of seats are reserved for the management/NRI quota.

Jawaharlal Nehru Technological University organises various activities for students such as sports activities and others. Jawaharlal Nehru Technological University, Kakinada campus, is spread over 110 acres of land. The institute has a a library, auditorium, seminar/ conference halls, guest houses, hostels, canteen, internet and wifi, computer labs, bank & fire station. 

There are no minimum scores and ranks required for admission to BTech courses at JNTUK. The ranks and cutoff vary according to the specialisation and seats available at the university. Check out the cutoff for the years 2022, 2023 and 2024 for BTech courses based on the TS EAMCET counselling that can give the applicants an idea about what is the bracket in which candidates are required to score for admissions: