Engineering

Admission to the Computer Science program at CET Bhubaneswar is based on the candidate's rank in the Odisha Joint Entrance Examination (OJEE) or JEE Main score. The cutoff for admission varies every year based on several factors such as the number of applicants, the difficulty level of the exam, and the availability of seats.
As you have mentioned that you belong to the General category and have a percentile score of 95.8, it is difficult to determine whether you will be eligible for admission to the Computer Science program at CET Bhubaneswar. It would depend on the cutoff rank for the Computer Science program in the current academic year and the number of seats available in that program.
I would recommend that you check the previous year's cutoff ranks for the Computer Science program at CET Bhubaneswar and compare it with your rank in OJEE or JEE Main to get a better idea of your chances of admission. You can also visit the official website of CET Bhubaneswar or contact the college's admission office for more information.

Eligibility criteria: Candidates must have passed 10+2 from a recognised board. Bachelor of Technology, BS, or DD candidates can apply for the programme at the end of their sixth semester with the approval of the DUGC of the concerned department. Students must have a minimum CPI of 7.0 at the end of their 6th semester and should not have any backlog in their Undergraduate courses. Candidates need to indicate their preferences for different specializations, like Finance or Operations Management however, these two specializations are available at present. For more information, you may visit the Shiksha SJSOM IIT Bombay page. I hope this will help you.