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New answer posted

a year ago

0 Follower 70 Views

S
Siddharth Agrawal

Beginner-Level 5

Congratulation for getting excellent percentage in JEE . you can easily getting seat in NIT (National Institute of Technology). The seats are allotted on the basis of several categories that are prevalent like ST, SC, GEN, OBC, PWD. In this year admission is total 23954 seats will be offered at NIT. The NIT  contains the total number of seats offered in the particular specializations for an NIT.

New answer posted

a year ago

0 Follower 12 Views

M
Malavika

Contributor-Level 10

The JEE Mains results will be made available online by NTA via the official website. On its official website, the NTA has made available the JEE Main 2024 Paper 2 result. The JEE Main 2024 session 2 paper 2 result is available to candidates at jeemain.nta.ac.in. The application number and date of birth are the login credentials needed to get the JEE Main Paper 2 result in 2024. The JEE Main 2024 paper 2 toppers have also been revealed by NTA along with the results. On April 24, the NTA released the JEE Main 2024 Session 2 Paper 1 result. The JEE Main Result Login 2024 has been made available by NTA on the official websites jeemain.nta.

...more

New answer posted

a year ago

0 Follower 45 Views

S
Shashank Kumar Mishra

Contributor-Level 6

SASTRA University takes the cutoff for admission in B.TECH as follows-

If a student secures a JEE Main Score of 185 and normalized +2 total marks of 95%, the combined score of the student will be (0.25*185)+(0.75*95) = 117.50. They ask applicants to submit the JEE scores in the application form even if they are not qualified for the Advanced or they don't have the cut-off prescribed by MHRD. SASTRA does not use the CBSE cut-off for its admission but its own ranks calculated based on +2 marks and JEE (Main) scores.

As you have 90% in board exam you can easily get ECE branch at SASTRA University, Kumbakonam campus. But you should try

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New answer posted

a year ago

0 Follower 7 Views

H
Himanshi Tirkha

Contributor-Level 10

With this rank, it is highly unlikely to get admission to VIT campuses. The cut-off for VIT campuses is generally high.

As per the data available, candidates selected for VIT based on JEE had under 30000 rank, so a 126344  rank will not be able to provide you admission to B.Tech CSE course at VIT.

I hope it will help. 

New answer posted

a year ago

0 Follower 57 Views

J
JATAVATH BHARATH

Beginner-Level 4

With JEE main rank of 600000 in general and 250000 in OBC. It is difficult to secure top colleges li IITS, NITS 

But you can try for state engineering college many state colleges have there own entrance exam or accept JEE Mains score but have different cut offs

You can try for private engineering college many top private colleges have relatively higher cutoff but can accessible with your rank

  • Vellore institute of technology (VIT)
  • Manipal Institute of Technology (MIT)
  • SRM Institute of Science and Technology
  • Amity University
  • Amity University
  • Sharda University
  • KIIT (Kalinga Institute of Industrial Technology)

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