VNIT Nagpur - Visvesvaraya National Institute of Technology
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5 months agoContributor-Level 6
As per the round 3 of JEE Main cutoff 2025, it is possible to get admission to VNIT Nagpur with a rank of 40,000 in JEE Main. The cutoff for the General AI category candidates was closed at 709 and 42319. Looking at the cutoff range, it was evident that getting admission at 40,000 rank is possible, among the General AI category candidates. Among the OBC AI category candidates, the closing ranks varied between 405 and 14336. For the OBC AI category candidates, getting a seat at 40,000 is not possible.
For the General Home State quota candidates, the range of cutoff was between 505 and 47323. Therefore, it is possible to get admission to
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5 months agoNew answer posted
5 months agoContributor-Level 6
VNIT Nagpur 2025 cutoff has been released for round 1 for students seeking admission to MSc specialisations on the basis of CCMN. The cutoff has been released for different categories belonging to the AI quota. For the General AI category candidates, the cutoff ranks varied between 884 and 1144. Therefore, the lowest rank to get admission into VNIT Nagpur is 884 for the toughest specialisation M.Sc. in Mathematics.
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