B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at Manav Rachna University, Faridabad

4.4 /5

(1 Review)

Private University
Estd. 2004

4.0

Placements

5.0

Infrastructure

4.0

Faculty & Course

5.0

Campus Life

4.0

Value for Money

Raj Mehta

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud - Batch of 2029

4.4

One of the best private colleges in Delhi NCR.

Placements: Around 90% of students are placed in the Software Engineering course. The highest package is between 50 and 60 LPA, according to me. Placement is good and overall depends on the students. Good studies result in good placement. Overall, everything is okay.

Infrastructure: The hostels provide good food, exceptional 24/7 security, and clean, hygienic facilities. The warden is good-natured but strict with periodic student checks. Counselling of students takes place when required. Overall, it is trustworthy.

Faculty: Faculty is good. The exam level is moderate and industry-oriented. The course curriculum is relevant and helps make students industry-ready. Semester exams are not very difficult. Overall, the pass percentage is not definite.

Other: I chose this course because it is a demand-driven field in Gen AI. Overall, it is a good experience.

Reviewed on 11 Jun 2026Read More

View 1 Review

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at
Manav Rachna University
Overview

Manav Rachna University offers a 4 years B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud course at the UG level. To get admitted to Manav Rachna University B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud course, applicants must meet the entry requirements - 60.0% in 12th. Manav Rachna University The total tuition fee for this course is INR 1335200 for the entire duration of the course. Apart from the tuition fee, students are also required to pay a one-time fee of INR 3000. The course offers admission to 60 students. To learn more about other courses offered under B.E. / B.Tech at Manav Rachna University, please visit.

Total Tuition Fees	₹13.35 Lakh Get Fees details
Duration	4 years
Course Level	UG Degree
Mode of Course	Full Time
Official Website	Go to Website
Seat breakup	60
Type of University	Private

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud

Table of contents

Overview
Fees
Student Reviews
Entry Requirements
Admission Process

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at
Manav Rachna University
Fees

Fee components	Amount (4 years)
Tuition Fees The fees might include components other than tuition fees.	₹ 13.35 Lakh
One-time Payment One time fee includes Life Time Alumni Membership Fee	₹ 3,000
Other Fees	₹ 6.16 Lakh
Total fee	₹ 19.54 Lakh

These are based on information available on various sources. Latest values may differ.

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at
Manav Rachna University

Frequently Asked Questions

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at
Manav Rachna University
Students Ratings & Reviews

4.4/5

1 Verified Review Info Icon

4-5
1

Placements4.0

Infrastructure5.0

Faculty & Course4.0

Campus Life5.0

Value for Money4.0

B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at
Manav Rachna University

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B.Tech. in Computer Science Engineering (Gen AI ) in Association with Google Cloud
at
Manav Rachna University
Entry Requirements

General

Requirements for 12th grade Up Arrow Icon

60%
Candidates must have passed 10+2 examination with minimum mentioned marks in aggregate in 4 subjects: Physics, Mathematics, English & one of the subjects out of Chemistry, Computer Science, Biology or Biotechnology. Also requires 60% marks in aggregate in 5 subjects based on: i. English, Physics & Mathematics; ii. One subject out of Chemistry, Computer Science, Biology or Biotechnology; and iii. One subject with the highest score out of the remaining subjects.
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