DILR Preparation Tips for MBA

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New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

 

 

July

 

 

Aug

 

 

Sep

 

 

Oct

 

 

Nov

 

 

Dec

 

Cities

Max

Min

Avg

Max

Min

Avg

Max

Min

Avg

Max

Min

Avg

Max

Min

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Max

Min

Avg

Ajmer

12.0

4.0

5.6

14.0

7.0

11.2

19.0

10.0

14.5

25.0

10.0

17.5

29.0

12.0

23.9

31.0

14.0

25.9

Ayodhya

6.0

1.0

2.0

8.0

3.0

6.0

10.0

5.0

7.5

14.0

9.0

11.5

16.0

11.0

14.5

19.0

14.0

17.5

Mathura

20.0

12.0

13.6

24.0

13.0

19.6

29.0

17.0

23.0

36.0

21.0

28.5

38.0

24.0

33.8

41.0

27.0

36.8

Kashi

13.0

7.0

8.2

16.0

10.0

13.6

19.0

14.0

16.5

21.0

16.0

18.5

24.0

18.0

22.2

26.0

21.0

24.5

New answer posted

8 months ago

Directions for questions: Answer the questions on the basis of the information given below. Given below is a network of oil pipelines and nine hubs– A through I. The requirement of oil at the hubs is exactly met by the flow in the pipelines. The flow in some of the pipelines and the requirement at some of the hubs is also mentioned. A is the only hub which is a source hub, i.e. the hub A does not have any requirement of its own but it supplies the requirement of all the other hubs.

It is also known that

I. The maximum capacity of any pipeline is 1000.

II. The requirement at any hub except A and I is equal to the flow in exactly on

...more
0 Follower 28 Views

P
Payal Gupta

Contributor-Level 10

As not two pipelines connecting same place are carrying same amount, and at least one of the pipelines should carry same as that of the place, either H-I or G-H must carry 300. If G-H carries 300, then H-I must carry 200, which is not possible.

H-I must carry 300 and G-H must carry 400. D-G should carry 400 more than the requirement at G.

G's requirement must equal that of G-H

Requirement at G = 400 D-G = 800

The flow in El must be equal to the requirement at E, and each of them must be equal to 100. Therefore the requirement at I = 100 + 300 = 400.

Considering F, the flow in FB must be equal to the requirement at F, i.e., 100, and the flo

...more

New answer posted

8 months ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

Son

Color of shirt

Likes

A

yellow

writing

K

white/blue/green

singing

S

red

traveling

R

blue/white

reading

N

green/white

playing

New answer posted

8 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Using the reverse of the above condition you can see that the actual percentage voting for each one of the options increased in at least one of the years, Hence, none of the options saw a continuous decrease over the period.

New answer posted

8 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

Percentage of Maharashtra

= 5 9 1 0 0 * 1 0 0 1 0 * 3 6 2 5 = 2 1 3 7 . 5

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

4% of India's crops in 2017-18 = 3625,  

India's export = 3625 * 25 = 90625

New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

Crops exports in 2017-18

= Rs. (17+30+300+200+60)lacs

= Rs. 607 lacs

Crops export in 2019-20

= Rs. (100 + 750 + 301 + 280 + 90)

= Rs. 1521 lacs

% growth = (1521607)607*2*100=75%

New answer posted

8 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Profit made on June

= (320 * 0.093) + (160 * 0.37) = Rs. 88.96 lakhss

which is the highest.

New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

Clearly for the line graph, the change is maximum in June

New answer posted

8 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

The difference between the sum of D1 and D2 dishes is maximum in the month of July. So, with respect to the sum of D1 and D2 dishes least beverages order in month of July.

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