Engineering Entrance Exam
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New answer posted
a year agoContributor-Level 10
IIT Guwahati has released the GATE 2026 syllabus. The syllabus is available on the official website- gate2026.itg.ac.in. As per the updated GATE MTech syllabus 2026, there are no changes are made.
New answer posted
a year agoContributor-Level 10
NIT Jamshedpur cutoff 2024 has been released across various specialisations in opening and closing ranks. NIT Jamshedpur BTech cutoff 2024 ranged between 7097 and 40194 and for the General AI category candidates, wherein BTech in CSE is the most competitive course. The easiest BTech specialisation to secure admission in is B.Tech. in Metallurgical and Materials Engineering. For a detailed NIT Jamshedpur branch-wise cutoff 2024, candidates can refer to the table below for the Round 1 cutoff. The cutoff mentioned below is for the General category under the AI Quota.
New answer posted
a year agoContributor-Level 8
The desired GATE range to get into Sardar Patel Institute of Technology for M.Tech is 50 percent and above. A candidate must appear for GATE/MHTCET MTech exams and qualify in the same. Also, they need to have a minimum of 50% aggregate in their Bachelor's degree. For more information, you are suggested to visit the Shiksha website.
New answer posted
a year agoContributor-Level 8
No, for admission to Sardar Patel Institute of Technology, GATE/MHTCET MTech exams are necessary. A candidate must appear for GATE/MHTCET MTech exams and qualify in the same. Also, they need to have a minimum of 50% aggregate in their Bachelor's degree.
New answer posted
a year agoContributor-Level 10
The NIT Hamirpur JEE Mains Cutoff 2024 was released for Round 1. The Cutoff ranks were released for different courses, across various specialisations. The Cutoff ranks for different courses ranged between 10724 and 40730. The most competitive course for the General AI category candidates was BTech in Computer Science and Engineering, while the least competitive one was BTech in Civil Engineering.
For the OBC AI category candidates, the NIT Hamirpur BTech Cutoff ranged between 4020 and 14215. The most competitive BTech course for the OBC AI category candidates was CSE, while the least competitive one was BTech in Material Science and Eng
New answer posted
a year agoContributor-Level 10
The admission criteria for Computer Science Engineering (CSE) at Silicon Institute of Technology, Bhubaneswar typically involve considering JEE Main ranks, but the cutoff rank can vary each year depending on the number of applicants and available seats. A JEE Common Rank List (CRL) rank of 473105 is relatively high, and it may not meet the cutoff requirements for CSE at Silicon Institute of Technology, which generally have lower cutoff ranks for competitive programs like CSE. It's advisable to check the institute's official website or contact their admissions office directly for the most accurate and up-to-date information regarding ad
New answer posted
a year agoContributor-Level 10
NIT Hamirpur JEE Mains Cutoff 2024 was released for Round 1. The Cutoff was released for different specialisations, across different categories. For the General AI category candidates, the most competitive course was BTech in Computer Science and Engineering, with the closing Cutoff of 10724. The least competitive course for the same was BTech in Civil Engineering, with the Closing rank of 40730.
For the OBC AI category candidates, the NIT Hamirpur BTech Cutoff ranged between 4020 and 14215. The most competitive BTech course for the OBC AI category candidates was Computer Science and Engineering.
Candidates can refer to the t
New answer posted
a year agoContributor-Level 8
Of course, you can take admission at SA Engineering College for B.Tech without the TNEA (Tamil Nadu Engineering Admissions) process. Candidates are admitted based on their eligibility criteria that are set by the college, namely passing the 10+2 (HSC Academic or equivalent) examination with the minimum required aggregate marks in Physics, Chemistry, and Mathematics. For OC, the minimum aggregate mark requirement is 45%.
Moreover, the applicants who have achieved a 10+3 or 12+2 years Diploma or B.Sc. with Mathematics as a major subject can apply also. The minimum aggregate marks requirements in this case differ: 55% for OC, 50% for BC/B
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