JEE

You must fall under the OBC-NCL category, I'm certain. You did pretty well in this category relative to the National Testing Agency's cutoff, which is around 67. This suggests to me that you have a strong Probability of being admitted to CSE. Based on your success in this exam, Shiksha has developed

You must achieve a score higher than the national testing agency's cutoff percentage in order to be admitted to any NIT. Even if you haven't addressed it here, I'm certain you are aware of your percentile. I've included a link created by Shiksha that will forecast the likely college or NIT you'll go

A well-informed estimate or prediction based on a few prior factors might undoubtedly produce positive outcomes. Shiksha has released a college predictor as a service to you. Based on your category and, of course, your test results, this will forecast the college and the branch that you can get. I'v

46 percent has been set by the National Testing Agency as the cutoff for your category. You will only be qualified to apply for admission to any NIT or Central Government-funded institution if your percentile is higher than this. A programme developed by Shiksha can forecast the college you will go

Despite the fact that you haven't explicitly said it this way, I must guess that you did fairly well in the JEE Mains examination. Fortunately for you, the minimum 12th grade point average criteria has been waived for this year's admissions procedure, thus you should be qualified to apply. Hope it's

Student must score in the top 99th percentile to qualify into the computer science branch. It's just a straightforward mathematical computation here. 1 percentile indicates that 1 percent of the students scored higher than you. A percentile of 99 indicates that, out of the 10 lakh students who took

Yes, on August 11th, a student may register for JEE Advanced. Students from India who took the JEE Mains and placed in the top two and a half Lacs candidates are eligible to take the JEE Advanced. You can get all the information you need regarding this exam at the website I've attached. https://www.

It is very difficult to translate % into ranks. This is the case since no one is aware of the number of pupils who fall within a few percentiles of each other or at the same percentile. Only the National Testing Agency has access to all the information, and they will definitely release it soon after