JEE Main
Get insights from 27.4k questions on JEE Main, answered by students, alumni, and experts. You may also ask and answer any question you like about JEE Main
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New question posted
9 months agoNew answer posted
9 months agoContributor-Level 8
NIT Kurukshetra offers admission to various courses on the basis of entrance. Candidates must secure valid scores in accepted entrance exams such as JEE Main for BTech. As the per the Round 6 cutoff 2025, BTech in Computer Science and Engineering rank closed off on 7037, while, BTech+MTech in Computer Science and Engineering closed off at the rank of 7283. Similarly. BTech in Artificial Intelligence and Data Science closed off at the rank of 8510.
New answer posted
9 months ago
Contributor-Level 6
Admission to NIT Patna (CSE) requires closing ranks between 10,529 to 13,706 in JoSAA for general candidates. Since your rank is much higher than that, CSE at any NIT is not attainable in the general category.
General cutoff trends for IIITs (CSE) range from ~15,000–40,000 rank? requiring 97–98+ percentile. So IIITs are also out of reach for CSE with your current rank
New answer posted
9 months ago
Contributor-Level 6
No, with an 83.5 percentile, getting Computer Science & Engineering (CSE) at any NIT is almost impossible.
CSE cutoffs at even lower-tier NITs typically require 97–99+ percentile, and top-tier ones demand 99.2–99.5 percentile
New answer posted
9 months ago
Contributor-Level 8
With a JEE Main percentile of 63.5, your Common Rank List (CRL) rank is likely around 3.2 to 3.4 lakh. At this rank, getting admission into any NIT is highly unlikely, especially in the open (General) category.
New answer posted
9 months ago
Contributor-Level 8
With a JEE Main rank of around 2,57,000, getting admission to HBTU Kanpur (Harcourt Butler Technical University) for B.Tech programs is extremely difficult, especially for core branches like CSE, IT, or AI.
New answer posted
9 months ago
Contributor-Level 8
With 83.2685530 percentile in JEE Main, your chances for B.Tech in Computer Science (CSE) at top NITs, IIITs, or GFTIs are very low, especially for General category. However, you can still get admission into good private colleges, state government colleges, and some lower-ranked GFTIs, depending on your category, home state, and counseling choice.
New answer posted
9 months agoContributor-Level 10
A U-shaped magnet is another type of bar magnet. This is known as a horseshoe magnet since its shapes resembles the object called horseshoe. The two ends of this U-shaped magnet are its magnetic poles. Configration of these magnetic poles creates a concentrated magnetic field. This concentrated magnetic field makes it much more stronger than a simple and straight bar magnet.
New answer posted
9 months agoContributor-Level 10
The two points in a bar magnet are its North pole and South pole. A bar magnet has magnetic field lines around it. These points give these field lines a travelling direction. For example, the magnetic field lines emerge form the North pole of the bar magnet and then they curve toward South pole. This makes a complete loop of magnetic field lines around the bar magnet.
New answer posted
9 months agoContributor-Level 6
You got 58.24 percentile in JEE Mains under SC category.
With this score, it is hard to get Civil Engineering in top NITs.
But you could get admission in a few low-rank GFTIs or private schools.
If you want a higher college, you must put together again and try to rating better within the next JEE try.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 689k Reviews
- 1850k Answers
