

B.E. in Computer Engineering
- A NAAC accredited
- Private Institute
- Estd. 2008
B.E. in Computer Engineering at SITRC Overview
Sandip Institute of Technology and Research Centre offers B.E. in Computer Engineering at UG level. The duration of the course is 4 years. Moreover, the total tuition fee for B.E. in Computer Engineering admission at Sandip Institute of Technology and Research Centre is INR 4,19,212, which is valid for the entire duration of the course. Students can also check the other Sandip Institute of Technology and Research Centre B.E. / B.Tech courses.
Total Tuition Fees | ₹4.19 Lakh Get Fees details |
Duration | 4 years |
Course Level | UG Degree |
Mode of Course | Full Time |
Average package | ₹ 5.00 Lakh |
Official Website | Go to Website |
Seat breakup | 180 |
Type of University | Private |
B.E. in Computer Engineering at SITRC Fees
Students taking admissions in the Sandip Institute of Technology and Research Centre B.E. in Computer Engineering course must pay the fee consisting of several components, such as One-Time Fees, Registration Fees, Exam Fees, and others. There are some additional charges to be paid by students (if applicable). These charges are specific to the institution. The total tuition fees to be paid by students for B.E. in Computer Engineering at Sandip Institute of Technology and Research Centre is INR 4,19,212. More details around Sandip Institute of Technology and Research Centre B.E. in Computer Engineering fees breakup is as follows:
Fee components | Amount (4 years) |
---|---|
Tuition fee is calculated on the basis of 1st year/semester. Actual amount may vary.
Mentioned fee is as per Fee Regulating Authority, Maharashtra State. | ₹ 4.19 Lakh |
₹ 4.19 Lakh |
B.E. in Computer Engineering at SITRC Frequently Asked Questions


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B.E. in Computer Engineering at SITRC Placements
Particulars | Statistics (2021) |
---|---|
Average Salary | INR 5.00 Lakh |
Highest Salary | INR 12.00 Lakh |
Median Salary | INR 1.92 Lakh |
B.E. in Computer Engineering at SITRC Entry Requirements
B.E. in Computer Engineering at SITRC Admission Process
- CounsellingAdmission is through counselling based on the rank obtained in Maharashtra Health and Technical Common Entrance Test (MHTCET). Vacant seats will be filled by the institute based on the rank obtained in JEE-Mains.
Important Dates
B.E. in Computer Engineering at SITRC Cutoffs
JEE Main round-wise cutoff Rank: (General-All India)
Round | 2023 | 2024 | 2025 |
---|---|---|---|
1 | 160527 | 204541 | 215742 |
2 | 175248 | 222122 | 219171 |
3 | 169509 | 186337 | 219580 |
4 | - | - | 180370 |
JEE Main round-wise cutoff Rank: (OBC-All India)
Round | 2021 | 2022 | 2023 |
---|---|---|---|
1 | 274112 | 255212 | 160527 |
2 | 272159 | 166923 | 175248 |
3 | - | - | 169509 |
MHT CET round-wise cutoff Rank: (General-All India)
Round | 2019 | 2020 | 2021 |
---|---|---|---|
1 | 85.54 | 72.12 | 80.23 |
2 | 77.34 | 69.76 | 77.73 |
3 | 80.33 | - | - |
MHT CET round-wise cutoff Rank: (General-Home State)
Round | 2021 | 2022 | 2023 |
---|---|---|---|
1 | 77.36 | 81.97 | 83.44 |
2 | 74.52 | 79.59 | 81.24 |
3 | - | 83.15 | 83.01 |
MHT CET round-wise cutoff Rank: (OBC-All India)
Round | 2019 | 2020 | 2021 |
---|---|---|---|
1 | 80.39 | 70.97 | 76.49 |
2 | 72.58 | 64.68 | 75.44 |
3 | 66.54 | - | - |
MHT CET round-wise cutoff Rank: (OBC-Home State)
Round | 2021 | 2022 | 2023 |
---|---|---|---|
1 | 72.28 | 80.37 | 82.21 |
2 | 72.12 | 79.53 | 80.08 |
3 | - | 81.51 | 81.86 |
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Courses | Eligibility |
---|---|
B.E. / B.Tech | Candidate must have completed Diploma Course in Engineering and Technology in relevant stream with minimum 45% marks (40% marks in case of candidates of Backward class categories and Persons with Disability belonging to Maharashtra State only) from an All India Council for Technical Education or Central or State Government approved Institution or its equivalent. OR Candidate must have completed B.Sc. from UGC/ Association of Indian Universities recognised University with at least 45% marks (40% in case of candidates of Backward class categories and Persons with Disability belonging to Maharashtra State only) and passed 10+2 with Mathematics as a subject. |
M.E./M.Tech | Sponsored candidate must have minimum of two years of full time work experience in a registered firm/ company/ industry/ educational and/ or research institute/ any Government Department or Government Autonomous Organization in the relevant field in which admission is being sought. |
MBA/PGDM | Candidate must have completed minimum three year Bachelor's Degree in any discipline or its equivalent with above mentioned marks (45% in case of candidates of backward class categories and Persons with Disability belonging to Maharashtra State only) from any of the Universities recognised by UGC or AIU. |
Student Forum
Answered 2 years ago
It is better to personally contact Sandip Foundation or consult their official website for their complete admission requirements and cutoff marks to find out if you may get admitted there with a JEE score of 62.45 and a 12th grade score of 83.17%.
The criteria for admission to colleges can change dep
D
Contributor-Level 8
Answered 5 years ago
P
Beginner-Level 1
Answered 9 years ago
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B.E. in Computer Engineering at SITRC News & Updates




B.E. in Computer Engineering at SITRC Contact Information
Sandip Institute of Technology & Research Center, Trimbak Road
Nashik ( Maharashtra)
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Can I get admission in Sandip Foundation with a JEE score of 62.45 and 12th score of 83.17%?