

Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT)
- B+ NAAC accredited
- Public/Government University
- Estd. 1946
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Overview
JNTUK Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) is of 2 years duration. It is a PG level programme offered in a Full Time mode. The total tuition fee for the entire course duration is INR 2,60,000. This fee is as per the official website/sanctioning body but is still subject to revision. Candidates seeking admission are advised to check eligibility requirements before form filling. JNTUK admits 50 students to the course.
Total Tuition Fees | ₹2.60 Lakh Get Fees details |
Duration | 2 years |
Course Level | PG Degree |
Mode of Course | Full Time |
Official Website | Go to Website |
Seat breakup | 50 |
Type of University | Public/Government |
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Fees
For enrollment to JNTUK courses, candidates need to pay the admission fee amount or the first-semester fee. The total fee for Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK further is cumulative of multiple components, such as caution money, tuition fee, etc. These components are either one-time chargeable or have to be paid as per the payment frequency set by the institution. The JNTUK Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) fee breakup can be checked from below table:
| Fee components | Amount (2 years) |
|---|---|
Those who get direct admission into the MSIT main program should pay a non- refundable admission fee of Rs. 30,000/- (part of the annual fee) at the time of counseling. | ₹ 2.60 Lakh |
₹ 2.60 Lakh |
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Rankings
| Rank | Rank Publisher |
|---|---|
| #120 |
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Highlights
- The program is offered by “Consortium of Institutions of Higher Learning” (CIHL) in collaboration with Carnegie Mellon University (CMU), USA.
- Specializations in Computer Networks, E-Business Technologies, Information Security, Software Engineering And Data Analytics & Data Visualization
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Students Ratings & Reviews
- 2-31
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Frequently Asked Questions
The total tuition fee for BTech courses at Jawaharlal Nehru Technological University ranges from INR 30,000 -INR 7.2 lakh. Candidates also have to pay tutition fee and hostel fee. Note: This information is sourced from official website/ sanctioning body and is subject to change.
The total tuition fee for BTech courses at NTU, Kakinada ranges from INR 30,000-INR 7.2 lakh. Candidates also have to pay tutition fee and hostel fee. Note: This information is sourced from official website/ sanctioning body and is subject to change.
Jawaharlal Nehru Technological University Kakinada cutoff 2024 which is based Andhra Pradesh EAMCET scores for the BTech admissions was concluded after the release of Round 1 Seat Allotment results. Candidates can check out the JNTUK cutoff 2024 in the table mentioned below for the General category candidates for top courses:
| BTech Specialisation | Cutoff 2024 |
|---|---|
| CSE | 3151 |
| Electronics & Communication Engineering | 1889 |
The total fee for the BTech programme at School of Food Technology JNTU, Kakinada is not given on the official website yet. Students are free to keep visiting the official website of School of Food Technology JNTU, Kakinada for updated information about the course fee.
The last date to apply online at School of Food Technology JNTU, Kakinada is not given on the official website. For last date update, students can keep reaching the official site of the college.
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Placements
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Entry Requirements
Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Admission Process
- Listening Comprehension and counselingCandidates qualifying in walk-in/regular GAT will be called for Stage-II of the entrance test, consisting of Listening Comprehension and counseling. Candidate with valid IELTS or TOEFL score are exempted from Listening Comprehension Exam Candidates qualifying the Listening Comprehension will be called for counseling on the same day.
- Preparatory CourseCandidates qualifying in Listening Comprehension and counseling Stage will be required to join the Preparatory Course for Five weeks.
- Final SelectionCandidates are selected on clearing the Preparatory course.
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Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Students also asked
Jawaharlal Nehru Technological University Kakinada offers admission through EAMCET, ECET, GATE, APICET, and GPAT exams. 70% of the seats are reserved for candidates who qualify for the entrance examination whereas the rest 30% of seats are reserved for the management/NRI quota.
The CGPA provided for a student by JNTUK is the Cumulative grade point for a student’s overall performance throughout all the semesters in a program. The CGPA is calculated by taking into account all the courses undergone by a student in all the semesters of a programme, i.e. CGPA = Σ (Ci X Si) / ΣCi Where Si is the SGPA of the ith semester and Ci is the total number of credits in that semester.
As per the B.Tech (R16) academic regulations of JNTUK, Kakinada, the following is
the procedure for the computation of Cumulative Grade Point Average (CGPA).
SGPA (Si) = Σ (Ci X Gi) / Σ Ci
Where Ci is the number of credits of the ith course and Gi is the grade point
scored by the student in the ith course.
The CGPA is calculated by taking into account all the courses undergone by
a student in all the semesters of a programme, i.e.
CGPA = Σ (Ci X Si) / Σ Ci
Where Si is the SGPA of the ith semester and Ci is the total number of
credits in that semester.
The equivalent percentage can be calculated as per the below formula for the
B.Tech students who obtains their degrees under R16 regulations ie. 2016-17
admitted batch onwards (2017-18 batch onwards for lateral entry scheme).
Equivalent Percentage = (CGPA – 0.75) X 10
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Discontinued (Mar 2022)- Master of Science in Information Technology (MSIT) at JNTUK Contact Information
Pithapuram Road, East Godavari District
Kakinada ( Andhra Pradesh)
(For general query)
(For admission query)
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