
The Compton effect is an effect observed by Arthur Compton in 1993. This effect is a phenomenon when x-rays or gamma rays are scattered on the material with an increase in wavelength. The Compton Effect formula is given as
. The practical applications of the Compton effect are material physics, gamma spectroscopy, and radiotherapy. In this article, we have explained the Compton effect in detail, including the derivation of the Compton effect equation, difference between the Compton effect and the photoelectric effect, with illustrated examples. Students can go through the article to learn about the Compton effect in detail.
Also Check: NCERT Solution for Class 11 and 12
- What is the Compton Effect?
- Compton Effect Derivation
- Difference Between the Compton Effect and Photoelectric Effect
- Derivation of Compton Effect for Class 11
- Illustrated Examples
What is the Compton Effect?
Compton effect can be observed when there is an increase in the wavelength caused by the dispersion of x-rays and gamma rays on the material. It was discovered by Arthur Compton in 1922.
The mathematical equation of the Compton effect is:
Here, Ө is the angle of radiation;
m0 is the mass of an electron;
h/m0c is the wavelength;
λs and λ0 are the peaks of the radiation spectrum.
Compton Effect Derivation
The derivation of the Compton equation is as follows:
The energy of the photon is hv0
Photon’s momentum is pi = hν0/c
Momentum conservation in x direction = pi = pf cos Θ + pe cos ϕ,
Momentum’s conservation in y direction = 0 = −pf sin Θ + pe sin ϕ.
p2e = p2e (cos2 ϕ + sin2 ϕ) = (pi − pf cos Θ) 2 + p2f sin2 Θ
= p2i + p2f − 2pi pfcos Θ hν0 + m0 c2 = hν + (√m20 c4 + p2 ec2)
m20 c4 + p2 ec2 = (hν0 – hν + m0c2)2
= (hν0 − hν)2 + m20 c4 + 2m0 c2 (hν0−hν)
p2ec2 = (hν0 − hν)2 + 2m0 c2 (hν0−hν)
p2ic2 + p2fc2 − 2pipf cos Θ c2= (hν0 − hν)2 + 2m0c2 (hν0 − hν)
hνν0 (1−cosΘ) = m0c2 (ν0−ν) ∴ λs − λ0 = hm0c (1 − cosΘ)
The step-by-step representation of the Compton effect’s derivation is illustrated above, and the wavelength of an electron is h/moc = λc.
Difference Between the Compton Effect and Photoelectric Effect
Compton effect is observed when there is an increase in the wavelength caused by the dispersion of x-rays and gamma rays on the material of the substance. The incident photon is lower than the wavelength of the photon scattered in the electron. Free electron’s energy is associated with the mid-energy.
On the other hand, the photoelectric effect is a weak bond of electrons released from the material’s surface; it occurs when the electromagnetic radiations and electrons interact with each other. The effect of photoelectric was explained by Albert Einstein. The energy here is low-energy, and the wavelength is not observed when photons disappear with electrons’ interaction.
Derivation of Compton Effect for Class 11
The chapter ‘Rotational Motion’ holds a weightage of 5 marks, consisting of two short questions. The first short question is of 2 marks and the second short question contains 3 marks.
Illustrated Examples
1. Define Compton Shift.
The shift in the scattered wavelength defines the Compton shift.
2. What does the Compton shift depend upon?
It depends upon the angle of scattering.
3.Give one example of non-mechanical waves.
Electromagnetic waves don’t require any medium for propagation, so they’re known as non-mechanical waves.
FAQs on Derivation of Compton effect
Q: What’s the mathematical equation for the Compton effect?
A: The mathematical equation of the Compton effect is:
λs−λ0=h/m0c (1−cosΘ).
Q: What’s the wavelength of an electron?
A: The wavelength of an electron is h/moc = λc.
Q: Who discovered the Compton effect and when?
A: Arthur Compton, in the year 1922, discovered the Compton effect. During his discovery of the effect, he found out that the intensity of incident radiation and wavelength are not dependent upon each other.
Q: How do you calculate a photon’s momentum in the Compton effect?
A: Photon’s momentum can be calculated using this equation 🡪 Pi=hν0/c.
Q: How do you calculate the momentum’s conservation in both the X and Y direction/axis?
A: You can calculate the momentum’s conversion in both directions in the following way –
- Momentum conservation in x direction = pi = pf cos Θ + pe cos ϕ
- Momentum’s conservation in y direction = 0 = −pf sin Θ + pe sin ϕ
Physics Motion Exam
Student Forum
Other Topics under this Chapter
- Rotation and Revolution
- Uniform and Non Uniform Motion
- Derivation of Centripetal Acceleration
- Derivation of Escape Velocity
- Drift Velocity Derivation
- Hubbles Law
- Kinematics of Machines
- Kinematics Equations of Motion
- Derivation of Compton Effect
- Derive Equation of Motion by Calculus method
- Terminal Velocity derivation
- Centripetal and Centrifugal Force
Other Class 11th Physics Chapters
- Physics Mechanical Properties of Solids
- NCERT Class 11 Physics
- NCERT Class 11 Notes
- NCERT Notes
- Physics Motion in Plane
- Physics Mechanical Properties of Fluids
- Physics Motion in Straight Line
- Physics System of Particles and Rotational Motion
- Physics Oscillations
- Physics Waves
- Physics Thermal Properties of Matter
- Physics Motion
- Physics Gravitation
- Physics Thermodynamics
- Physics Work, Energy and Power
- Physics Units and Measurement
- Physics Laws of Motion
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