NCERT Solutions for Class 11 Chemistry Chapter 5 States of Matter: Download Questions & Answers PDF

Chemistry Ncert Solutions Class 11th 2023

Vishal Baghel
Updated on Mar 18, 2025 12:22 IST

By Vishal Baghel, Executive Content Operations

States of Matter is an important chapter in Class 11 NCERT chemistry. In this chapter students will learn about the three states of matter, Solid, Liquid and Gases. This chapter includes various properties of states of matter, the properties of changes when matter flows from one state to the other, type of bonding, melting and boiling points, role of gas laws in elucidating the concept of the molecule, intermolecular interactions.

Laws of matter combining forces like Boyle’s law, Charles’ law, Gay Lussac’s law, Avogadro’s law, ideal behavior, empirical derivation of gas equation, Avogadro’s number, ideal gas equation, deviation from ideal behavior, liquefaction of gases, critical temperature is also studied in the chapter, states of matter. We provide accurate solutions of NCERT Class 11 Chemistry chapters. Students can also refer to NCERT Solutions Chemistry class 12.

 

 

Table of content
  • Class 11 Some Basic Concepts of Chemistry: Key Topics, and Weightage and Important Formulae
  • State of Matter Solution
Chemistry Ncert Solutions Class 11th Logo

Class 11 Some Basic Concepts of Chemistry: Key Topics, and Weightage and Important Formulae

Class 11 Some Basic Concepts of Chemistry: Key Topics, and Weightage and Important Formulae

Chemistry Ncert Solutions Class 11th Logo

State of Matter Solution

5.1. What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?

Answer: Initial Pressure, P1 = 1 bar                           Final Pressure, P2 =?      

               Initial Volume, V1= 500 dm3                       Final Volume, V2=200 dm3
As the value of temperature constant (=30°C)
                  P1V1=P2V2
1 bar x 500 dm3 = P2 x 200 dm3 

Or                   P2=500/200 bar

                           =2.5 bar

 

= mRT/MV

Replacing m/V by d (i.e. density), we get

                            P = dRT/M

    P ∝ d

Hence, at a given temperature, the density of a gas is directly proportional to its pressure.
5.4. At 0°C, the density of a gaseous oxide at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide?

Answer: Using the expression, d =MP/RT, at 0°C

Since, the same compound is under observation, so their densities will be same.              

Therefore,                           M1P1 = M2P2 
                                          5.2. A vessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35°C. What would be its pressure?                                                                                      
Answer:  V1= 120 mL                                                P1=1.2 bar,
                V2 = 180 mL                                               P2 =?
As temperature remains constant, P1V1 = P2V2
                                 (1.2 bar) (120 mL) = P2 (180mL)

Or                                                        P2 = 1.2 x 120 / 180 = 0.8 bar

5.3. Using the equation of state PV= nRT, show that at a given temperature, density of a gas is proportional to the gas pressure P.

Answer: According to ideal gas equation
                        PV = nRT

Or                        P= nRT/V

Replacing n by m/M, we get

                            P M1 x 2 = 28 x 5(Molecular mass of N2 = 28 g/mol)
or                                             M1 = 70 g/mol

Q&A Icon
Commonly asked questions
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MCQs:

5.28. The average kinetic energy of the gas molecule is

(a) Inversely proportional to its absolute temperature

(b) Directly proportional to its absolute temperature

(c) Equal to the square of its absolute temperature

(d) All of the above

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5.29. At constant temperature, the pressure of the gas is reduced to one-third, the volume

(a) Reduce to one-third

(b) Increases by three times

(c) Remaining the same

(d) Cannot be predicted

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5.32. Which of the following gases will have the lowest rate of diffusion?

(a) H2

(b) N2

(c) F2

(d) O2

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5.10. 34.05 mL of phosphorus vapour weighs 0.0625 g at 546°C and 1.0 bar pressure. What is the molar mass of phosphorus?

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5.30. With rise in temperature, the surface tension of a liquid

(a) Decreases 

(b) Increases

(c) Remaining the same

(d) None of the above

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5.1. What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?

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5.42.  State and explain Dalton’s law of partial pressures. Can we apply Dalton’s law of partial pressures to a mixture of carbon monoxide and oxygen?

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5.17. Calculate the volume occupied by 8.8 g of CO2 at 31.1 °C and 1 bar pressure. R = 0.083 bar LK-1 mol-1

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5.13. Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

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5.6. The drain cleaner, Drainex contains small bits of aluminium which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20 °C and one bar will be released when 0.15g of aluminium reacts?

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5.37. What is the effect of temperature on (i) surface tension and (ii) Viscosity?

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5.39. Why liquids diffuse slowly as compared to gases?

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5.40. (a) What do you mean by Surface Tension of a liquid?

(b) Explain the factors which can affect the surface tension of a liquid.

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5.18. 2.9 g of a gas at 95°C occupied the same volume as 0.184 g of hydrogen at 17°C at the same pressure. What is the molar mass of the gas?

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5.35. What is critical temperature?

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5.7. What will be the pressure exerted by a mixture of 3.2g of methane and 4.4g of carbon dioxide contained in a 9 dm3 flask at 27 °C?

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5.12. Calculate the temperature of 4.0 moles of a gas occupying 5 dm3 at 3.32 bar (R = 0.083 bar dm3 K-1 mol-1).

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5.14. How much time would it take to distribute one Avogadro number of wheat grains if 1010 grains are distributed each second?

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Assertion and Reason:

Directions:

(a) Assertion and reason both are correct statements and reason is correct explanation for assertion.

(b) Assertion and reason both are correct statements but reason is not correct explanation for assertion.

(c) Assertion is correct statement but reason is wrong statement.

(d) Assertion is wrong statement but reason is correct statement.

5.23. Assertion: The dipole-dipole interactionbetween two HCl moleculesis stronger than the London forces.

Reason: Only partial charges are involved

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5.26. Assertion: Intermolecular interactions may hold the closely and slowly moving molecules together and thus the solid liquifies.

Reason: Compression brings the molecules in close vicinity and cooling slows down the movement of molecules.

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5.19. A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.   

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5.31. Viscosity of a liquid is a measure of

(a) Repulsive forces between the liquid molecules

(b) Frictional resistance

(c) Intermolecular forces between the molecules

(d) None of the above

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5.15. Calculate the total pressure in a mixture of 8g of oxygen and 4g of hydrogen confined in a vessel of l dm3 at 27°C. R = 0.083 bar dm3 K-1 mol-1.    

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5.16. Pay load is defined as the difference between the mass of the displaced air and the mass of the balloon. Calculate the pay load when a balloon of radius 10 m, mass 100 kg is filled with helium at 1.66 bar at 27°C (Density of air = 1.2 kg m-3 and R = 0.083 bar dm3 K-1 mol-1).

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5.3. Using the equation of state PV= nRT, show that at a given temperature, density of a gas is proportional to the gas pressure P.

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5.8. What will be the pressure of the gas mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in all vessel at 27 °C?

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5.36. Define Avogadro law, Dalton’s law, Boyle’s law and Charles’ law.

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5.22. Critical temperature for CO2 and CH4 are 31.1°C and -81.9°C respectively. Which of these has stronger intermolecular forces and why?

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5.27. Assertion: At high altitudes, liquids boil at lower temperatures in comparison to that at sea level.

Reason: At high altitudes atmospheric pressure is high.

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5.21. In terms of Charles’ law explain why -273°C is the lowest possible temperature.

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5.24. Assertion: Viscosity of liquids decreases as the temperature rises.

Reason: Molecules of liquids are held together by attractive intermolecular forces.

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5.25. Assertion: Liquids and solids are hard to compress.

Reason: Magnitude of the repulsion rises very rapidly as the distance separating the molecules decreases.

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5.34. Define boiling point of a liquid.

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5.33. Liquids can assume the shape of the container. Explain how?

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5.38. What is Boyle Temperature?

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5.41. What are ideal and real gases? Out of CO2 and NH3 gases, which is expected to show more deviation from the ideal gas behaviour.

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5.20. What would be the SI unit for the quantity PV2T2/n?

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5.5. Pressure of l g of an ideal gas A at 27°C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature, the pressure becomes 3 bar. Find the relationship between their molecular masses.

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