

M.Des. in Industrial Design
- Public/Government Institute
- Estd. 1847
M.Des. in Industrial Design at IIT Roorkee Overview
IIT Roorkee - Indian Institute of Technology offers 2 years M.Des. in Industrial Design programme at the PG level. The total course fee for this programme is INR 20,000. The fee structure is inclusive of multiple components such as tuition fees, hostel fees and one-time payments. The hostel fee is INR 1,39,200 and one-time payment of INR 9,000. Check M.Des. in Industrial Design details below:
Total Tuition Fees | ₹20,000 Get Fees details |
Duration | 2 years |
Course Level | PG Degree |
Mode of Course | Full Time |
Official Website | Go to Website |
Type of University | Public/Government,Autonomous |
M.Des. in Industrial Design at IIT Roorkee Fees
Students taking admissions in the IIT Roorkee - Indian Institute of Technology M.Des. in Industrial Design course must pay the fee consisting of components, namely One-Time Fees, Registration Fees, Exam Fees, and others. There are some additional charges to be paid by students (if applicable). These charges are specific to the institution. The total tuition fees to be paid by students for M.Des. in Industrial Design at IIT Roorkee - Indian Institute of Technology is INR 20,000. More details around IIT Roorkee - Indian Institute of Technology M.Des. in Industrial Design fees breakup is as follows:
| Fee components | Amount (2 years) |
|---|---|
The mentioned fees is for general category and for Sponsored candidates the fees is Rs. 100000 | ₹ 20,000 |
The fees might include components other than hostel fees.Meal Plan is included in mentioned fee. Mess advance is included in the mentioned fee. | ₹ 1.46 Lakh |
One time payment includes onetime payments at the time of admission, Caution Deposit and Library Fee | ₹ 9,000 |
₹ 1.75 Lakh |
M.Des. in Industrial Design at IIT Roorkee Frequently Asked Questions
IIT Roorkee MDes cutoff 2024 is based on CEED scores 2024 followed by the round-wise CEED Counselling. IIT Roorkee CEED cutoff 2024 is out for Part A. The mean and standard deviation for CEED 2024 Part A are 41.90 and 16.72, respectively. Refer to the table given below to check out the CEED Part A cutoff 2024 for IIT Roorkee.
| Cutoff Type | CEED Cutoff 2024 |
|---|---|
| Mean | 41.90 |
| Standard Deviation | 16.72 |
According to media reports, the highest package offered during IIT Roorkee placements 2024 as compared with 2023 and 2022 are presented below:
Particulars | Placement Statistics (2022) | Placement Statistics (2023) | Placement Statistics (2024) |
|---|---|---|---|
Highest domestic package | INR 2.15 crore per annum | INR 1.30 crore per annum | NA |
Highest international package | INR 2.15 crore per annum | INR 1.06 crore per annum | INR 2.05 Crore per Annum |
DOMS IIT Roorkee accepts CAT score for admission to MBA programme. Hence, applicants cannot get a seat in MBA without CAT. Besides, the selection for PhD course is based on UGC NET, CSIR NET, GATE, etc. Aspirants applying for PhD do not require a CAT score. So, the requirement will depend on the course opted by the candidates.
DOMS IIT Roorkee offers postgraduate and PhD programmes in Management. The institute offers a two-year residential MBA programme in the specialisations including Marketing, Finance, Information Systems, Operations, Human Resource Management, etc. Candidates scoring above the minimum qualifying CAT cutoff percentile are considered for subsequent selection stages for admission to its flagship MBA programme.
Yes, IIT Roorkee offers good placements to its students. A total of 742 offers were made and 163 companies visited the campus during IIT Roorkee placements 2025 (phase 1). Earlier, the key highlights of IIT Roorkee placements 2024 are presented below:
Particulars | Placement Statistics (2024) |
|---|---|
the highest domestic package | INR 150 LPA |
the highest international package | INR 205 LPA |
Average package | INR 20 LPA (approx.) |
Total offers | 938 |
Total PPOs | 213 |
Total companies visited | 261 |
Particulars | Placement Statistics (2022) | Placement Statistics (2023) | Placement Statistics (2024) |
|---|---|---|---|
the highest package | INR 25.8 LPA | INR 27.94 LPA | INR 26 LPA |
Average package | INR 16.8 LPA | INR 18.34 LPA | INR 18.3 LPA |
Median package | INR 18 LPA | INR 18.09 LPA | INR 18.5 LPA |
Top domain | Product Management | Operations, IT & Analytics | Operations, IT & Analytics |
Download exam sample paper
M.Des. in Industrial Design at IIT Roorkee Placements
| Particulars | Statistics (2024) |
|---|---|
| Median Salary | INR 11.00 Lakh |
M.Des. in Industrial Design at IIT Roorkee Entry Requirements
M.Des. in Industrial Design at IIT Roorkee Admission Process
Important Dates
Explore Courses offered by IIT Roorkee
Get best suited colleges for you in real-time
Tell us about your city, course, budget & more
Discover best colleges that meet all your needs
Compare Courses From Similar Colleges
M.Des. in Industrial Design at IIT Roorkee Students also asked
The minimum marks required in JEE Mains to qualify for JEE Advanced 2026 will be announced with the JEE Main 2026 final result after session 2 exams. Last year's minimum marks in JEE Mains to qualify for JEE Advanced were:
2025:
- Unreserved (UR): 93.1023262
- Gen-EWS: 80.3830119
- OBC-NCL: 79.4313582
- SC: 61.1526933
- ST: 47.9026465
- UR-PwD: 0.0079349
2024:
- General (UR): 93.2362181
- General (UR) PWD: 0.0018700
- Economically Weaker Section (EWS): 81.3266412
- Other Backward Classes (OBC): 79.6757881
- Scheduled Caste (SC): 60.0923182
- Scheduled Tribe (ST): 46.6975840
2023:
- General (UR): 90.7788642
- OBC-NCL: 73.6114227
- SC: 51.9776027
- ST: 37.2348772
- GEN-EWS: 75.6229025
- General (UR) PWD: 0.0013527
Candidates aiming for admission to the Indian Institutes of Technology (IITs) need to meet these cutoff marks in JEE Mains to be eligible for JEE Advanced 2026.
The number of recruiters visited and offers made for top profiles during IIT Roorkee placements 2025 (Phase 1) are presented below:
Profile | Total Recruiters (2025) | Total Offers (2025) |
|---|---|---|
SDE | 60 | 201 |
Core | 37 | 92 |
PM / Consulting | 32 | 114 |
Data Science | 21 | 73 |
Finance | 4 | 14 |
Design | 3 | 1 |
Management | 3 | 18 |
Quant | 2 | 4 |
Education | 1 | 4 |
In case students' rank is not good enough for IIT Roorkee admission to the BTech course, they can consider other IITs with lenient cutoff ranks for admission. For the General AI quota, the JEE Advanced last round cutoff ranks varied between 592 and 8159 for BTech admission at IIT Roorkee. For other IITs, the cutoff range is given below:
| Course Name | Last Round Cutoff 2025 (General AI Quota) |
| IIT Jodhpur | 2918 - 15278 |
| IIT Mandi | 3123 -14879 |
Through JEE Advanced ranks, candidates can secure admission to BTech courses. With regards to the admission, the IIT Roorkee cutoff 2025 has been released for the first round by the institute. The cutoff was released for different categories under the All India quota. For the General AI category candidates, the cutoff ranks varied between 535 and 16596, for different BTech/Integerated BTech/BSc/BArch courses. Among the OBC category candidates, the cutoff ranks varied between 244 and 6237. For the SC AI category candidates, the ranks varied between 121 and 3181. For more information on cutoff for IIT Roorkee, click here.
The table given below records the round 1 cutoff for IIT Roorkee JEE Advanced cutoff 2025 for the General AI category candidates:
| Course | 2025 |
|---|---|
| Bachelor of Architecture (B.Arch.) | 3181 |
| B.Tech. in Chemical Engineering | 1260 |
| B.Tech. in Civil Engineering | 1614 |
| B.Tech. in Electrical Engineering | 572 |
| B.Tech. in Electronics and Communication Engineering | 393 |
| B.Tech. in Computer Science and Engineering | 121 |
| B.Tech. in Mechanical Engineering | 1039 |
| B.Tech. in Metallurgical and Materials Engineering | 1975 |
| B.Tech. in Production and Industrial Engineering | 1712 |
| B.Tech. in Engineering Physics | 1530 |
| Integrated B.Sc. + M.Sc. in Physics | 2171 |
| Integrated M.Tech. in Geophysical Technology | 2486 |
| Integrated M.Tech. in Geological Technology | 2475 |
| B.Tech. Biosciences and Bioengineering | 2142 |
| Integrated B.Sc. + M.Sc. in Economics | 2001 |
| B.Sc. + M.Sc. in Mathematics and Computing | 565 |
| B.Sc. + M.Sc. in Chemical Sciences | 2318 |
| B.Tech. in Data Science and Artificial Intelligence | 208 |
| B.Tech. in Energy Engineering | 1470 |
Student Forum
Answered a year ago
Hello,
The Master of Design programme at IIT Roorkee is aimed at providing an engaging environment to foster creativity and skills through an interdisciplinary process of teaching and training.
MINIMUM ELIGIBILITY CRITERIA
Candidates belonging to General, GEN-EWS and OBC category must have secured at l
A
Beginner-Level 4
Content authored by:
M.Des. in Industrial Design at IIT Roorkee News & Updates




M.Des. in Industrial Design at IIT Roorkee Contact Information
Academic Affairs Office, James Thomason Building
Roorkee ( Uttarakhand)
(For general query)
(For admission query)
(For general query)
(For admission query)
Useful Links
Know more about IIT Roorkee
- All About IIT Roorkee
- Courses 2026
- Fees 2026
- Reviews on Placements, Faculty & Facilities
- Admission 2026 - Cutoffs, Eligibility & Dates
- Placement - Highest & Average Salary Package
- Cut off & Merit List 2026
- IIT Roorkee Rankings
- Gallery 2026
- Infrastructure Details & Reviews
- IIT Roorkee Faculty
- Compare IIT Roorkee
- IIT Roorkee Q&A
- Scholarships
- JEE Advanced
- IIT Roorkee News & Articles


I want to know about the latest cutoff information for M.Des. in Industrial Design at IIT Roorkee.