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Mamona Majumder
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Updated on Sep 23, 2025 23:49 IST

We have provided the previous year JEE Advanced Chemistry question paper. Also, you will find the 14 most difficult questions asked in the past JEE Advanced exam. Check the complete article.

JEE Advanced Chemistry Questions

JEE Advanced Chemistry Questions

JEE Advanced Chemistry Questions: Chemistry is consider to be most easy paper in JEE Advanced. But sometime tricky questions are asked which might be time consuming. Majority of question in JEE Advanced chemistry paper is based on  p-block, Chemical bonding, Coordination compounds, Electrochemistry, Ionic & Chemical Equilibrium, Electrochemistry & Surface Chemistry, Aldehyde & Ketones, Polymers, and Biomolecules.

To master the question based on these topic intense practice is required. Students can solve previous year question for this. In this article we have provided past year JEE Advanced Chemistry questions. Also some tricky questions are provided here.

📎Last 10 Year JEE Advanced Question Paper PDF

  Download Here
Table of content
  • 15 Most Difficult JEE Advanced Chemistry Questions Asked in Previous 10 Years
  • All JEE Advanced Chemistry Questions From Previous Years
  • JEE Advanced Chemistry Section Overview

15 Most Difficult JEE Advanced Chemistry Questions Asked in Previous 10 Years

Check below the most difficult questions in JEE Advanced chemistry in the past 10 years as analysed by the experts:

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Q1: The option(s) with only amphoteric oxides is (are) (JEE Advanced 2020)

  1. NO, B2O, PbO, SnO2 
  2. Cr2O3, CrO, SnO, PbO
  3. Cr2O3, BeO, SnO, SnO2
  4. ZnO, Al2O3, PbO, PbO2

Ans: C and D

Q2: The 1st, 2nd and 3rd ionization enthalpies I1, I2 and I3, of four atoms with atomic numbers n, n + 1, n + 2 and n + 3 where n < 10 are tabulated below. What is the value of n? (JEE Advanced 2020)

Atomic Number Ionization Enthalpies (kJ/mol)
I1 I2 I3
n 1681 3374 6050
n+1 2081 3952 6122
n+2 496 4562 6910
n+3 738 1451 7733

Ans: n=9

Q3: Identify the least stable ion among the following: (JEE Advanced 2022)

  1. Li-
  2. Be-
  3. B-
  4. C-

Ans: B

Q:   How to prepare for Physics, Mathematics and Chemistry for JEE Advanced?
A:

Preparation for JEE Advanced begins by knowing exam syllabus. Every student must follow syllabus. Once preparation is done then start solving previous year questions for self-assessment. This will give an overview of your preparation.

Q:   How to prepare for JEE Mains 2nd attempt as well as JEE Advanced simultaneously also BITSAT and CET at the same time?
A:

You can prepare for all entrance tests at same time. It is a tough task but not impossible. For this a proper strategy is required. Here are some important tips. 

  • Compare the syllabus: All engineering entrance exams have almost the same syllabus. There might be some additional topics in some exams. The aspirant must study the syllabus for all exams and find out the topics that are extra, and prepare those separately. Almost 90% of the topics will be common for all entrance exams, and hence, syllabus completion for one exam will lead to completion of the syllabus for all the exams.
  • Prepare for JEE Mains and incorporate the preparation for all other exams: Apart from JEE Advanced, all the exams are pretty straightforward for a well-prepared candidate. JEE Advanced require a higher level of preparation as the questions are multi-conceptual. However, the state-level entrance exams, and exams like BITSAT, VITEEE, etc., have direct questions. Most of the questions in JEE Mains are also direct and require the application of basic concepts. Hence, the candidates must prepare for one exam, like JEE Mains, that will cover their preparation for all other exams.
  • JEE Advanced needs extra effort: For JEE Advanced candidates must focus on time management and building exam day temperament. Learn how to apply multiple concepts to a question.

The bottom line is to prepare for JEE Mains to cover the preparation for all other CETs and exams like BITSAT and VITEEE. For JEE Advanced, work on sharpening your skills of time management, stress handling, multiple concept application, speed and accuracy.

Q:   What has been the highest score in JEE Advanced till date?
A:

So far no student has ever scored full marks in JEE Advanced signifies exam's difficulty level. Highest marks one has achieved to date in JEE Advanced are 355 marks out of 360. Ved Lahoti scored these marks in 2024.

Q4: identify the correct order of acidic strength of CO2, CuO, CaO, H2O (JEE Advanced 2022)

  1. CaO < CuO < H2O < CO2
  2. H2O < CuO < CaO < CO2
  3. CaO < H2O < CuO < CO2
  4. H2O < CO2 < CaO < CuO

Ans: A

Q5: Among the following, the number of elements showing only one  non-zero oxidation state is: (JEE Advanced 2010)

O, Cl, F, N, P, Sn, Tl, Na, Ti

Ans: 2

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Q6: Assuming 2s - 2p mixing is not operative, the paramagnetic species among the following is: (JEE Advanced 2014)

  1. Be2
  2. B2
  3. C2
  4. N2

Ans: C

Q7: If the distribution of the molecular speed of a gas is as per the figure shown below, then the ratio of the most probable, the average and the root mean square speeds, respectively, is: (JEE Advanced 2020)

  1. 1 : 1 : 1
  2. 1 : 1 : 1.224
  3. 1 : 1.128 : 1.224
  4. 1 : 1.128 : 1

Ans: B

Q:   Where can I check the JEE Advanced rank list?
A:

There is no seperate rank list released for JEE Advanced. The rank of the candidates in All India category and in the respective category of the candidate is meantioned on the result itslef.

Q:   What is a safe score for JEE Advanced exam?
A:

As per the analysis of the previous year data, the candidates belonging to general category must aim to score around 180 marks out of 360 to qualify the exam. 180+ marks will be a safe zone and will ensure that you pass the exam for IIT admissions. However, note that this marks will not get you a good rank and hence tier 1 IITs (IIT B, IIT M, IIT D) and courses will be out of reach.

Q8: 1 mol of a monoatomic real gas satisfies the equation p(V-b) = RT where, b is a constant. The relationship of interatomic potential V(r) and interatomic distance for as is given by: (JEE Advanced 2015)

Ans: C

Q9: The treatment of an aqueous solution of 3.74 g of Cu(NO3)2 with excess Kl results in a brown solution along with the formation of a precipitate. Passing H2S through this brown solution gives another precipitate X. The amount of X (in g) is ______________ ? (JEE Advanced 2022, paper 1)
[Given: Atomic mass of H = 1, N=14, O = 16, S = 32, K = 39, Cu = 63, I = 127]

Ans: 0.32

Q10: For the given close packed structure of a salt made of cation X and anion Y shown below (ions of only one face are shown for clarity), the packing fraction is approximately: (JEE Advanced 2021, paper 1)

(packing fraction = packing efficiency ÷ 100)

  1. 0.74
  2. 0.63
  3. 0.52
  4. 0.48

Ans: 0.63

Q11: The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y x 10-2 °C.

(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely. Use: Molal elevation constant (Ebullioscopic Constant), K = 0.5 K kg mol-1; Boiling point of pure water as 100°C).

The value of lyl is__________ (JEE Advanced 2021, paper 1)

Ans: 2.5

Q12: In a bimolecular reaction, the steric factor P was experimentally determined to be 4.5. The correct option(s) among the following is(are) (JEE Advanced 2017, paper 2)

  1. The activation energy of the reaction is unaffected by the value of the steric factor
  2. Experimentally determined value of frequency factor is higher than that predicted by Arrhenius equation
  3. Since P= 4.5, the reaction will not proceed unless an effective catalyst is used
  4. The value of the frequency factor predicted by the Arrhenius equation is higher than that determined experimentally

Ans: A and B

Q13: The decomposition reaction 2N2O5 (g) → 2N2O4 (g) + O2(g) is started in a closed cylinder under Isothermal isochoric condition at an initial pressure of 1 atm. After Y x 103 s, the pressure inside the cylinder is found to be 1.45 atm. If the rate constant of the reaction is 5 x 10-4 S-1, assuming ideal gas behaviour, the value of Y is___________ (JEE Advanced 2019, paper 2)

Ans: 2.30

Q14: Consider a Helium (He) atom that absorbs a photon of wavelength 330 nm. The change in velocity (in cm s-1) of the He atom after the photon absorption is ______________

(Assume momentum is conserved when photon is absorbed. Use Planck constant = 6.5 X 10-13 J s, Avogadro number = 6 X 1023 mol-1, Molar mass of He = 4 m mol-1) (JEE Advanced 2021)

Ans: 30 cm/s

Q15: The atomic masses of He and Ne are 4 and 20 a.m.u., respectively. The value of the de Broglie wavelength of He gas at -73°C is "M" times that of the de Broglie wavelength of Ne at 727°C. M is - (JEE Advanced 2013)

Ans: 5

Also Read:

All JEE Advanced Chemistry Questions From Previous Years

Above we curated and provided you the most difficult questions in JEE Advanced Chemistry over the past 10 years. However, candidates who wish to have all the previous year JEE Advanced Chemistry questions for practice, can download the PDF files below:

JEE Advanced Chemistry Questions with Solutions 2024 to 2019:

Check below the JEE Advanced Chemistry questions with solutions PDF:

Year

JEE Advanced Chemistry questions with solutions

2024

Paper 1 -  Download here

Paper 2 -  Download here

2023

Paper 1 -  Download here

Paper 2 -  Download here

2022

Paper 1 - Download here

Paper 2 - Download here

2021

Paper 1 - Download here

Paper 2 - Download here

2020

Paper 1 - Download here

Paper 2 - Download here

2019

Paper 1 - Download here

Paper 2 - Download here

Also Check:

JEE Advanced Physics Questions JEE Advanced Maths Questions

JEE Advanced Chemistry Section Overview

Check below the details regarding the JEE Advanced Chemistry section in JEE Advanced question paper followed in the past 2 years:

Total Marks in JEE Advanced Chemistry section: 120

  • 60 marks in JEE Advanced paper 1
  • 60 marks in JEE Advanced paper 2

In each paper of JEE Advanced, the Chemistry section has the following sections:

  • Sec-I (Max. marks-12)
  • Sec-II (Max. Marks-12)
  • Sec-III (Max. marks-24)
  • Sec-IV (Max. marks-12)

Number of questions and marks distribution in each of the sections is as follows:

Section

Number of questions and total marks

Marking Scheme

1

4 questions of 12 marks

  • +3 If ONLY the correct option is chosen
  • 0 If none of the options is chosen (i.e. the question is unanswered)
  • -1 in all other cases

2

3 questions of 12 marks

  • +4 ONLY if (all) the correct option(s) is(are) chosen
  • +3 If all four options are correct but ONLY three options are chosen
  • +2 If three or more options are correct but ONLY two options are chosen, both of
    which are correct
  • +1 If two or more options are correct but ONLY one option is chosen and it is a
    correct option
  • 0 If none of the options is chosen (i.e. the question is unanswered)
  • -2 In all other cases

3

6 questions of 24 marks

  • +4 for the correct answer
  • 0 for no attempts

4

4 questions of 12 marks

  • +3 If ONLY the correct option is chosen
  • 0 If none of the options is chosen (i.e. the question is unanswered)
  • -1 for the wrong attempts

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Mamona Majumder
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Expertise: Engineering Education and Counselling

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