The National Testing Agency (NTA) will announce JEE Main 2026 Result in the form of percentile score. NTA uses the normalization formula to calculate the JEE Main percentile score of candidates. JEE Main percentile and normalization formula used by NTA (National Testing Agency) is provided here. To determine JEE Main 2026 results and rank list, NTA will adopt the process of normalization which is based on percentile calculation. The rank list of JEE Main 2026 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
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Predict JEE Main Colleges- How To Calculate JEE Main 2026 Percentile Score
- Key Terms For Calculating JEE Main 2026 Percentile Score
- Highlights of JEE Main 2026 Percentile Score
- JEE Main 2026 Tie Breaker Rules
- Normalization Process To Prepare JEE Main 2026 Ranklist
- Read Important FAQs Here
How To Calculate JEE Main 2026 Percentile Score
NTA uses the given below formula to calculate the percentile score of a candidate
Key Terms For Calculating JEE Main 2026 Percentile Score
Before we delve deeper into how will NTA calculate the JEE Main 2026 Percentile Score through the Normalisation Process, there are some key terms you should know.
| Key terms |
What they mean |
|---|---|
| Percentile/ Percentile Score |
Percentile Score is the score based on the relative performance of candidates who have appeared for the exam. To calculate a percentile score, the marks secured are converted into a scale ranging from 100 to 0 for each session of examinees. NOTE: Percentile score is not the same as the percentage of marks secured. |
| Normalisation |
It is the practice of comparing candidates' scores who appeared in different shifts of the exam. The normalization process will be similar to the ones currently being adopted for other national level competitive exams like CAT. |
| Highest Raw Score and Percentile Score |
All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session. |
| Lowest Raw Score and Percentile Score |
Percentile Score of all the lowest raw scores is different. In this case, the percentile score will depend on the total number of candidates who have taken the examination for their respective sessions. |
Highlights of JEE Main 2026 Percentile Score
- JEE Main percentile score is the normalized score for the exam and not the raw marks of the test taker.
- The percentile score specifies the percentage of candidates who have scored equal to below (raw scores) a particular percentile in JEE Main. Thus, the topper of each session of JEE Main will get the same percentile i.e. 100.
- Percentiles will also be calculated and converted for marks obtained in between the highest and lowest scores
- The percentile score will be used to prepare the JEE Main merit list
- The percentile scores for JEE Main will be calculated up to 7 decimal places to reduce tie-breaking scenarios and avoid the bunching effect
- The overall percentile is not the aggregate of the percentile of the individual subject
To help you understand how the agency will calculate JEE Main percentile score, here’s an example.
Example: In 2026, JEE Main was held in two sessions of test-takers where the days and shifts were allotted randomly to candidates.
- Session-1: Day-1 Shift-1
- Session-2: Day-1 Shift-2
The JEE Main test takers were distributed in the following manner:
| Distribution of candidates |
||||||
|---|---|---|---|---|---|---|
| Session |
Day/Shift |
No of Candidates |
|
Marks |
|
|
| Absent |
Appeared |
Total |
Highest |
Lowest |
||
| Session-1 |
Day-1 Shift-1 |
3974 |
28012 |
31986 |
335 |
-39 |
| Session-2 |
Day-1 Shift-2 |
6189 |
32541 |
38730 |
346 |
-38 |
| Total (Session-1 to Session-4) |
25273 |
142482 |
167755 |
346 |
-49 |
|
The above example of the distribution of candidates, the method to calculate the Highest Raw Score in each paper will be normalized to 100, thus indicating that 100% of candidates have obtained scores that are equal to or lesser than the highest scorer/ topper for that session.
Example: Highest Raw Score and Percentile Score
According to the official website of JEE Main, the Percentile Score of all the lowest raw scores will be different and will be based on the total number of test-takers for their respective sessions.
Highest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Highest Raw Score |
Candidates who scored EQUAL OR LESS THAN Highest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
335 |
28012 |
100.0000000 [(28012/28012)*100] |
| Session-2 |
32541 |
346 |
32541 |
100.0000000 [(32541/32541)*100] |
| Session-3 |
41326 |
331 |
41326 |
100.0000000 [(41326/41326)*100] |
Lowest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Lowest Raw Score |
Candidates who scored EQUAL OR LESS THAN Lowest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
-39 |
1 |
0.0035699 [(1/28012)*100] |
| Session-2 |
32541 |
-38 |
1 |
0.0030730 [(1/32541)*100] |
| Session-3 |
41326 |
-49 |
1 |
0.0024198 [(1/41326)*100] |
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JEE Main 2026 Tie Breaker Rules
NTA resolves tie among students having same total percentile score in the following order
- NTA score in Mathematics
- NTA score in Physics
- NTA score in Chemistry
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Physics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Chemistry in the test
- If there is a tie even after this, candidates will be assigned the same rank.
| JEE Main Result 2026 | JEE Main 2026 Marks vs Percentile |
| JEE Main Question Paper PDF 2026-2013 | JEE Mains Cutoff 2026 |
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Normalization Process To Prepare JEE Main 2026 Ranklist
NTA’s normalization process for the preparation of the JEE Main merit/rank list will comprise of the following steps:
Stage 1: Refers to the conduct of the exam. JEE Main is conducted in two shifts over four days.
Stage 2: Once the examination is over, the results for each session will be prepared using raw scores and percentile scores for each subject.
Stage 3: The third and last step would be the compilation of the NTA score and preparation of JEE Main merit list. Remember, the Final Ranking/ Merit would be prepared only after resolving ties (if any).
To compile JEE Main 2026 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking. Candidates who appear in both the attempts; their best of the two NTA scores will be considered further for the preparation of Merit List /Ranking.
Read Important FAQs Here
Q. What is JEE Main Percentile Score?
A. JEE Main Percentile Score is the score based on the relative performance of candidates who have appeared for the JEE Main entrance exam and it is not the same as the percentage of marks secured.
Q. What is Normalisation in JEE Main?
A. It is the practice of comparing candidates' scores who appeared in different shifts of the JEE Main exam.
Q. What is Highest Raw Score and Percentile Score in JEE Main?
A. It is the practice of comparing candidates' scores who appeared in different shifts of the JEE Main exam.
Q. What is Highest Raw Score and Percentile Score in JEE Main?
A. All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session.
Q. How JEE Main merit list is prepared?
A. The percentile score will be used to prepare JEE Main merit list.
Q. What are the JEE Main 2026 Tie Breaker Rules?
A. In case, where two or more test takers secure equal Percentile Scores in the exam, the inter-se merit will be determined in the following order: Candidates obtaining higher Percentile Score in Mathematics in the Test, their higher Percentile Score in Physics in the Test, higher Percentile Score in Chemistry in the Test and Candidates older in age to be preferred.
Q. How final JEE Main result will be prepared?
A. To compile the final JEE Main 2026 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking.
Q. How JEE Main rank list is prepared?
A. The rank list of JEE Main 2026 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
Q. How will NTA calculate JEE Main 2026 Percentile Score?
A. The National Testing Agency will calculate JEE Main 2026 Percentile Score through the Normalisation Process.
Q. Will NTA release the JEE Main result along with the percentile score?
A. NTA is responsible for releasing JEE Main 2026 result along with the percentile score. To determine JEE Main 2025 results and rank list, NTA adopted the process of normalization which was based on percentile calculation.
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Student Forum
Anything you would want to ask experts?Answered Yesterday
Yes, students can get direct admission, without JEE Main at SR Group of Institutions. The final selection is based on merit/ CUET/ JEE Main exam. Students can also get admission on the basis of academic scores.
G
Contributor-Level 10
Answered 2 days ago
Yes, admissions are possible to the BTech course at DY Patil University, Navi Mumbai without the JEE Main rank through MHT CET. Securing good scores in the MHT CET is very important. Hence, the students must work hard and secure good marks for successful admission to the BTech course.
R
Contributor-Level 10
Answered 2 days ago
Yes, JEE Main is compulsory to take admission in BTech at IIIT Lucknow. Candidates must fulfil the eligibility and apply for JEE Main on the official website of NTA. Applicants must clear the JEE Main cutoff for IIIT Lucknow. They have to particpate in JoSAA/CSAB cousnelling for seat allocation.
R
Contributor-Level 10
Answered 2 days ago
With 77 percentile, getting a seat is possible, but it will depend on the branch and the admission cycle. For highly demanded branches like CSE, the chances are usually quite low at that percentile. But for some core or less competitive branches, there may still be opportunities.
One of my juniors go
A
Beginner-Level 3
Answered 4 days ago
No, candidates cannot take admission in BTech at NIT Uttarakhand without JEE Main. It is the mandatory national-level entrance test for admission through JoSAA/CSAB counselling. Admission is based entirely on your JEE Main Rank and counseling round.
R
Contributor-Level 10
Answered 4 days ago
Yes, JEE Main is enough for Krupanidhi Institute of Technology admission. But it is not the only exam accepted for B.E. The institute also accepts CET and COMEDK score. Hence, even if JEE score is not available, students can still apply for admissions at the institute.
A
Contributor-Level 10
Answered a week ago
The JEE Mains 2026 is not out till now. The data for 2025 is available for BIT Mesra.
As per the recent BIT Mesra JEE Main cutoff 2025, the round 6 results have been released. Based on the final cutoff for the General AI category, BTech in Computer Science and Engineering closed off at the rank of 18
S
Contributor-Level 10
Answered a week ago
If you are OBC candidate then you can
1) Fill JoSSA — try for NIT Manipur/Nagaland/Mizoram in Civil or Mechanical
2) Participate in CSAB — extra chance
3) Don't skip state counselling — OBC quota there can be very beneficial
4) Apply to NSUT/YMCA — placements rival many NITs
A lower branch NIT vs NSUT/YM
S
Beginner-Level 1
Answered a week ago
No, interview round for BSc admission at BIT Mesra is part of BITCHEM which is not required for candidates who are open to pusuing BSc at Birla Institute of Technology, Mesra. Candidates who apply through JEE Main will not be required to appear in BITCHEM.
S
Contributor-Level 10
Answered a week ago
Candidates wishing to take admission in BTech at IIIT Bhagalpur have to appear in JEE Main. Along with that, candidates also have to participate in JOSAA/ CSAB counselling process. Seat allocation is done when candidates clear cutoff ranks released on the official JoSAA website.
R
Contributor-Level 10
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