How to calculate JEE Main 2026 Percentile Score: Know Normalization Process
Joint Entrance Exam (JEE) Main 2026 ( JEE Main )
Exam On - 21 Jan '26 - 30 Jan '26
The National Testing Agency (NTA) will announce JEE Main 2026 Result in the form of percentile score. NTA uses the normalization formula to calculate the JEE Main percentile score of candidates. JEE Main percentile and normalization formula used by NTA (National Testing Agency) is provided here. To determine JEE Main 2026 results and rank list, NTA will adopt the process of normalization which is based on percentile calculation. The rank list of JEE Main 2026 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
Also Check: JEE Main Rank Predictor 2026
| JEE Main Result 2026 | JEE Main 2025 Marks vs Percentile |
| JEE Main Question Paper PDF 2025-2013 | JEE Mains Cutoff 2025 |
Use your JEE Main 2026 Percentile and predict your Rank and the Colleges you are eligible for using Shiksha's JEE Main Rank and College Predictor.Get cut-off information for 600 colleges and 2500 colleges
Predict JEE Main Colleges- How To Calculate JEE Main 2026 Percentile Score
- Key Terms For Calculating JEE Main 2026 Percentile Score
- Highlights of JEE Main 2026 Percentile Score
- JEE Main 2026 Tie Breaker Rules
- Normalization Process To Prepare JEE Main 2026 Ranklist
- Read Important FAQs Here
How To Calculate JEE Main 2026 Percentile Score
NTA uses the given below formula to calculate the percentile score of a candidate
Key Terms For Calculating JEE Main 2026 Percentile Score
Before we delve deeper into how will NTA calculate the JEE Main 2026 Percentile Score through the Normalisation Process, there are some key terms you should know.
| Key terms |
What they mean |
|---|---|
| Percentile/ Percentile Score |
Percentile Score is the score based on the relative performance of candidates who have appeared for the exam. To calculate a percentile score, the marks secured are converted into a scale ranging from 100 to 0 for each session of examinees. NOTE: Percentile score is not the same as the percentage of marks secured. |
| Normalisation |
It is the practice of comparing candidates' scores who appeared in different shifts of the exam. The normalization process will be similar to the ones currently being adopted for other national level competitive exams like CAT. |
| Highest Raw Score and Percentile Score |
All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session. |
| Lowest Raw Score and Percentile Score |
Percentile Score of all the lowest raw scores is different. In this case, the percentile score will depend on the total number of candidates who have taken the examination for their respective sessions. |
Highlights of JEE Main 2026 Percentile Score
- JEE Main percentile score is the normalized score for the exam and not the raw marks of the test taker.
- The percentile score specifies the percentage of candidates who have scored equal to below (raw scores) a particular percentile in JEE Main. Thus, the topper of each session of JEE Main will get the same percentile i.e. 100.
- Percentiles will also be calculated and converted for marks obtained in between the highest and lowest scores
- The percentile score will be used to prepare the JEE Main merit list
- The percentile scores for JEE Main will be calculated up to 7 decimal places to reduce tie-breaking scenarios and avoid the bunching effect
- The overall percentile is not the aggregate of the percentile of the individual subject
To help you understand how the agency will calculate JEE Main percentile score, here’s an example.
Example: In 2024, JEE Main was held in two sessions of test-takers where the days and shifts were allotted randomly to candidates.
- Session-1: Day-1 Shift-1
- Session-2: Day-1 Shift-2
The JEE Main test takers were distributed in the following manner:
| Distribution of candidates |
||||||
|---|---|---|---|---|---|---|
| Session |
Day/Shift |
No of Candidates |
|
Marks |
|
|
| Absent |
Appeared |
Total |
Highest |
Lowest |
||
| Session-1 |
Day-1 Shift-1 |
3974 |
28012 |
31986 |
335 |
-39 |
| Session-2 |
Day-1 Shift-2 |
6189 |
32541 |
38730 |
346 |
-38 |
| Total (Session-1 to Session-4) |
25273 |
142482 |
167755 |
346 |
-49 |
|
The above example of the distribution of candidates, the method to calculate the Highest Raw Score in each paper will be normalized to 100, thus indicating that 100% of candidates have obtained scores that are equal to or lesser than the highest scorer/ topper for that session.
Example: Highest Raw Score and Percentile Score
According to the official website of JEE Main, the Percentile Score of all the lowest raw scores will be different and will be based on the total number of test-takers for their respective sessions.
Highest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Highest Raw Score |
Candidates who scored EQUAL OR LESS THAN Highest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
335 |
28012 |
100.0000000 [(28012/28012)*100] |
| Session-2 |
32541 |
346 |
32541 |
100.0000000 [(32541/32541)*100] |
| Session-3 |
41326 |
331 |
41326 |
100.0000000 [(41326/41326)*100] |
Lowest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Lowest Raw Score |
Candidates who scored EQUAL OR LESS THAN Lowest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
-39 |
1 |
0.0035699 [(1/28012)*100] |
| Session-2 |
32541 |
-38 |
1 |
0.0030730 [(1/32541)*100] |
| Session-3 |
41326 |
-49 |
1 |
0.0024198 [(1/41326)*100] |
NIT Andhra Pradesh BTech admission is based on candidates' performance in the JEE Main entrance exam, followed by the JoSAA counselling process. The Round 1 of JEE Main cutoff 2025 has been released for different categories of students belonging to the AI and HS quotas. For students belonging to the OBC category, the JEE Main closing ranks ranged between 5741 and 14452. For branch-wise Round 1 cutoff details, check out the table below:
| Course | JEE Main Round 1 Cutoff 2025 (OBC AI Quota) |
|---|---|
| B.Tech. in Biotechnology | 14191 |
| B.Tech. in Chemical Engineering | 13555 |
| B.Tech. in Civil Engineering | 14452 |
| B.Tech. in Computer Science and Engineering | 5741 |
| B.Tech. in Electrical and Electronics Engineering | 10155 |
| B.Tech. in Electronics and Communication Engineering | 7400 |
| B.Tech. in Mechanical Engineering | 12259 |
| B.Tech. in Metallurgical and Materials Engineering | 14368 |
The National Testing Agency (NTA) will declare the JEE Mains result 2026 in the form of percentile scores. Candidates can check here the previous year JEE Main marks vs percentile data to understand how much is 120 marks in JEE Main percentile.
As per the last year JEE Main marks vs percentile analysis, 120 marks would be around 95 to 97 percentile. However, the exact JEE Main 2025 percentile marks 120 would vary depending upon the highest number scored by the candidate in a particula shift and the total number candidates appeared in that particular shift.
JEE Main 2026 Tie Breaker Rules
NTA resolves tie among students having same total percentile score in the following order
- NTA score in Mathematics
- NTA score in Physics
- NTA score in Chemistry
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Physics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Chemistry in the test
- If there is a tie even after this, candidates will be assigned the same rank.
Normalization Process To Prepare JEE Main 2026 Ranklist
NTA’s normalization process for the preparation of the JEE Main merit/rank list will comprise of the following steps:
Stage 1: Refers to the conduct of the exam. JEE Main is conducted in two shifts over four days.
Stage 2: Once the examination is over, the results for each session will be prepared using raw scores and percentile scores for each subject.
Stage 3: The third and last step would be the compilation of the NTA score and preparation of JEE Main merit list. Remember, the Final Ranking/ Merit would be prepared only after resolving ties (if any).
To compile JEE Main 2026 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking. Candidates who appear in both the attempts; their best of the two NTA scores will be considered further for the preparation of Merit List /Ranking.
Candidates who do not score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
The cutoff for NITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC, ST candidates. Candidates can check the previous year JEE Main cutoff below for some top NITs and branches. For detailed cutoff report, candidates can check Shiksha page.
- MNNIT Allahabad CSE Closing Rank Open Category: 5627 (Home State)
- MNNIT Allahabad CSE Closing Rank Open Category: 4254 (Open)
- MNIT Jaipur CSE Closing Rank Open Category: 5610 (Home State)
- MNIT Jaipur CSE Closing Rank Open Category: 4631 (Open)
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Read Important FAQs Here
Q. What is JEE Main Percentile Score?
A. JEE Main Percentile Score is the score based on the relative performance of candidates who have appeared for the JEE Main entrance exam and it is not the same as the percentage of marks secured.
Q. What is Normalisation in JEE Main?
A. It is the practice of comparing candidates' scores who appeared in different shifts of the JEE Main exam.
Q. What is Highest Raw Score and Percentile Score in JEE Main?
A. It is the practice of comparing candidates' scores who appeared in different shifts of the JEE Main exam.
Q. What is Highest Raw Score and Percentile Score in JEE Main?
A. All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session.
Q. How JEE Main merit list is prepared?
A. The percentile score will be used to prepare JEE Main merit list.
Q. What are the JEE Main 2026 Tie Breaker Rules?
A. In case, where two or more test takers secure equal Percentile Scores in the exam, the inter-se merit will be determined in the following order: Candidates obtaining higher Percentile Score in Mathematics in the Test, their higher Percentile Score in Physics in the Test, higher Percentile Score in Chemistry in the Test and Candidates older in age to be preferred.
Q. How final JEE Main result will be prepared?
A. To compile the final JEE Main 2026 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking.
Q. How JEE Main rank list is prepared?
A. The rank list of JEE Main 2026 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
Q. How will NTA calculate JEE Main 2026 Percentile Score?
A. The National Testing Agency will calculate JEE Main 2026 Percentile Score through the Normalisation Process.
Q. Will NTA release the JEE Main result along with the percentile score?
A. NTA is responsible for releasing JEE Main 2026 result along with the percentile score. To determine JEE Main 2025 results and rank list, NTA adopted the process of normalization which was based on percentile calculation.
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Student Forum
Anything you would want to ask experts?Answered Yesterday
Chamistry
N
Beginner-Level 1
Answered 3 days ago
The Anant National University JEE Main Cutoff 2024 was released for all rounds and categories for students under the Homes State and All India quota who were seeking admission to the BE/BTech and BArch courses.
The JEE Main Cutoff 2024 for the BArch course was 22012 for students belonging to the Gene
N
Contributor-Level 10
Answered 4 days ago
In 2023, the Dr. D.Y. Patil Institute of Engineering Management and Research, Akurdi JEE Main cutoff ranks varied between 38276 and 208419 for the students belonging to the General AII India quota for BTech admission. Among all the specialisations, the most competitive was Computer Engineering, with
R
Contributor-Level 10
Answered 4 days ago
No. NTA has not allowed calculators of kind - virtual or physical inside the JEE Main exam hall. Candidates must not carry calculators or any other electronic device in the JEE Main examination centre.
V
Contributor-Level 6
Answered 4 days ago
No. NTA has clearly mentioned that ot will not change the dates of JEE Main exam of there is a clash of dates with any other examinations.
V
Contributor-Level 6
Answered 4 days ago
Hi.
JEE Main Score Route
If you have a JEE Main 2026 score, you can apply directly using that.
Your All India Rank (AIR) is used for:
Branch allocation (high-demand branches like CSE, AI/ML, IT, etc.)
Merit-based scholarships
No CU-specific entrance exam is required in this case.
CUCET / Direct Admission R
h
Scholar-Level 17
Answered 4 days ago
Hi.
There is no fixed “minimum JEE Main percentile/rank” that guarantees admission to Chandigarh University (CU)'s B.Tech/B.E. in Computer Science Engineering (CSE), because admission depends on seat demand, number of applicants, branch popularity, and round of counselling. But we can estimate a roug
h
Scholar-Level 17
Answered 4 days ago
Hi.
Yes — at Chandigarh University (CU), it is possible to get a scholarship for B.Tech/B.E. (including CSE with specialisations like AI & ML / “IBM‑program” etc.) based on your JEE Main performance — but only under certain conditions and only for a small fraction of seats.
How CU's JEE‑based scholar
h
Scholar-Level 17
Answered 4 days ago
Hi.
1. Admission is primarily through CUCET
Chandigarh University (CU) uses CUCET, its own entrance test, as the primary criterion for seat allotment in all B.Tech/B.E programs — including specialised CSE branches.
Whether you want CSE – Cyber Security, CSE – Cloud Computing, or CSE – Data Science, you
h
Scholar-Level 17
Answered 4 days ago
Hi.
For 2024, the “closing cutoff rank” for CSE (General category, all‑India) was ~ 80,940.
For 2023 it was ~ 63,416, and for 2022 about 47,509 — showing demand has been rising year‑on‑year.
For branches like ECE (or general electronics‑type branches), the 2024 closing rank was ~112,216.
For other bran
h
Scholar-Level 17