How to calculate JEE Main 2026 Percentile Score: Know Normalization Process
Joint Entrance Exam (JEE) Main 2026 ( JEE Main )
JEE Main CSAB special counselling
22 Jul '26 - 18 Aug '26
The National Testing Agency (NTA) will announce JEE Main 2026 Result in the form of percentile score. NTA uses the normalization formula to calculate the JEE Main percentile score of candidates. JEE Main percentile and normalization formula used by NTA (National Testing Agency) is provided here. To determine JEE Main 2026 results and rank list, NTA will adopt the process of normalization which is based on percentile calculation. The rank list of JEE Main 2026 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
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Predict JEE Main Colleges- How To Calculate JEE Main 2026 Percentile Score
- Key Terms For Calculating JEE Main 2026 Percentile Score
- Highlights of JEE Main 2026 Percentile Score
- JEE Main 2026 Tie Breaker Rules
- Normalization Process To Prepare JEE Main 2026 Ranklist
- Read Important FAQs Here
How To Calculate JEE Main 2026 Percentile Score
NTA uses the given below formula to calculate the percentile score of a candidate
Key Terms For Calculating JEE Main 2026 Percentile Score
Before we delve deeper into how will NTA calculate the JEE Main 2026 Percentile Score through the Normalisation Process, there are some key terms you should know.
| Key terms |
What they mean |
|---|---|
| Percentile/ Percentile Score |
Percentile Score is the score based on the relative performance of candidates who have appeared for the exam. To calculate a percentile score, the marks secured are converted into a scale ranging from 100 to 0 for each session of examinees. NOTE: Percentile score is not the same as the percentage of marks secured. |
| Normalisation |
It is the practice of comparing candidates' scores who appeared in different shifts of the exam. The normalization process will be similar to the ones currently being adopted for other national level competitive exams like CAT. |
| Highest Raw Score and Percentile Score |
All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session. |
| Lowest Raw Score and Percentile Score |
Percentile Score of all the lowest raw scores is different. In this case, the percentile score will depend on the total number of candidates who have taken the examination for their respective sessions. |
Highlights of JEE Main 2026 Percentile Score
- JEE Main percentile score is the normalized score for the exam and not the raw marks of the test taker.
- The percentile score specifies the percentage of candidates who have scored equal to below (raw scores) a particular percentile in JEE Main. Thus, the topper of each session of JEE Main will get the same percentile i.e. 100.
- Percentiles will also be calculated and converted for marks obtained in between the highest and lowest scores
- The percentile score will be used to prepare the JEE Main merit list
- The percentile scores for JEE Main will be calculated up to 7 decimal places to reduce tie-breaking scenarios and avoid the bunching effect
- The overall percentile is not the aggregate of the percentile of the individual subject
To help you understand how the agency will calculate JEE Main percentile score, here’s an example.
Example: In 2026, JEE Main was held in two sessions of test-takers where the days and shifts were allotted randomly to candidates.
- Session-1: Day-1 Shift-1
- Session-2: Day-1 Shift-2
The JEE Main test takers were distributed in the following manner:
| Distribution of candidates |
||||||
|---|---|---|---|---|---|---|
| Session |
Day/Shift |
No of Candidates |
|
Marks |
|
|
| Absent |
Appeared |
Total |
Highest |
Lowest |
||
| Session-1 |
Day-1 Shift-1 |
3974 |
28012 |
31986 |
335 |
-39 |
| Session-2 |
Day-1 Shift-2 |
6189 |
32541 |
38730 |
346 |
-38 |
| Total (Session-1 to Session-4) |
25273 |
142482 |
167755 |
346 |
-49 |
|
The above example of the distribution of candidates, the method to calculate the Highest Raw Score in each paper will be normalized to 100, thus indicating that 100% of candidates have obtained scores that are equal to or lesser than the highest scorer/ topper for that session.
Example: Highest Raw Score and Percentile Score
According to the official website of JEE Main, the Percentile Score of all the lowest raw scores will be different and will be based on the total number of test-takers for their respective sessions.
Highest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Highest Raw Score |
Candidates who scored EQUAL OR LESS THAN Highest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
335 |
28012 |
100.0000000 [(28012/28012)*100] |
| Session-2 |
32541 |
346 |
32541 |
100.0000000 [(32541/32541)*100] |
| Session-3 |
41326 |
331 |
41326 |
100.0000000 [(41326/41326)*100] |
Lowest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Lowest Raw Score |
Candidates who scored EQUAL OR LESS THAN Lowest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
-39 |
1 |
0.0035699 [(1/28012)*100] |
| Session-2 |
32541 |
-38 |
1 |
0.0030730 [(1/32541)*100] |
| Session-3 |
41326 |
-49 |
1 |
0.0024198 [(1/41326)*100] |
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JEE Main 2026 Tie Breaker Rules
NTA resolves tie among students having same total percentile score in the following order
- NTA score in Mathematics
- NTA score in Physics
- NTA score in Chemistry
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Physics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Chemistry in the test
- If there is a tie even after this, candidates will be assigned the same rank.
| JEE Main Result 2026 | JEE Main 2026 Marks vs Percentile |
| JEE Main Question Paper PDF 2026-2013 | JEE Mains Cutoff 2026 |
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Normalization Process To Prepare JEE Main 2026 Ranklist
NTA’s normalization process for the preparation of the JEE Main merit/rank list will comprise of the following steps:
Stage 1: Refers to the conduct of the exam. JEE Main is conducted in two shifts over four days.
Stage 2: Once the examination is over, the results for each session will be prepared using raw scores and percentile scores for each subject.
Stage 3: The third and last step would be the compilation of the NTA score and preparation of JEE Main merit list. Remember, the Final Ranking/ Merit would be prepared only after resolving ties (if any).
To compile JEE Main 2026 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking. Candidates who appear in both the attempts; their best of the two NTA scores will be considered further for the preparation of Merit List /Ranking.
Read Important FAQs Here
Q. What is JEE Main Percentile Score?
A. JEE Main Percentile Score is the score based on the relative performance of candidates who have appeared for the JEE Main entrance exam and it is not the same as the percentage of marks secured.
Q. What is Normalisation in JEE Main?
A. It is the practice of comparing candidates' scores who appeared in different shifts of the JEE Main exam.
Q. What is Highest Raw Score and Percentile Score in JEE Main?
A. It is the practice of comparing candidates' scores who appeared in different shifts of the JEE Main exam.
Q. What is Highest Raw Score and Percentile Score in JEE Main?
A. All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session.
Q. How JEE Main merit list is prepared?
A. The percentile score will be used to prepare JEE Main merit list.
Q. What are the JEE Main 2026 Tie Breaker Rules?
A. In case, where two or more test takers secure equal Percentile Scores in the exam, the inter-se merit will be determined in the following order: Candidates obtaining higher Percentile Score in Mathematics in the Test, their higher Percentile Score in Physics in the Test, higher Percentile Score in Chemistry in the Test and Candidates older in age to be preferred.
Q. How final JEE Main result will be prepared?
A. To compile the final JEE Main 2026 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking.
Q. How JEE Main rank list is prepared?
A. The rank list of JEE Main 2026 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
Q. How will NTA calculate JEE Main 2026 Percentile Score?
A. The National Testing Agency will calculate JEE Main 2026 Percentile Score through the Normalisation Process.
Q. Will NTA release the JEE Main result along with the percentile score?
A. NTA is responsible for releasing JEE Main 2026 result along with the percentile score. To determine JEE Main 2025 results and rank list, NTA adopted the process of normalization which was based on percentile calculation.
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Student Forum
Anything you would want to ask experts?Answered 16 hours ago
No, JEE Main is not required to get admission in BTech at Rajalakshmi Engineering College. Admissions under the government quota rely primarily on Class 12 marks through TNEA counseling. However, JEE Main scores may be considered for admission.
R
Contributor-Level 10
Answered 17 hours ago
Yes, most Coimbatore colleges, including PSG Tech, Karunya, and Kumaraguru, primarily admit students through TNEA counselling, which is based on Class 12 merit rather than JEE Main. JEE Main is mainly relevant if you're targeting government institutes like NITs. So a strong Class 12 score alone can
T
Contributor-Level 10
Answered 20 hours ago
No, I don't think you can get into B.Tech EEE at Ajay Kumar Garg Engineering College, Ghaziabad with JEE Main rank of 5,30,000 as General, non-UP domicile candidate. Typically, closing rank for EEE close much earlier around 3,00,00.
A
Contributor-Level 6
Answered 22 hours ago
Absolutely. Unlike government colleges with very tight cutoffs, most private engineering colleges in UP admit students across a wide score range, and several also accept students without a JEE Main score at all. Your branch choice and college reputation still matter, but private colleges generally o
T
Contributor-Level 10
Answered Yesterday
No, JEE Main is not mandatory for BTech admission to SVSU Meerut. While JEE Main scores are accepted for BTech application, students can qualify directly through the university's SNET examination or Class 12 merit.
A
Contributor-Level 9
Answered 4 days ago
No, JEE Main has not been mentioned as an accepted entrance exam for BTech at GLA University.
Candidates who want to apply for BTech at this institute must appear in their own entrance exam called GLAET.
Admissions are based solely on scores obtained in this exam along with performance in PI rounds.
S
Contributor-Level 10
Answered 4 days ago
Yes, along with the CUET UG score, DIT Dehradun also select students based on JEE Main and on the merit of Class 12. On-campus admission counselling is conducted by the university, for which 25% of seats are reserved for Uttarakhand candidates who have scored 95% or above in Class 12. Direct admissi
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Contributor-Level 10
Answered 6 days ago
A JEE Main rank of 2000 would get you admission to this institute if you belong to the General AI category. In the first round, the highest Round 1 rank acceptable is 34000 for this category. Hence, students in this category would need a rank of at least 34000 to be considered qualified for admissio
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Contributor-Level 10
Answered 6 days ago
MIT-WPU JEE Main cutoff 2026 is released for admission to the BTech course based on the student's peformance in the JEE Main entrance exam. For the General AI category, the round 1 cutoff was 34000 for various BTech course branches. Students can check the table below to know the round 1 cutoff for o
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Contributor-Level 10
Answered 6 days ago
If you belong to the General AI category, the JEE Main Round 5 closing ranks for BTech admission ranged between 24247 and 77123. Among all the branches, Computer Science and Engineering turned out to be the most competitive for admission, while Food Engineering and Technology was the least competiti
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Contributor-Level 10
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