The National Testing Agency (NTA) will announce JEE Main 2027 result in the form of a percentile score. NTA uses the normalisation formula to calculate the JEE Main percentile score of candidates. JEE Main percentile and normalisation formula used by NTA (National Testing Agency) is provided here. To determine JEE Main 2027 results and rank list, NTA will adopt the process of normalization which is based on percentile calculation. The rank list of JEE Main 2027 will be prepared by the NTA based on percentile scores and not on the raw marks secured by aspirants in the exam.
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Predict JEE Main Colleges- How To Calculate JEE Main 2027 Percentile Score
- Key Terms For Calculating JEE Main 2027 Percentile Score
- Highlights of JEE Main 2027 Percentile Score
- JEE Main 2027 Tie Breaker Rules
- Normalization Process To Prepare JEE Main 2027 Ranklist
How To Calculate JEE Main 2027 Percentile Score
NTA uses the formula given below to calculate the percentile score of a candidate
Key Terms For Calculating JEE Main 2027 Percentile Score
Before we delve deeper into how will NTA calculate the JEE Main 2027 Percentile Score through the Normalisation Process, there are some key terms you should know.
| Key terms |
What they mean |
|---|---|
| Percentile/ Percentile Score |
Percentile Score is the score based on the relative performance of candidates who have appeared for the exam. To calculate a percentile score, the marks secured are converted into a scale ranging from 100 to 0 for each session of examinees. NOTE: Percentile score is not the same as the percentage of marks secured. |
| Normalisation |
It is the practice of comparing candidates' scores who appeared in different shifts of the exam. The normalization process will be similar to the ones currently being adopted for other national level competitive exams like CAT. |
| Highest Raw Score and Percentile Score |
All the highest raw scores will have a normalised Percentile Score of 100 for their respective session. This means, that the highest raw scores secured by candidates would be normalised to a 100 Percentile Score for their respective session. |
| Lowest Raw Score and Percentile Score |
Percentile Score of all the lowest raw scores is different. In this case, the percentile score will depend on the total number of candidates who have taken the examination for their respective sessions. |
Commonly asked questions
The JEE Main cutoff is the minimum percentile score required to qualify for the JEE Advanced exam. Its is released with the April session result.
Candidates who do not score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
No. There is no qualifying percentile in JEE Main. However, the candidates who want to appear in JEE Advanced will have to get a minimum qualifying percentile in JEE Mains. This minimum qualifying percentile is announced with the JEE Main session 2 reult.
As per the analysis of JEE Main marks vs percentile, 120 marks would be around 95 to 97 percentile.
Highlights of JEE Main 2027 Percentile Score
- JEE Main percentile score is the normalized score for the exam and not the raw marks of the test taker.
- The percentile score specifies the percentage of candidates who have scored equal to below (raw scores) a particular percentile in JEE Main. Thus, the topper of each session of JEE Main will get the same percentile i.e. 100.
- Percentiles will also be calculated and converted for marks obtained in between the highest and lowest scores
- The percentile score will be used to prepare the JEE Main merit list
- The percentile scores for JEE Main will be calculated up to 7 decimal places to reduce tie-breaking scenarios and avoid the bunching effect
- The overall percentile is not the aggregate of the percentile of the individual subject
To help you understand how the agency will calculate JEE Main percentile score, here’s an example.
Example: In 2027, JEE Main was held in two sessions of test-takers where the days and shifts were allotted randomly to candidates.
- Session-1: Day-1 Shift-1
- Session-2: Day-1 Shift-2
The JEE Main test takers were distributed in the following manner:
| Distribution of candidates |
||||||
|---|---|---|---|---|---|---|
| Session |
Day/Shift |
No of Candidates |
|
Marks |
|
|
| Absent |
Appeared |
Total |
Highest |
Lowest |
||
| Session-1 |
Day-1 Shift-1 |
3974 |
28012 |
31986 |
335 |
-39 |
| Session-2 |
Day-1 Shift-2 |
6189 |
32541 |
38730 |
346 |
-38 |
| Total (Session-1 to Session-4) |
25273 |
142482 |
167755 |
346 |
-49 |
|
The above example of the distribution of candidates, the method to calculate the Highest Raw Score in each paper will be normalized to 100, thus indicating that 100% of candidates have obtained scores that are equal to or lesser than the highest scorer/ topper for that session.
Example: Highest Raw Score and Percentile Score
According to the official website of JEE Main, the Percentile Score of all the lowest raw scores will be different and will be based on the total number of test-takers for their respective sessions.
Highest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Highest Raw Score |
Candidates who scored EQUAL OR LESS THAN Highest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
335 |
28012 |
100.0000000 [(28012/28012)*100] |
| Session-2 |
32541 |
346 |
32541 |
100.0000000 [(32541/32541)*100] |
| Session-3 |
41326 |
331 |
41326 |
100.0000000 [(41326/41326)*100] |
Lowest Raw Score and Percentile Score
| Session |
Total Candidates Appeared |
Lowest Raw Score |
Candidates who scored EQUAL OR LESS THAN Lowest Raw Score |
Percentile Score |
|---|---|---|---|---|
| Session-1 |
28012 |
-39 |
1 |
0.0035699 [(1/28012)*100] |
| Session-2 |
32541 |
-38 |
1 |
0.0030730 [(1/32541)*100] |
| Session-3 |
41326 |
-49 |
1 |
0.0024198 [(1/41326)*100] |
JEE Main 2027 Tie Breaker Rules
NTA resolves tie among students having same total percentile score in the following order
- NTA score in Mathematics
- NTA score in Physics
- NTA score in Chemistry
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Physics in the test
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Chemistry in the test
- If there is a tie even after this, candidates will be assigned the same rank.
| JEE Main Result 2027 | JEE Main 2027 Marks vs Percentile |
| JEE Main Question Paper PDF 2027-2013 | JEE Mains Cutoff 2027 |
Commonly asked questions
Various experts provide the JEE Mains percentile vs rank estimation. Candidates can search "JEE Mains marks vs percentile by Shiksha" on Google to get their estimation.
CRL (the Common Rank List) in JEE Main. It is the overall merit-based ranking assigned to all candidates irrespective of their category.
The general and category wise JEE Mains are:
Category | Cutoff from Previous Year |
|---|---|
Unreserved (UR) | 93.1023262 |
Gen-EWS | 80.3830119 |
OBC-NCL | 79.4313582 |
SC | 61.1526933 |
ST | 47.9026465 |
UR-PwD | 0.0079349 |
NTA does not release marks vs rank data officially. The data available on the internet is provided by various experts and is subject to changes due to various variables.
Normalization Process To Prepare JEE Main 2027 Ranklist
NTA’s normalization process for the preparation of the JEE Main merit/rank list will comprise of the following steps:
Stage 1: Refers to the conduct of the exam. JEE Main is conducted in two shifts over four days.
Stage 2: Once the examination is over, the results for each session will be prepared using raw scores and percentile scores for each subject.
Stage 3: The third and last step would be the compilation of the NTA score and preparation of JEE Main merit list. Remember, the Final Ranking/ Merit would be prepared only after resolving ties (if any).
To compile JEE Main 2027 result, the four NTA scores (Physics, Chemistry, Mathematics, and overall score) of the first attempt and the second attempt will be merged for the compilation of results and preparation of the overall Merit List/Ranking. Candidates who appear in both the attempts; their best of the two NTA scores will be considered further for the preparation of Merit List /Ranking.
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Student Forum
Answered 19 hours ago
If your JEE Main score is not strong, Galgotias University can be a practical option to consider. It offers multiple B.Tech programmes and gives preference to JEE Main scores while also allowing admission based on its programme-specific eligibility criteria. Compare fees, branch, curriculum, and opp
A
Beginner-Level 2
Answered 22 hours ago
For the General All-India category at DIT University Dehradun, the JEE Main Round 1 closing ranks generally range from 1,20,000 to 2,50,000.
P
Beginner-Level 2
Answered 3 days ago
JECRC University Scholarship based on JEE Main scores is offered to BTech students. Check below eligibility and amount offered to BTech students at JECRC University:
Scholarship Criteria | Eligible Degree Programmes | Amount as percentage of Tuition Fee |
|---|---|---|
JEE (Main) 2026 Percentile Score 85 to 89.99 (General Category) | All BTech Programmes | 15% |
JEE (Main) 2026 Percentile Score more than 90 (General Category) | All BTech Programmes | 25% |
G
Contributor-Level 10
Answered 2 weeks ago
Top Aerospace and Aeronautical Engineering colleges in India that do not require JEE Main rely instead on private entrance exams, state-level tests, or direct merit admissions. Check the table below for the Aerospace engineering colleges in India without JEE.
| Top Colleges | Tuition Fee |
|---|---|
| Amity University, Noida | INR 11.4 lakh |
| Presidency University, Bangalore | INR 9 lakh |
| SNS College of Technology | INR 2 lakh |
| Parul University | INR 7.8 Lacs - INR 10.8 lakh |
| Amity University, Mumbai | INR 4.24 lakh |
T
Contributor-Level 10
Answered 4 weeks ago
According to the tentative schedule, JEE Main 2027 counselling registration is likely to commence in June 2027 after the conclusion of both exam sessions.
H
Beginner-Level 5
Answered 4 weeks ago
The cutoff rank in Round 7 for BTech Computer Science & Engineering under General All India category is 53,013. It is the most competitive branch in the institute.
H
Beginner-Level 5
Answered 4 weeks ago
Yes, JEE Main is compulsory for admission in B.Tech course at SGSITS.
H
Beginner-Level 5
Answered 4 weeks ago
After qualifying JEE Main, students need to register themselves for MP BE Counselling, choose colleges/branches, attend rounds and verify documents to secure admission.
H
Beginner-Level 5
Answered 4 weeks ago
Getting into B.Tech CSE is straightforward. You need to have passed 10+2 with Physics and Mathematics, along with Chemistry, Biotechnology, Biology, or a Technical Vocational subject. Marks from boards like CBSE, ISC, and PSEB are accepted. JEE Main scores are also recognised under the RBUEdge Schol
P
Contributor-Level 6
Answered 4 weeks ago
Yes, JEE Main scores are recognised under the RBUEdge Scholarship Program, so your entrance exam effort can also help reduce your fees. A higher score falls in a higher scholarship slab, with the top slab offering a 60% waiver on the course fee. This is a nice reward for the hard work that goes into
A
Contributor-Level 6


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