How To Calculate JEE Main 2026 Rank From Percentile: Criteria and Method
Joint Entrance Exam (JEE) Main 2026 ( JEE Main )
Registration - 31 Oct '25 - 27 Nov '25
- How to calculate JEE Main rank from percentile
- Can JEE Main rank be calculated from percentile score?
Some experts believe that candidates cannot calculate JEE Main Rank from the percentile score of just one examination, while others believe the opposite. Let us discuss both cases in this article.
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Predict JEE Main Colleges- How to calculate JEE Main 2026 rank from Percentile?
- Can JEE Main rank be calculated from percentile score?
- FAQs regarding JEE Main Percentile and Ranks
How to calculate JEE Main 2026 rank from Percentile?
Candidates can analyze their NTA scores and calculate their approximate JEE Main rank through their percentile scores. Here’s how.
Take the total number of candidates who appeared for the JEE Main exam as "N". The exam is conducted in four days in two slots (4 days x 2 slots = 8 sessions in total). So, "S" number of students took the exam in each session. Note that the JEE Main results/scorecard mentions only the NTA score for each subject and not the subject-wise marks secured by candidates. The percentile score is displayed against each of the subjects and the overall percentile score is calculated up to 7 decimals using a pre-determined formula.
| For more information on how JEE Main 2026 Percentile score is calculated, read this article on How to calculate JEE Main 2026 Percentile Score - Know Normalization Process |
The following data is required to convert the JEE Main percentile into a rank:
- Your JEE Main score
- Number of students who appeared for JEE Main exam
- Percentage of students whose marks are below or equal to yours.
- The percentage of students whose marks are above yours.
- Number of students above your marks
While the data for the first two aspects are easily available, the figures for the other three data points are difficult to find. To calculate these, here's what you need to do.
Let’s assume:
| Your NTA score = |
P |
| Total Number of Students = |
N |
| Percentage of students below or equal to your marks = |
P For example: if you got 70 percentile in JEE Main, this means 70% of candidates who appeared for JEE Main are below or at the same level as you are |
| Percentage of students above your marks = |
100 - P |
| Number of students above your marks |
(100 – P)/100)*N |
The formula to calculate the JEE Main rank from percentile score is: (100 – P)/100)*N
The rank generated will be the probable All India Rank (AIR) you can expect to secure in JEE Main. The actual rank might differ owing to different factors.
Can JEE Main rank be calculated from percentile score?
According to an IIT Bombay expert, it’s difficult to derive an AIR through one’s percentile score. To help you understand why you cannot calculate JEE Main rank from percentile scores of the first attempt of the exam, let’s take the example of two students.
| Student |
Percentile Score – January |
Percentile Score – April |
AIR (All India Rank) |
|---|---|---|---|
| A |
96 percentile |
65 percentile |
? |
| B |
60 percentile |
98 percentile |
? |
Student A secured 96 percentile in the JEE Main January exam, while Student B got 60 percentile in the same session of the examination. Now, the same set of students has secured the 65 percentile and 98 percentile respectively in JEE Main.
Now, the general thought process of candidates after seeing the percentile score of the January attempt would be that Student A has performed better than Student B in JEE Main. But, that’s not the case. Because, on the second attempt of the exam, Student B secured a better percentile than Student A. As per NTA, JEE Main ranks or rank list will be published after taking into account the better of the two four NTA scores of all candidates who have appeared for JEE Main January and April sessions. Furthermore, to determine JEE Main results and rank list, the agency will adopt the process of normalization which will be based on percentile calculation. Thus, deriving one’s rank from the percentile score of the first attempt is not possible as the exam is being conducted twice.
Important note:
- The percentile is not the same as a percentage.
- JEE Main merit list will be prepared based on percentile scores and not on the raw marks secured by aspirants in the exam.
FAQs regarding JEE Main Percentile and Ranks
Q. Is percentile equal to a percentage?
A. No, percentile and percentage are totally different from each other. The percentile rank of a score is the percentage of scores in its frequency distribution that are equal to or lower than it.
Q. What is percentile vs percentage?
A. The percentile is relative to the score that other people made on the test, while the percentage is your individual score. Percentile is used when scoring standardized tests and is used in statistics.
Q. What is the percentile in JEE Main?
A. JEE Main percentile score will be the normalised score for the exam and not the raw marks of the test taker.
Q. Is 100 percentile possible?
A. If the "percentage below or equal to" definition is used, then, yes, we can have 100 percentile. However, if we use the "percentage below" definition, then, no, you cannot have a 100 percentile.
Q. Can I get nit with 94 percentile?
A. According to your percentile, your approximate rank is 66,000. If you have a home state quota, then you will definitely get an NIT.
Q. Is 97 percentile good in JEE mains?
A. Scoring 97% is good, so, when you are looking for the colleges that you can get at such percentile. It can be an NIT.
Q. Can I get nit with 70 percentile?
A. No, there is no chance to get admission to any NITs with a 70 percentile for the general category. For the general candidates, at least 97 percentile is required to get a seat in NITs. You can try to get admission to other good engineering colleges.
Q. Can I get nit with 90 percentile OBC?
A. You have very low chances of getting admission in any of the NITs based on your JEE Main percentile score and category rank. Try for admission in private colleges through state counselling.
Q. What percentile is required for IIIT?
A. Every year cut off score for IIIT Hyderabad's last closing branch is around 250-260 or 99 percentile, which means a rank of around 1000 will be required for admission.
Q. Is IIIT better than nit?
A. It depends on which IIIT/NIT you are getting according to your rank. In terms of placement, faculties and infrastructure some IIITs are far better than many NITs.
As per the JEE Main 2023 cutoff data released by the NTA, PwD category has the lowest cutoff of 0.0013527. The highest cutoff is for general category which is 90.7788642. The PwD candidates scoring above 0.0013527 NTA score are eligible to appear in JEE Advanced for admission to IITs. The PwD cutoff has been lowered in 2023 to 0.0013527 which was 0.0031029 in the year 2022.
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Candidates who do not score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
NIT Andhra Pradesh BTech admission is based on candidates' performance in the JEE Main entrance exam, followed by the JoSAA counselling process. The Round 1 of JEE Main cutoff 2025 has been released for different categories of students belonging to the AI and HS quotas. For students belonging to the OBC category, the JEE Main closing ranks ranged between 5741 and 14452. For branch-wise Round 1 cutoff details, check out the table below:
| Course | JEE Main Round 1 Cutoff 2025 (OBC AI Quota) |
|---|---|
| B.Tech. in Biotechnology | 14191 |
| B.Tech. in Chemical Engineering | 13555 |
| B.Tech. in Civil Engineering | 14452 |
| B.Tech. in Computer Science and Engineering | 5741 |
| B.Tech. in Electrical and Electronics Engineering | 10155 |
| B.Tech. in Electronics and Communication Engineering | 7400 |
| B.Tech. in Mechanical Engineering | 12259 |
| B.Tech. in Metallurgical and Materials Engineering | 14368 |
The cutoff for NITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC, ST candidates. Candidates can check the previous year JEE Main cutoff below for some top NITs and branches. For detailed cutoff report, candidates can check Shiksha page.
- MNNIT Allahabad CSE Closing Rank Open Category: 5627 (Home State)
- MNNIT Allahabad CSE Closing Rank Open Category: 4254 (Open)
- MNIT Jaipur CSE Closing Rank Open Category: 5610 (Home State)
- MNIT Jaipur CSE Closing Rank Open Category: 4631 (Open)
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