The National Testing Agency (NTA) has released JEE Main 2019 results with percentile score for Paper 1 on the official website of the exam. The exam results with JEE Main percentile score were expected to be declared on January 31, but the exam conducting authority released the same almost two weeks in advance. Please note that the JEE Main 2019 Paper-II for BArch will be declared later.
Latest: JEE Main 2020 result for January session announced
Read: How To Calculate JEE Main 2019 Rank From Percentile
To check JEE Main 2019 result cum scorecard with percentile score online on the official website, candidates will need their log-in details like Application Number and Date of Birth/Password.
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Read:JEE Main 2019 Toppers (Paper 1); 15 Students Secure 100 Percentile
JEE Main 2019 result and scorecard released by NTA comprises only subject-wise percentiles for candidates who appeared for the exam. The overall score for JEE Main 2019 for candidates who appeared for the exam is yet to be declared. JEE Main 2019 cut off too haven’t been declared by NTA as yet. Check JEE Main 2019 expected cut-offs now!
Read:JEE Main 2019 Topper Interview (January Exam): Dhruv Arora from Indore secures 100 percentile
The NTA scorecard of JEE Main 2019 comprises details like the aspirant's name, roll number, DOB (Date of Birth), his/her parent’s name, category, state code of eligibility, NTA score obtained in Physics, Chemistry and Mathematics, total marks obtained etc. Please note that the JEE Main 2019 All India Ranks (AIR) will be declared once the April session of the exam concludes. The ranks will be published taking into consideration better of the two NTA Scores of all candidates who have appeared in January and April session of the examinations.
JEE Main 2019 Percentile scores of a Candidate have been calculated as follows:
100 X Number of candidates appeared in the ‘Session’ with raw score EQUAL TO OR LESS than the candidate/ Total number of the candidates appeared in the ’Session’
Read: How to calculate JEE Main 2019 Percentile Score - Know Normalization Process
In a recently released notification, NTA has also released the list of candidates who have secured 100 percentile in JEE Main 2019 Paper 1 of the January session. Check out the list of JEE Main 2019 toppers with 100 percentile for Paper 1 - BTech below.
| S.No. |
Application No. |
Candidate Name |
State Code of Eligibility |
| 1 |
190310086378 |
DHRUV ARORA |
MADHYA PRADESH |
| 2 |
190310096437 |
RAJ ARYAN AGRAWAL |
MAHARASHTRA |
| 3 |
190310126508 |
ADELLY SAI KIRAN |
TELANGANA |
| 4 |
190310131614 |
BOJJA CHETAN REDDY |
ANDHRA PRADESH |
| 5 |
190310139257 |
SAMBIT BEHERA |
RAJASTHAN |
| 6 |
190310150035 |
NAMAN GUPTA |
UTTAR PRADESH |
| 7 |
190310166518 |
YINDUKURI JAYANTH PHANI SAI |
TELANGANA |
| 8 |
190310167837 |
VISHWANTH K |
TELANGANA |
| 9 |
190310204122 |
HIMANSHU GAURAV SINGH |
UTTAR PRADESH |
| 10 |
190310208678 |
KEVIN MARTIN |
KARNATAKA |
| 11 |
190310240908 |
SHUBHANKAR GAMBHIR |
RAJASTHAN |
| 12 |
190310244684 |
BATTEPATI KARTHIKEYA |
TELANGANA |
| 13 |
190310324762 |
ANKIT KUMAR MISRA |
MAHARASHTRA |
| 14 |
190310378068 |
JAYESH SINGLA |
PUNJAB |
| 15 |
190310597090 |
GUPTA KARTIKEY CHANDRESH |
MAHARASHTRA |
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Student Forum
Answered 3 hours ago
The East Point Group of Institutions accepts many exams for the BE course. The accepted exams are JEE Main, COMEDK, and KCET. Students can appear in any of these exams to get admission at EPGI. Students need to fulfil the eligibility criteria as well.
A
Contributor-Level 10
Answered 2 days ago
With 57.8 percentile in JEE Main and 73% boards, getting CSE/AI in top government colleges is unlikely. But you still have good chances in private colleges through UPTAC/AKTU or direct admission.
Possible options:
KIET Group of Institutions
ABES Engineering College
Galgotias College of Engineering a
H
Beginner-Level 1
Answered 2 days ago
Amrut Institute offer admission in BTech and Diploma in Engineering based on merit in last qualifying exam. So, no JEE Main is not compulsory to take admission in Amrut Institute courses.
R
Contributor-Level 10
Answered 5 days ago
With a JEE Main rank of 291970, you can get into NIT Calicut if you belong to the SC Home State quota category.
For this category, the highest rank admissible was 543879 (as per the last round of NIT Calicut cutoff 2025). See the table below to know which courses you can opt for.
| Course | NIT Calicut JEE Main cutoff 2025 |
|---|---|
| B.Tech. in Chemical Engineering | 343880 |
| B.Tech. in Biotechnology | 386381 |
| B.Tech. in Civil Engineering | 405588 |
| B.Tech. in Production Engineering | 449781 |
| B.Tech. in Energy Engineering | 543879 |
To know the accepte
N
Contributor-Level 10
Answered 6 days ago
JEE (Main) cutoff for BTech in Computer Science and Engineering in Sagar Institute of Science Technology and Research, Bhopal in the closing round has ranged between 3,75,232 to 10,07,060 from 2021 to 2023.
S
Contributor-Level 10
Answered 6 days ago
Yes, students can get EIT Faridabad scholarship with 97.6 percentile in JEE Main. Applicants can get scholarship on the basis of scores in entrance exam. Check the table below to know eligiblity of scholarships offered on the basis of JEE Main scores:
| Eligibility Criteria | Scholarship (on tuition fee) |
|---|---|
| 95.01 percentile and above | 50% |
| 90.01 - 95 prcentile | 35% |
| 85.01 - 90 percentile | 25% |
| 80.01 - 85 percentile | 20% |
G
Contributor-Level 10
Answered 6 days ago
Yes, you can get admission in BTech in Sagar Institute of Science Technology and Research without JEE (Mains) rank through College Level Counselling based on merit if there are any seats left vacant after DTE Bhopal Counselling.
S
Contributor-Level 10
Answered 6 days ago
Guru Tegh Bahadur 4th Centenary Engineering College BTech admission is based on merit and entrance. Students are selected based on academic scores and JEE Main scores. However, JEE Main scores are not enough for admission. The final seat allotement for BTech is conducted through the centralised coun
G
Contributor-Level 10
Answered a week ago
Yes. The syllabus overlaps heavily, and JEE preparation often covers TS EAMCET topics. Just add state-specific mock tests for better speed and familiarity.
M
Contributor-Level 8
Answered a week ago
Any candidate who cleared Class 12th with an aggregate of less than 50% must appear for JEE Mains to qualify for Sagar Institute of Science Technology and Engineering (SISTec-E) - Sagar Group of Institutions Bhopal BTech admission. Howver, candidates who cleared Class 12th with a minimum aggregate o
S
Contributor-Level 10

