240 Marks in JEE Main 2027 Percentile: Check Expected Rank
Joint Entrance Exam (JEE) Main 2027 ( JEE Main )
JEE Main 2027 Registration Session 1
24 Oct '26 - 22 Nov '26
Candidates can check the 240 Marks in JEE Percentile on this page. Candidates are given admission based on the JEE Main percentile. Check here to know the normalisation formula used by NTA to calculate the percentile. Read more to know what the percentile score is expected for 240 marks.
240 Marks in JEE Main Percentile
240 Marks in JEE Main Percentile 2027: The National Testing Agency announces the exam result in percentile. Candidates can check this page to know how the percentile calculation is done from marks. After the results are announced, students have doubts about percentile scores compared to marks. By using the JEE Main marks vs percentile converter, candidates can calculate the percentile.
The National Testing Agency (NTA) normalises raw shift scores into percentile marks to determine final JEE Main ranks. For candidates scoring 240 out of 300 marks in JEE Main 2027, the expected percentile sits at an excellent 99.5 to 99.9, securing an All India Rank between 5,000 and 11,000.
Also Read: JEE Main 2026 Marks Vs Percentile
What is 240 marks in JEE Main 2027 Percentile?
As per the data provided by the experts at Shiksha.com, the expected percentile for a score of 240 is given below.
| JEE Main marks | Expected percentile |
|---|---|
| 240 - 280+ | 99.9+ |
| 210 - 240 | 99.5 - 99.9 |
As per the table above, it can be said that
- 240 marks in JEE Mains 2027 percentile can be around the 99.5 to 99.9 percentile.
Important points to note here:
- The percentile score calculation will change every year. Candidates must not come to a conclusion based on previous years' marks vs ranks data of the exam.
- Candidates must always try to score high in JEE Main 2027.
- The percentile given here is not an accurate estimation. The percentile marks in JEE Mains depend on factors like the highest score of the candidates in the exam, the number of candidates appearing for the exam, the number of shifts in the exam and also the exam difficulty level.
- Formula to Calculate NTA JEE Main Percentile
- Is 240 a Good Score in JEE Mains 2027?
- JEE Main 2027 Rank Predictor
Formula to Calculate NTA JEE Main Percentile
NTA uses a normalisation formula to calculate the JEE Main percentile. The steps used to calculate the JEE Main percentile from raw scores of the candidates are given below:
Step 1: Raw Score Calculation
The raw scores of the candidates are calculated using the marking scheme of the JEE Main 2027 exam:
- +4 for each correct answer.
- -1 for each wrong attempt.
- 0 for unanswered
Step 2: Raw Marks to Percentile
The raw scores of the candidates are converted into a percentile score or NTA score in each subject. The total marks out of 300 are also converted to a percentile score using the formulas below:
Also Read:
| 110 Marks in JEE Main Percentile 2027 | 250 Marks in JEE Main Percentile 2027 |
| 120 Marks in JEE Main Percentile 2027 | |
Is 240 a Good Score in JEE Mains 2027?
A score of 240 marks in JEE Main 2027 yields an excellent percentile range of 99.5 to 99.9, translating to an All India Rank between 5,000 and 11,000. Because the National Testing Agency (NTA) normalises raw marks across different shifts to calculate final ranks, admissions rely strictly on this percentile-derived rank rather than the score itself. This performance easily secures eligibility for JEE Advanced and guarantees top-tier branches at premier NITs, IIITs, and CFTIs during JoSAA counselling.
| JEE Main marks | Expected percentile | Expected ranks |
|---|---|---|
| 240 - 280+ | 99.9+ | 1 - 1,200 |
| 210 - 240 | 99.5 - 99.9 | 1,200 - 6,000 |
Commonly asked questions
Candidates who do not score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
NTA does not release marks vs rank data officially. The data available on the internet is provided by various experts and is subject to changes due to various variables.
As per the JEE Main cutoff data released by the NTA, PwD category has the lowest cutoff.
The cutoff for NITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC, ST candidates. Candidates can check the previous year JEE Main cutoff below for some top NITs and branches. For detailed cutoff report, candidates can check Shiksha page.
- MNNIT Allahabad CSE Closing Rank Open Category: 5627 (Home State)
- MNNIT Allahabad CSE Closing Rank Open Category: 4254 (Open)
- MNIT Jaipur CSE Closing Rank Open Category: 5610 (Home State)
- MNIT Jaipur CSE Closing Rank Open Category: 4631 (Open)
JEE Main 2027 Rank Predictor
Candidates can calculate their All India Rank with the JEE Main Rank Predictor. Candidates must enter all the details asked in the predictor. The Rank predictors will predict the rank based on the previous year's trends and cutoff. Candidates can also use the JEE Main 2027 College Predictor to know the college in which they are likely to get admission based on rank. The candidates need to know the colleges to which they can apply based on ranks.
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Student Forum
Anything you would want to ask experts?Answered 6 hours ago
For the General All-India category at DIT University Dehradun, the JEE Main Round 1 closing ranks generally range from 1,20,000 to 2,50,000.
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Beginner-Level 2
Answered 3 days ago
JECRC University Scholarship based on JEE Main scores is offered to BTech students. Check below eligibility and amount offered to BTech students at JECRC University:
Scholarship Criteria | Eligible Degree Programmes | Amount as percentage of Tuition Fee |
|---|---|---|
JEE (Main) 2026 Percentile Score 85 to 89.99 (General Category) | All BTech Programmes | 15% |
JEE (Main) 2026 Percentile Score more than 90 (General Category) | All BTech Programmes | 25% |
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Contributor-Level 10
Answered 2 weeks ago
Top Aerospace and Aeronautical Engineering colleges in India that do not require JEE Main rely instead on private entrance exams, state-level tests, or direct merit admissions. Check the table below for the Aerospace engineering colleges in India without JEE.
| Top Colleges | Tuition Fee |
|---|---|
| Amity University, Noida | INR 11.4 lakh |
| Presidency University, Bangalore | INR 9 lakh |
| SNS College of Technology | INR 2 lakh |
| Parul University | INR 7.8 Lacs - INR 10.8 lakh |
| Amity University, Mumbai | INR 4.24 lakh |
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Answered 3 hours ago
If your JEE Main score is not strong, Galgotias University can be a practical option to consider. It offers multiple B.Tech programmes and gives preference to JEE Main scores while also allowing admission based on its programme-specific eligibility criteria. Compare fees, branch, curriculum, and opp
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The cutoff rank in Round 7 for BTech Computer Science & Engineering under General All India category is 53,013. It is the most competitive branch in the institute.
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Yes, JEE Main is compulsory for admission in B.Tech course at SGSITS.
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After qualifying JEE Main, students need to register themselves for MP BE Counselling, choose colleges/branches, attend rounds and verify documents to secure admission.
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Getting into B.Tech CSE is straightforward. You need to have passed 10+2 with Physics and Mathematics, along with Chemistry, Biotechnology, Biology, or a Technical Vocational subject. Marks from boards like CBSE, ISC, and PSEB are accepted. JEE Main scores are also recognised under the RBUEdge Schol
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Contributor-Level 6
Currently - Deputy Manager, Content
Role - News and Feature Writer, Content Editor
Expertise - Engineering Education and Counselling
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