150 Marks in JEE Main Percentile 2027: Check Expected Rank and NITs
Joint Entrance Exam (JEE) Main 2027 ( JEE Main )
JEE Main 2027 Registration Session 1
24 Oct '26 - 22 Nov '26
Check here what JEE Main percentile you can get if you score 150 marks out of 300. Also, we have provided here the list of NITs and courses that you can get with 150 marks in JEE Main 2027.
150 marks in JEE Main 2027 Percentile
150 marks in JEE Main 2027 Percentile: What would your JEE Main 2027 percentile be if you score 150 marks out of 300? Let us analyse below how NTA calculates your percentile score from the raw score here. Based on previous year trends, we have provided here an estimation of the percentile score for the raw score of 150 out of 300 marks in JEE Main 2027.
The exact percentile for 150 marks in JEE Main 2027 cannot be determined until results are out. This is because percentiles depend on shift difficulty, the highest score, and student numbers. However, based on trends from previous years, 150 marks generally corresponds to a 97.5 to 98.5 percentile.
- JEE Main Percentile Calculator 2027 - NTA Score Calculation
- What will 150 Marks be in JEE Main Percentile?
- What Does 150 Marks in JEE Main 2027 Mean - Which NIT and Course Can you Get?
- What is a Good Score in JEE Main 2027?
JEE Main Percentile Calculator 2027 - NTA Score Calculation
There is a set formula that NTA uses to calculate the JEE Main percentile. The raw scores of the candidates out of 300 in the exam are converted to a percentile score using this standard formula. The detailed formula is provided via the information brochure of JEE Main 2027. Candidates can check out the formula to know how to calculate the JEE Main percentile. We have also mentioned the steps below:
The process to calculate the JEE Main percentile from your raw score out of 300 is as follows:
Step 1: Candidates are distributed in shifts:
The candidates are distributed equally in two shifts on each day of the exam:
- Day-1 Shift -1
- Day-1 Shift -2
Step 2: Result for each shift
The JEE Main result for each shift is prepared taking into consideration the following scores:
- Raw Score
- Percentile scores of total raw scores
For each shift, the percentile score is calculated using the formula below:
In this formula, let TP1 be your percentile score of the total raw score. Then, your percentile in your shift will be:
Step 3: Compilation of NTA score and preparation of result:
The Percentile scores for the total raw score for all the shifts (Day-1 Shift -1 and Day-1 Shift -2) as calculated in Step 2 above, are merged and are called the NTA scores, which will then be used for the compilation of results.
Also Read: Marks vs Percentile JEE Mains 2026
| JEE Main Counselling | JEE Main Cutoff 2027 |
| Want to know what your JEE Main 2027 rank will be based on your score and percentile? Check out the JEE Main rank predictor 2027 by Shiksha.com, which predicts your rank after analysing several years’ percentile/marks vs rank data. JEE Main Rank Predictor 2027 |
What will 150 Marks be in JEE Main Percentile?
Check JEE Main percentile for 150 marks, based on past year trends below:
| JEE Main Score | JEE Main Percentile |
|---|---|
| 161 - 170 | 99.272084 - 99.431214 |
| 151 - 160 | 99.028614 - 99.239737 |
| 141 - 150 | 98.732389 - 98.990296 |
| 131 - 140 | 98.317414 - 98.666935 |
From the above table, it is clear that:
- 150 marks in JEE Main 2027 will be around 98 to 99 percentile
But, candidates should keep in mind that the above estimation of 150 marks in JEE Mains 2027 percentile is per the past few years' analysis of the JEE Main marks vs rank data. Since the percentile score calculation depends on different factors like the number of candidates appearing for the exam, the difficulty level of the shifts, the top score, etc., the exact estimation is difficult to reach.
| Curious about which college you may get based on your JEE Main 2027 performance? Check out the JEE Main college predictor 2027 by Shiksha.com, which predicts college based on your JEE Main marks, ranks and percentile after analysing data from previous year cutoffs. JEE Main 2027 College Predictor 2027 |
Commonly asked questions
The JEE Main cutoff is the minimum percentile score required to qualify for the JEE Advanced exam. Its is released with the April session result.
| Year | General (UR) Percentile |
|---|---|
| 2026 | 93.4123549 |
| 2025 | 93.1023262 |
| 2024 | 93.2362181 |
| 2023 | 90.7788642 |
| 2022 | 88.4121383 |
| 2021 | 87.8992241 |
| 2020 | 90.3765335 |
| 2019 | 89.7548849 |
Candidates who do not score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
No. There is no qualifying percentile in JEE Main. However, the candidates who want to appear in JEE Advanced will have to get a minimum qualifying percentile in JEE Mains. This minimum qualifying percentile is announced with the JEE Main session 2 reult.
What Does 150 Marks in JEE Main 2027 Mean - Which NIT and Course Can you Get?
Predicting exact NIT allotments for 150 marks in JEE Main is difficult due to changing shift difficulties and annual cut-offs. However, past trends indicate 150 marks roughly gives a 97.5 to 98.5 percentile, and an approximate rank range of 9,000 to 11,678. General category candidates can expect the following NITs and courses as per the previous year's JoSAA opening and closing ranks in this rank range:
| Institute | Academic Program Name | Closing Rank |
|---|---|---|
| Malaviya National Institute of Technology Jaipur | Electronics and Communication Engineering (4 Years, Bachelor of Technology) | 9667 |
| National Institute of Technology Delhi | Electronics and Communication Engineering (4 Years, Bachelor of Technology) | 10909 |
| Maulana Azad National Institute of Technology Bhopal | Computer Science and Engineering (4 Years, Bachelor of Technology) | 9249 |
| National Institute of Technology Durgapur | Computer Science and Engineering (4 Years, Bachelor of Technology) | 9836 |
|
National Institute of Technology, Kurukshetra
|
Artificial Intelligence and Machine Learning (4 Years, Bachelor of Technology) | 9204 |
| Mathematics and Computing (4 Years, Bachelor of Technology) | 10265 | |
|
National Institute of Technology, Rourkela
|
Electrical Engineering (4 Years, Bachelor of Technology) | 10623 |
| Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology) | 9555 | |
|
Sardar Vallabhbhai National Institute of Technology, Surat
|
Artificial Intelligence (4 Years, Bachelor of Technology) | 10721 |
| Mathematics and Computing (4 Years, Bachelor of Technology) | 10306 | |
| Visvesvaraya National Institute of Technology, Nagpur | Electronics and Communication Engineering (4 Years, Bachelor of Technology) | 10545 |
What is a Good Score in JEE Main 2027?
A score of 200+ in JEE Main is considered excellent. It results in a 99+ percentile based on the difficulty level of the shift. Also, a score above 180 is good and opens up opportunities to get admission to top NITs. In addition, a JEE Main score ranging from 140 to 170 is considered acceptable and may provide access to a reputable NIT branch, depending on category. However, the approach of good score varies every year, depending on the difficulty level and competition.
Also Check:
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Commonly asked questions
As per the JEE Main cutoff data released by the NTA, PwD category has the lowest cutoff.
The cutoff for NITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC, ST candidates. Candidates can check the previous year JEE Main cutoff below for some top NITs and branches. For detailed cutoff report, candidates can check Shiksha page.
- MNNIT Allahabad CSE Closing Rank Open Category: 5627 (Home State)
- MNNIT Allahabad CSE Closing Rank Open Category: 4254 (Open)
- MNIT Jaipur CSE Closing Rank Open Category: 5610 (Home State)
- MNIT Jaipur CSE Closing Rank Open Category: 4631 (Open)
The JEE Main cutoff for GFTIs is released by the JoSAA after the counselling is over. Candidates can check previous year JEE Main cutoff for GFTIs from the Shiksha page. The cutoff for GFTIs vary for various branches and also category of students.
Yes, candidates are required to submit proof of domicile in case availing the home-state quota in NITs. It is only NIT where admission is offered against the Home State quota.
Candidates home state is determined based on the state from which you appear for your 12th board exam and on the basis of the state to which you belong.
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Student Forum
Anything you would want to ask experts?Answered Yesterday
If your JEE Main score is not strong, Galgotias University can be a practical option to consider. It offers multiple B.Tech programmes and gives preference to JEE Main scores while also allowing admission based on its programme-specific eligibility criteria. Compare fees, branch, curriculum, and opp
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Beginner-Level 2
Answered Yesterday
For the General All-India category at DIT University Dehradun, the JEE Main Round 1 closing ranks generally range from 1,20,000 to 2,50,000.
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Beginner-Level 2
Answered 4 days ago
JECRC University Scholarship based on JEE Main scores is offered to BTech students. Check below eligibility and amount offered to BTech students at JECRC University:
Scholarship Criteria | Eligible Degree Programmes | Amount as percentage of Tuition Fee |
|---|---|---|
JEE (Main) 2026 Percentile Score 85 to 89.99 (General Category) | All BTech Programmes | 15% |
JEE (Main) 2026 Percentile Score more than 90 (General Category) | All BTech Programmes | 25% |
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Contributor-Level 10
Answered 2 weeks ago
Top Aerospace and Aeronautical Engineering colleges in India that do not require JEE Main rely instead on private entrance exams, state-level tests, or direct merit admissions. Check the table below for the Aerospace engineering colleges in India without JEE.
| Top Colleges | Tuition Fee |
|---|---|
| Amity University, Noida | INR 11.4 lakh |
| Presidency University, Bangalore | INR 9 lakh |
| SNS College of Technology | INR 2 lakh |
| Parul University | INR 7.8 Lacs - INR 10.8 lakh |
| Amity University, Mumbai | INR 4.24 lakh |
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Contributor-Level 10
Answered 4 weeks ago
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The cutoff rank in Round 7 for BTech Computer Science & Engineering under General All India category is 53,013. It is the most competitive branch in the institute.
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Yes, JEE Main is compulsory for admission in B.Tech course at SGSITS.
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After qualifying JEE Main, students need to register themselves for MP BE Counselling, choose colleges/branches, attend rounds and verify documents to secure admission.
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Getting into B.Tech CSE is straightforward. You need to have passed 10+2 with Physics and Mathematics, along with Chemistry, Biotechnology, Biology, or a Technical Vocational subject. Marks from boards like CBSE, ISC, and PSEB are accepted. JEE Main scores are also recognised under the RBUEdge Schol
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Contributor-Level 6
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Yes, JEE Main scores are recognised under the RBUEdge Scholarship Program, so your entrance exam effort can also help reduce your fees. A higher score falls in a higher scholarship slab, with the top slab offering a 60% waiver on the course fee. This is a nice reward for the hard work that goes into
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Contributor-Level 6
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