160 marks in JEE Main Percentile will help students estimate how much percentile range they can expect with 160 marks in JEE Mains. NTA considers scores obtained in JEE Main 2027 exam while preparing the percentile range. A normalisation formula is used to calculate JEE Main percentile marks. Based on JEE Main 2027 percentile, admissions will be done. Read to know more details about 160 Marks in JEE Main Percentile 2027.
160 Marks in JEE Main Percentile 2027: Students will be able to check their percentile scores through the JEE Mains 2027 result. The official result will not consist of raw scores obtained in exam, so students should know how to convert their scores into JEE Main percentile marks. To make it easy for students to understand how much marks is needed for preferred percentile range, students can check expected JEE Mains marks vs percentile. A normalisation formula is used to calculate the JEE Main percentile from raw scores. During the calculation, various factors such as shift-wise difficulty, total number of students, etc., will be used.
To understand the expected range of marks vs percentile, students can refer to previous years’ trends of JEE Mains exam. They are advised to score good marks in NTA JEE Main result, so that they have higher chances of getting admissions into their preferred courses and colleges. Read to know more about 160 Marks in JEE Main 2027 Percentile.
Also Read: Marks vs Percentile JEE Mains 2026
- What is the JEE Main 2027 Percentile for 160 Marks?
- How is JEE Main 2027 percentile calculated?
- Expected JEE Main 2027 Marks vs Percentile vs Rank
- What is JEE Main 2027 Rank Predictor?
- JEE Main 2027 Counselling
What is the JEE Main 2027 Percentile for 160 Marks?
As per previous year’s marks vs percentile data, students can check details of the expected JEE Main percentile for 160 marks in the table given below.
| JEE Main Score |
Expected JEE Main Percentile Range |
|---|---|
| 171 to 180 |
99.29558 to 99.45693 |
| 161 to 170 |
99.06985 to 99.27208 |
| 151 to 160 |
98.77819 to 99.02861 |
Students can estimate that 160 marks is likely to fall under the range of 98.77 to 99.45 JEE Main percentile range. However, this estimation may not be accurate and may have some discrepancies. While calculating the JEE Main 2027 percentile marks, different factors such as shift wise difficulty level, obtained scores, total number of students and more will be considered. Students should check previous years’ cutoff carefully while determining how much marks they need to score for their preferred percentile.
Also Check:
How is JEE Main 2027 percentile calculated?
A pre-determined formula is used by NTA to calculate JEE Main percentile scores. To make the calculation, students will have to use their obtained scores in the exam. Scores can be calculated by following official marking scheme. Four marks are given for every correct answer. One mark is deducted for every incorrect response.
Must Read: JEE Main 2027 Percentile Calculator
Formula used to convert raw scores into NTA scores is given below.
Expected JEE Main 2027 Marks vs Percentile vs Rank
Students can check expected JEE Main 2027 marks vs percentile vs rank from the table given below.
| JEE Main marks | Expected percentile | Expected ranks |
|---|---|---|
| 240 - 280+ | 99.9+ | 1 - 1,200 |
| 210 - 240 | 99.5 - 99.9 | 1,200 - 6,000 |
| 180 - 210 | 99.0 - 99.5 | 6,000 - 12,000 |
| 160 - 180 | 98.0 - 99.0 | 12,000 - 25,000 |
| 140 - 160 | 97.0 - 98.0 | 25,000 - 35,000 |
| 120 - 140 | 95.0 - 97.0 | 35,000 - 60,000 |
| 100 - 120 | 90.0 - 95.0 | 60,000 Lakh - 1.1 Lakh |
| 70 - 100 | 80.0 - 90.0 | 1.1 Lakh - 2.5 Lakh |
Commonly asked questions
Yes, candidates are required to submit proof of domicile in case availing the home-state quota in NITs. It is only NIT where admission is offered against the Home State quota.
Candidates home state is determined based on the state from which you appear for your 12th board exam and on the basis of the state to which you belong.
No. There is no qualifying percentile in JEE Main. However, the candidates who want to appear in JEE Advanced will have to get a minimum qualifying percentile in JEE Mains. This minimum qualifying percentile is announced with the JEE Main session 2 reult.
The JEE Main cutoff for GFTIs is released by the JoSAA after the counselling is over. Candidates can check previous year JEE Main cutoff for GFTIs from the Shiksha page. The cutoff for GFTIs vary for various branches and also category of students.
Candidates who do not score above JEE Main cutoff marks are eligible to take admissions in NITs, IIITs and GFTIs but not IITs. To appear in the admission process for IITs, candidates need to get marks above than the JEE Main cutoff and appear in JEE Advanced exam.
What is JEE Main 2027 Rank Predictor?
Using JEE Main rank predictor 2027 by Shiksha, students will be able to determine ranks before result is declared. To make calculation, they will have to submit percentile marks or scores obtained in exam. It is beneficial for students to know ranks beforehand to help them prepare for counselling and the admission process. Further, they can submit their ranks in JEE Main 2027 college predictor to know list of colleges they are likely to be eligible for.
JEE Main 2027 Counselling
Joint Seat Allocation Authority will conduct JEE Main counselling through JoSAA. Qualified candidates can check JoSAA counselling 2027 dates to know when to participate in the admission process. Through JoSAA counselling, candidates will be eligible for admissions into NITs. GFTIs, and IIITs. For IITs, JEE Advanced scores are required. During JoSAA, registration and selection of courses has to be done according to preference. Allotment of seats will be done based on merit, preferences and seat availability. JoSAA 2027 seat allotment will be released online. Once allotted, they will have to confirm their admission before final date. If allotment is not confirmed, admission will be cancelled.
Commonly asked questions
NTA does not release marks vs rank data officially. The data available on the internet is provided by various experts and is subject to changes due to various variables.
As per the JEE Main cutoff data released by the NTA, PwD category has the lowest cutoff.
The cutoff for NITs vary for various branches and also category of students. Specialised branches like computer Science and electronics engineering has higher cutoff in comparison to other branches. Similarly, JEE Main cutoff for general category candidates is higher in comparison to OBC-NCL and SC, ST candidates. Candidates can check the previous year JEE Main cutoff below for some top NITs and branches. For detailed cutoff report, candidates can check Shiksha page.
- MNNIT Allahabad CSE Closing Rank Open Category: 5627 (Home State)
- MNNIT Allahabad CSE Closing Rank Open Category: 4254 (Open)
- MNIT Jaipur CSE Closing Rank Open Category: 5610 (Home State)
- MNIT Jaipur CSE Closing Rank Open Category: 4631 (Open)
| Year | General (UR) Percentile |
|---|---|
| 2026 | 93.4123549 |
| 2025 | 93.1023262 |
| 2024 | 93.2362181 |
| 2023 | 90.7788642 |
| 2022 | 88.4121383 |
| 2021 | 87.8992241 |
| 2020 | 90.3765335 |
| 2019 | 89.7548849 |
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Student Forum
Answered 4 days ago
If your JEE Main score is not strong, Galgotias University can be a practical option to consider. It offers multiple B.Tech programmes and gives preference to JEE Main scores while also allowing admission based on its programme-specific eligibility criteria. Compare fees, branch, curriculum, and opp
D
Contributor-Level 7
Answered Yesterday
Top Aerospace and Aeronautical Engineering colleges in India that do not require JEE Main rely instead on private entrance exams, state-level tests, or direct merit admissions. Check the table below for the Aerospace engineering colleges in India without JEE.
| Top Colleges | Tuition Fee |
|---|---|
| Amity University, Noida | INR 11.4 lakh |
| Presidency University, Bangalore | INR 9 lakh |
| SNS College of Technology | INR 2 lakh |
| Parul University | INR 7.8 Lacs - INR 10.8 lakh |
| Amity University, Mumbai | INR 4.24 lakh |
T
Contributor-Level 10
Answered 2 weeks ago
According to the tentative schedule, JEE Main 2027 counselling registration is likely to commence in June 2027 after the conclusion of both exam sessions.
H
Beginner-Level 5
Answered 2 weeks ago
The cutoff rank in Round 7 for BTech Computer Science & Engineering under General All India category is 53,013. It is the most competitive branch in the institute.
H
Beginner-Level 5
Answered 2 weeks ago
Yes, JEE Main is compulsory for admission in B.Tech course at SGSITS.
H
Beginner-Level 5
Answered 2 weeks ago
After qualifying JEE Main, students need to register themselves for MP BE Counselling, choose colleges/branches, attend rounds and verify documents to secure admission.
H
Beginner-Level 5
Answered 2 weeks ago
Getting into B.Tech CSE is straightforward. You need to have passed 10+2 with Physics and Mathematics, along with Chemistry, Biotechnology, Biology, or a Technical Vocational subject. Marks from boards like CBSE, ISC, and PSEB are accepted. JEE Main scores are also recognised under the RBUEdge Schol
P
Contributor-Level 6
Answered 2 weeks ago
Yes, JEE Main scores are recognised under the RBUEdge Scholarship Program, so your entrance exam effort can also help reduce your fees. A higher score falls in a higher scholarship slab, with the top slab offering a 60% waiver on the course fee. This is a nice reward for the hard work that goes into
A
Contributor-Level 6
Answered 2 weeks ago
The JEE Main Round 7 cutoff 2026 for SGSITS Indore ranged from 53,013 to 90,468 for General All India candidates across BTech branches.
H
Beginner-Level 5
Answered 2 weeks ago
If a student has appeared for JEE Main, they can apply for B.Tech admission at Galgotias University through the university's admission process. JEE Main scores are considered for preference in the merit list, along with the eligibility requirements of the chosen B.Tech programme. After applying, the
S
Contributor-Level 8

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