Check how NTA resolves ties when two or more candidates get the same percentile. Read all details below,
JEE 2026 Tie Rule Explanation: The National Testing Agency (NTA) has mentioned the tie-breaking rule for JEE Mains paper 1 (BE/Tech), paper 2a (BArch) and paper 2b (BPlan). In case two or more candidates get the same percentile score, then NTA will follow a set rule to break the ties. The tie-breaking rule is explained in detail in the article below. Note that, previously the JEE Mains tie-breaking rule used to include the "age criteria" too. However, the "age criteria" for breaking ties has been dropped in 2024.
- JEE Mains 2026 Tie Breaking Rule for Paper 1 (BE/BTech)
- JEE Mains 2026 Tie Breaking Rule for Paper 2a (BArch)
- JEE Mains 2026 Tie Breaking Rule for Paper 2b (BPlan)
- How to Check JEE Mains 2026 Ranks?
JEE Mains 2026 Tie Breaking Rule for Paper 1 (BE/BTech)
Check below the tie-breaking rule for JEE Mains 2026 paper 1:
- Candidates with a better NTA score in Mathematics will be given a higher rank.
- If that fails, then NTA score in Physics will be given priority
- If that fails, then NTA score in Chemistry will be given priority
If all the above criteria fail, then
- A candidate with a lower proportion of incorrect answers and correct answers in all the subjects in the test will be considered for a better rank
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Mathematics in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Physics in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Chemistry in the test
If there is a tie even after this, candidates will be assigned the same rank.
JEE Mains 2026 Tie Breaking Rule for Paper 2a (BArch)
Check below the tie-breaking rule for JEE Mains 2026 paper 2a:
- Candidates with a better NTA score in Mathematics will be given a higher rank.
- If that fails, then NTA score in Aptitude will be given priority
- If that fails, then NTA score in Drawing will be given priority
If all the above criteria fail, then
- Candidate with less proportion of number of attempted incorrect answers and correct answers in all the subjects in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Mathematics in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Aptitude in the test
If there is a tie even after this, candidates will be assigned the same rank.
JEE Mains 2026 Tie Breaking Rule for Paper 2b (BPlan)
Check below the tie-breaking rule for JEE Mains 2026 paper 2b:
- Candidates with a better NTA score in Mathematics will be given a higher rank.
- If that fails, then NTA score in Aptitude will be given priority
- If that fails, then NTA score in Planning will be given priority
If all the above criteria fail, then
- Candidate with less proportion of number of attempted incorrect answers and correct answers in all the subjects in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Mathematics in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Aptitude in the test
- Followed by a candidate with less proportion of number of attempted incorrect answers and correct answers in Planning in the test
If there is a tie even after this, candidates will be assigned the same rank.
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How to Check JEE Mains 2026 Ranks?
Candidates can check their JEE Main ranks with their JEE Main session 2 scorecard. To check their ranks, candidates have to download the scorecard from their respective logins.
The JEE Mains 2026 session 2 scorecard will have the category rank as well as the overall All India Ranks of the students.
- AIR (All India Rank): Determines your position nationwide, crucial for seat allocation in the general category.
- Category Rank: Specific to a category (SC/ST/OBC/EWS/PwD). It helps candidates secure seats in top institutions, sometimes even with a lower AIR.

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Student Forum
Answered 2 days ago
If candidates have identical Common Rank List (CRL) in JEE (Main) - 2026 Paper-I even after applying NTA's tie-breaking measures, the following order of additional tie-breaking criteria shall be adopted for seat allocation in JAC Delhi:
1. Date of Birth (preference to the elder candidate).
2. Random d
R
Contributor-Level 10
Answered 5 days ago
Candidates wishing to take admission in BTech at Ramaiah Institute of Science and Management have to appear in JEE Main, JEE Advanced, CUET-UG, SAT, KCET, COMEDK. So, yes even if you have not appeared in JEE, you can produce score card of any of the above mentioned exams.
R
Contributor-Level 10
Answered a week ago
The East Point Group of Institutions accepts many exams for the BE course. The accepted exams are JEE Main, COMEDK, and KCET. Students can appear in any of these exams to get admission at EPGI. Students need to fulfil the eligibility criteria as well.
A
Contributor-Level 10
Answered a week ago
With 57.8 percentile in JEE Main and 73% boards, getting CSE/AI in top government colleges is unlikely. But you still have good chances in private colleges through UPTAC/AKTU or direct admission.
Possible options:
KIET Group of Institutions
ABES Engineering College
Galgotias College of Engineering a
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Beginner-Level 1
Answered a week ago
Amrut Institute offer admission in BTech and Diploma in Engineering based on merit in last qualifying exam. So, no JEE Main is not compulsory to take admission in Amrut Institute courses.
R
Contributor-Level 10
Answered a week ago
With a JEE Main rank of 291970, you can get into NIT Calicut if you belong to the SC Home State quota category.
For this category, the highest rank admissible was 543879 (as per the last round of NIT Calicut cutoff 2025). See the table below to know which courses you can opt for.
| Course | NIT Calicut JEE Main cutoff 2025 |
|---|---|
| B.Tech. in Chemical Engineering | 343880 |
| B.Tech. in Biotechnology | 386381 |
| B.Tech. in Civil Engineering | 405588 |
| B.Tech. in Production Engineering | 449781 |
| B.Tech. in Energy Engineering | 543879 |
To know the accepte
N
Contributor-Level 10
Answered a week ago
JEE (Main) cutoff for BTech in Computer Science and Engineering in Sagar Institute of Science Technology and Research, Bhopal in the closing round has ranged between 3,75,232 to 10,07,060 from 2021 to 2023.
S
Contributor-Level 10
Answered a week ago
Yes, students can get EIT Faridabad scholarship with 97.6 percentile in JEE Main. Applicants can get scholarship on the basis of scores in entrance exam. Check the table below to know eligiblity of scholarships offered on the basis of JEE Main scores:
| Eligibility Criteria | Scholarship (on tuition fee) |
|---|---|
| 95.01 percentile and above | 50% |
| 90.01 - 95 prcentile | 35% |
| 85.01 - 90 percentile | 25% |
| 80.01 - 85 percentile | 20% |
G
Contributor-Level 10
Answered a week ago
Yes, you can get admission in BTech in Sagar Institute of Science Technology and Research without JEE (Mains) rank through College Level Counselling based on merit if there are any seats left vacant after DTE Bhopal Counselling.
S
Contributor-Level 10
Answered 2 weeks ago
Guru Tegh Bahadur 4th Centenary Engineering College BTech admission is based on merit and entrance. Students are selected based on academic scores and JEE Main scores. However, JEE Main scores are not enough for admission. The final seat allotement for BTech is conducted through the centralised coun
G
Contributor-Level 10

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