Updated on Apr 3, 2024 23:23 IST
JEE Main Cut off 2024 is the minimum mark required by the candidate in the exam to be eligible for admission in an institute. Check all the details related to the expected JEE Main 2024 qualifying marks for admission to NITs. Admission to NITs will be based on the All India Rank (AIR) in JEE Mains.

JEE Main cut-off 2024 for NITs will be released by JoSAA after the announcement of JEE Main 2021 results. Read the article below for all the BTech admissions-related updates offered by the National Institute of Technology (NIT).

JEE Main cut off for NITs depends on the marks obtained by the candidate in the JEE Main entrance exam and All India Ranks (AIR). The cutoff list varies as per the category and courses offered under the NITs and the seat allotment will be purely based on JEE Main cut off.

Admission to BTech courses in the National Institute of Technology (NIT) is completely based on qualifying JEE Main entrance exam. According to the NTA eligibility criteria, a candidate needs to score a minimum 75 percent aggregate score in the class 12 board examination or he/she must be among the top 20 percentile in 10+2 or any equivalent examination for admissions at the NITs and also for the other institutes of national importance such as IITs/IIITs and CFTIs.

For SC/ST candidates minimum of 65 percent required in +2 class by a recognised board or equivalent examination as per the relaxation norms for reserved category. Aspirants who will qualify the JEE Main or JEE Advanced have to register for JoSAA 2021 for further admission process for various renowned engineering institutes across India. The Joint Seat Allocation Authority (JoSAA) is responsible for admissions in 23 IITs, 31 NITs, 25 IIITs, and 28 Other- Government Funded Technical Institutes (Other-GFTIs). To know more read the article below.

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Table of contents
  • NIT 2024 Cut Offs for BTech Admission
  • Expected JEE Main 2024 Qualifying Marks for NITs
  • List top NITs in India

NIT 2024 Cut Offs for BTech Admission

  • Candidates need to qualify specific entrance exams to get admission to various UG Engineering courses under NITs.
  • For UG or BTech courses, candidates are admitted through JEE Main exam.
  • JoSAA will release the category-wise and round-wise opening and closing cut off/ranks for admission to BTech, Mech and dual degree courses in NITs. 
  • Candidates who qualify the JEE Main exam will have to register and participate in the JoSAA counselling cum seat allotment process. 
  • JoSAA (Joint Seat Allocation Authority) conducts a joint counselling session for candidates qualifying JEE Main and JEE Advanced exam.
  • JEE Main Cut off depends on several factors such as:
    • Total number of candidates appearing in the JEE Main entrance exam.
    • Total candidates applied for the admission in UG or PG degree courses in NITs.
    • Total seat intake and difficulty level of the examination.
Q&A Icon
Commonly asked questions
Q:   Is 75 percent marks in class 12 required for JEE Mains?
A: 

Candidates need not have 75 percent marks in class 12 for appearing in JEE Main. As per the official brochure released by the NTA, there is no minimum percentage required for appearing in the JEE Main. The requirement of 75 percent marks need not be associated with appearing in the JEE Main exam.

It is to be understood that 75 percent marks is required for admission to institutes which include NITs, IIITs, GFTIs and IITs. Many institutes offer admission at 60% and even less, along with JEE Main. Candidates must clearly understand that the requirement of 75 percent marks in class 12 is only for taking admission in the institutes.

Q:   What is the cutoff for BTech in Computer Science and Engineering at NIT Hamirpur for other than General categories?
A: 

The last year 2022 cutoff ranks for BTech in Computer Science and Engineering at NIT Hamirpur - National Institute of Technology other than General category are - 17445 for OBC, 1663 for SC, 578 for ST, 16770 for EWS, 187395 for PWD. While the admissions are based on the scores/rank obtained in JEE exam, the last cut offs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.

Q:   What is NIT Rourkela cutoff for BTech?
A: 

NIT Rourkela cutoff 2024 has been released across various specialisations in opening and closing ranks. NIT Rourkela BTech cutoff 2024 ranged between 2680 and 35593 for the General AI category candidates, wherein BTech in CSE is the most competitive course. The easiest BTech specialisation to secure admission in is B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering. For a detailed NIT Rourkela branch-wise cutoff 2024, candidates can refer to the table below for the Round 1 cutoff. The cutoff mentioned below is for the General category under the AI Quota.

Course2024
B.Tech. in Biomedical Engineering28053
B.Tech. in Ceramic Engineering34492
B.Tech. in Chemical Engineering16708
B.Tech. in Civil Engineering23425
B.Tech. in Computer Science and Engineering2680
B.Tech. in Electrical Engineering8770
B.Tech. in Electronics and Communication Engineering5053
B.Tech. in Mechanical Engineering13682
B.Tech. in Metallurgical and Materials Engineering27499
B.Tech. in Mining Engineering31497
B.Tech. in Biotechnology27533
B.Tech. in Electronics and Instrumentation Engineering8646
B.Tech. in Industrial Design27601
B.Tech. + M.Tech. in Chemical Engineering18843
B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering35593
B.Tech. + M.Tech. in Metallurgical and Materials Engineering33676
B.Tech. + M.Tech. in Mining Engineering32461
Bachelor of Architecture (B.Arch.)439
B.Tech. in Food Process Engineering34726
B.Tech. in Artificial Intelligence3880
Q:   What is the cutoff for BTech at NIT Andhra Pradesh for OBC category?
A: 

NIT Andhra Pradesh BTech admission is based on candidates' performance in the JEE Main entrance exam, followed by the JoSAA counselling process. For the OBC category students under the AI quota, the JEE Main closing ranks ranged between 5741 and 100661. Candidates can refer to the table below to view the NIT Andhra Pradesh OBC category cutoff 2025 for the first and the last round in the AI quota. 

Course

Round 1 Cutoff 2025

Last Round Cutoff 2025

B.Tech. in Biotechnology

14191

100661

B.Tech. in Chemical Engineering

13555

69612

B.Tech. in Civil Engineering

14452

81169

B.Tech. in Computer Science and Engineering

5741

29695

B.Tech. in Electrical and Electronics Engineering

10155

51887

B.Tech. in Electronics and Communication Engineering

7400

40587

B.Tech. in Mechanical Engineering

12259

63517

B.Tech. in Metallurgical and Materials Engineering

14368

87677

Expected JEE Main 2024 Qualifying Marks for NITs

Below is the list of expected JEE Main Qualifying Marks for admission to NITs based on the previous year trends:

Category

Minimum Percentile 

General

78-80

OBC – NCL

73- 76

SC

54- 57

ST

43- 46

PwD

0- 2

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Answered 7 hours ago

The East Point Group of Institutions accepts many exams for the BE course. The accepted exams are JEE Main, COMEDK, and KCET. Students can appear in any of these exams to get admission at EPGI. Students need to fulfil the eligibility criteria as well.

A

Anjali Sharma

Contributor-Level 10

Answered 2 days ago

With 57.8 percentile in JEE Main and 73% boards, getting CSE/AI in top government colleges is unlikely. But you still have good chances in private colleges through UPTAC/AKTU or direct admission.

 

Possible options:

 

KIET Group of Institutions

 

ABES Engineering College

 

Galgotias College of Engineering a

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H

Harshitha

Beginner-Level 1

Answered 2 days ago

Amrut Institute offer admission in BTech and Diploma in Engineering based on merit in last qualifying exam. So, no JEE Main is not compulsory to take admission in Amrut Institute courses. 

R

Raj Priya

Contributor-Level 10

Answered 5 days ago

With a JEE Main rank of 291970, you can get into NIT Calicut if you belong to the SC Home State quota category. 

For this category, the highest rank admissible was 543879 (as per the last round of NIT Calicut cutoff 2025). See the table below to know which courses you can opt for. 

CourseNIT Calicut JEE Main cutoff 2025
B.Tech. in Chemical Engineering343880
B.Tech. in Biotechnology386381
B.Tech. in Civil Engineering405588
B.Tech. in Production Engineering449781
B.Tech. in Energy Engineering543879

To know the accepte

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N

Neerja Rohatgi

Contributor-Level 10

Answered 6 days ago

JEE (Main) cutoff for BTech in Computer Science and Engineering in Sagar Institute of Science Technology and Research, Bhopal in the closing round has ranged between 3,75,232 to 10,07,060 from 2021 to 2023.

S

Saumya Gairola

Contributor-Level 10

Answered 6 days ago

Yes, students can get EIT Faridabad scholarship with 97.6 percentile in JEE Main. Applicants can get scholarship on the basis of scores in entrance exam. Check the table below to know eligiblity of scholarships offered on the basis of JEE Main scores:

Eligibility CriteriaScholarship (on tuition fee)
95.01 percentile and above50%
90.01 - 95 prcentile35%
85.01 - 90 percentile25%
80.01 - 85 percentile20%

G

Gaurika Chhabra

Contributor-Level 10

Answered 6 days ago

Yes, you can get admission in BTech in Sagar Institute of Science Technology and Research without JEE (Mains) rank through College Level Counselling based on merit if there are any seats left vacant after DTE Bhopal Counselling.

S

Saumya Gairola

Contributor-Level 10

Answered 6 days ago

Guru Tegh Bahadur 4th Centenary Engineering College BTech admission is based on merit and entrance. Students are selected based on academic scores and JEE Main scores. However, JEE Main scores are not enough for admission. The final seat allotement for BTech is conducted through the centralised coun

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Gaurika Chhabra

Contributor-Level 10

Answered a week ago

Yes. The syllabus overlaps heavily, and JEE preparation often covers TS EAMCET topics. Just add state-specific mock tests for better speed and familiarity.

M

Manori Patra

Contributor-Level 8

Answered a week ago

Any candidate who cleared Class 12th with an aggregate of less than 50% must appear for JEE Mains to qualify for Sagar Institute of Science Technology and Engineering (SISTec-E) - Sagar Group of Institutions Bhopal BTech admission. Howver, candidates who cleared Class 12th with a minimum aggregate o

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Saurabh Khanduri

Contributor-Level 10